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angle CXM = angle AXB (directly opp angle)

angle CMX = angle ABX (alternate angle)
angle MCX = angle BAX (alternate angle)

Therefore triangle CMX and triangle AXB is similar based on AAA property

Thanks so much for your response. We got that. Any thoughts on part (b) (ii) of this problem? Greatly appreciate your help on this!

Please let me know if you can please help me solve this problem. Thank you! http://i57.tinypic.com/24gvk1f.jpg\">