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    Tutor MathsGuru: Ask me for your burning Maths questions!

    Scheduled Pinned Locked Moved Primary Schools - Academic Support
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    • Y Offline
      YLH88
      last edited by

      Hi all,


      Need help with the below questions :? :

      1)At 11am, a van set off from Town P for Town Q while a car set off from Town Q for Town P.
      At 4pm, the van and the car passed each other.
      4 hours after they met, the car reached Town P but the van was still 180km away from Town Q.
      Find the distance between Town P and Town Q.


      2) Greg counted the number of cars, vans and motorcycles parked at the multi-storey carpark.
      There were 5/9 as many vans as cars.
      1/4 of the number of motorcycles was 36 less than 1/5 of the number of vans.
      After some cars left the carpark, there was an equal number of cars and vans.
      Given that there was a total of 480 cars and motorcycles at the carpark at first, how many cars left the carparks ?


      3) The capacity of a mug is 1375 ml less than the capacity of a jar.
      The capacity of a cup is 1/5 that of a mug.
      4/9 of the amount of orange cordial in a dispenser was used to fill 3 cups and 5 mugs completely.
      3/5 of the remaining amount of orange cordial was used to fill 2 jars completely.
      Find the difference between the capacity of a jar and a cup.

      Thank you!

      1 Reply Last reply Reply Quote 0
      • B Offline
        benorito
        last edited by

        Dharma:
        firebird:

        Dear maths guru


        Please help me on the following maths:



        2) At 9am John was cycling from Point A to Point B. At the same time, Mary was cycling from point B to point A using the same route as John. Cycliing at a speed of 4km/h faster than Mary, they would pass each other 300 meter away from the mid point.

        a) What time did they pass each other?


        a) Difference in distance travelled by John and Mary = 4km/h x T
        T = 0.3km x 2/(4km/hr) = 3/20 hrs = 9 mins
        Time they passed each other => 9.09am

        Dharma,

        Can you tell me why you must multiply the 0.3 km by 2 ?

        Thanks

        1 Reply Last reply Reply Quote 0
        • V Offline
          Vanilla Cake
          last edited by

          YLH88:
          1)At 11am, a van set off from Town P for Town Q while a car set off from Town Q for Town P.At 4pm, the van and the car passed each other.4 hours after they met, the car reached Town P but the van was still 180km away from Town Q.Find the distance between Town P and Town Q.

          11 am (set off) to 4 pm (passed each other) -> 5 h
          So, the van and car took 5h for the whole journey.
          1h -> 1/5 of the journey together

          Car
          5h + 4h = 9h to complete the journey
          1 h -> 1/9 of the journey

          Van
          1 h -> Together minus car
          -> 1/5-1/9 = 9/45-5/45 = 4/45

          1 h -> 4/45 of the distance
          9 h -> 4/45x9 = 4/5 of the distance
          Remaining distance = 1/5 of the distance ie 1 unit left
          Since van was still 180km away from Town Q -> 1 unit -> 180 km
          5 units -> 5x180 km = 900 km

          Distance between Town P and Town Q = 900 km

          Note:
          I think that there are shorter methods of solving this speed question, hope to learn from others.

          1 Reply Last reply Reply Quote 0
          • V Offline
            Vanilla Cake
            last edited by

            YLH88:
            2) Greg counted the number of cars, vans and motorcycles parked at the multi-storey carpark.There were 5/9 as many vans as cars.1/4 of the number of motorcycles was 36 less than 1/5 of the number of vans.After some cars left the carpark, there was an equal number of cars and vans.Given that there was a total of 480 cars and motorcycles at the carpark at first, how many cars left the carparks ?

            If I am not mistaken, this question had been posted before and already solved in KSP forum (maybe Uncle Dharma?). Cannot find the link and here's my suggested solution:

            πŸ˜„ Cars
            V: Vans
            M: Motorcycles

            Before
            V : C
            5u : 9u

            1/4 of the number of motorcycles was 36 less than 1/5 of the number of vans-> 1/4 of M +36= 1/5 of 5u
            M/4+36=u
            M+144=4u
            M= 4u-144

            There was a total of 480 cars and motorcycles at the carpark at first,
            9u+4u-144=480
            13u=624
            u=48

            After some cars left the carpark, there was an equal number of cars and vans.
            After
            V : C
            1p : 1p
            5u : 5u

            Number of cars left -> 9u-5u=4u
            4u= 4x48=192
            Number of cars left the carpark = 192
            YLH88:
            3) The capacity of a mug is 1375 ml less than the capacity of a jar.The capacity of a cup is 1/5 that of a mug.4/9 of the amount of orange cordial in a dispenser was used to fill 3 cups and 5 mugs completely.3/5 of the remaining amount of orange cordial was used to fill 2 jars completely.Find the difference between the capacity of a jar and a cup.
            Mug: u-1375
            Jar: u
            Cup: 1/5x(u-1375)=0.2u-275

            3C+5M -> 4/9 of total
            2J -> 3/9 of total
            2Jx9/3x4/9 -> 4/9 of total
            8J/3 -> 4/9 of total

            3C+5M -> 8J/3
            9C+15M -> 8J

            9(0.2u-275)+15(u-1375)=8u
            1.8u-2475+15u-20625=8u
            8.8u=23100
            u=2625

            Difference in capacity between a jar and a cup-> u-(0.2u-275)=u-0.2u+275=0.8u+275
            0.8u+275 = 0.8(2625)+275=2100+275=2375 ml

            Pls check the above calculations as I am in a sleepy mood.
            Good night.
            :snooze:

            1 Reply Last reply Reply Quote 0
            • D Offline
              Dharma
              last edited by

              benorito:
              Dharma:

              [quote=\"firebird\"]Dear maths guru


              Please help me on the following maths:



              2) At 9am John was cycling from Point A to Point B. At the same time, Mary was cycling from point B to point A using the same route as John. Cycliing at a speed of 4km/h faster than Mary, they would pass each other 300 meter away from the mid point.

              a) What time did they pass each other?


              a) Difference in distance travelled by John and Mary = 4km/h x T
              T = 0.3km x 2/(4km/hr) = 3/20 hrs = 9 mins
              Time they passed each other => 9.09am

              Dharma,

              Can you tell me why you must multiply the 0.3 km by 2 ?

              Thanks

              [/quote]It will be easier to imagine if Mary cycled in the same direction as John.

              If T hrs was taken if the met when they were cycling in opposite direction. So, when they cycled in the same direction starting at the same time, in T hours, the distance travelled by John will be distance cycled by Mary plus 300m (up to the midpoint) and plus another 300m (after the midpoint).

              # The distance cycled by John + distance cycle by Mary = Distance between Town A and Town B

              If you still don’t understand, please let me know.

              1 Reply Last reply Reply Quote 0
              • Y Offline
                YLH88
                last edited by

                Hi VC


                Thank you so much!!

                Have a nice weekend!

                1 Reply Last reply Reply Quote 0
                • D Offline
                  Dharma
                  last edited by

                  1)At 11am, a van set off from Town P for Town Q while a car set off from Town Q for Town P.

                  At 4pm, the van and the car passed each other.
                  4 hours after they met, the car reached Town P but the van was still 180km away from Town Q.
                  Find the distance between Town P and Town Q.

                  Speed is fixed (car)
                  Time ratio => Q to meeting pt : Meeting pt to P = 5 : 4
                  Distance ratio => Q to meeting pt : Meeting pt to P = 5 : 4

                  Time is fixed (car & van pass each other)
                  Distance ratio => Van : Car = 4 : 5
                  Speed ratio => Van : Car = 4 : 5

                  5u – 4u = 180km
                  1u = 180km
                  Distance between Town P and Q = 5u = 900km


                  2) Greg counted the number of cars, vans and motorcycles parked at the multi-storey carpark.
                  There were 5/9 as many vans as cars.
                  1/4 of the number of motorcycles was 36 less than 1/5 of the number of vans.
                  After some cars left the carpark, there was an equal number of cars and vans.
                  Given that there was a total of 480 cars and motorcycles at the carpark at first, how many cars left the carparks ?

                  Vans : 5u
                  Cars : 9u
                  Motorcycles : 4(1u – 36) = 4u – 144

                  13u – 144 = 480
                  13u = 624
                  1u = 48
                  No. of cars that left the carpark = 4u = 4 x 48 = 192


                  3) The capacity of a mug is 1375 ml less than the capacity of a jar.
                  The capacity of a cup is 1/5 that of a mug.
                  4/9 of the amount of orange cordial in a dispenser was used to fill 3 cups and 5 mugs completely.
                  3/5 of the remaining amount of orange cordial was used to fill 2 jars completely.
                  Find the difference between the capacity of a jar and a cup.

                  Cup : 1u
                  Mug : 5u
                  Jar : 5u + 1375

                  4/9 of dispenser = 3u + 25u = 28u
                  3/5 x 5/9 = 1/3 of dispenser = 10u + 2750

                  30u + 8250 = 63u
                  33u = 8250
                  1u = 250
                  Difference = 4u + 1375 = 2375

                  1 Reply Last reply Reply Quote 0
                  • Y Offline
                    YLH88
                    last edited by

                    Hi Dharma,


                    Thank you so much for the solution! Have a great weekend!

                    Regards

                    1 Reply Last reply Reply Quote 0
                    • M Offline
                      Muffins
                      last edited by

                      Hi Publica!


                      I have done your first problem, but first, let me tell you something. \"u\" means unit, and \"p\" means part. So, here goes:

                      AT FIRST - A : B
                      7u : 5p

                      AFTER FIRST TRANSFER - A : B
                      6u : 5p + 1u

                      AFTER SECOND TRANSFER - A : B
                      6.2u + 1p : 4p + 0.8u

                      6.2 u = 3p + 0.8u

                      Therefore, 5.4u = 3p

                      Dividing both by 3, we get: 1.8u = 1p

                      Unit : Part
                      5 : 9

                      So, first ratio: 5 X 7 : 9 X 5
                      35 : 45

                      35 : 45
                      = 7 : 9

                      1 Reply Last reply Reply Quote 0
                      • H Offline
                        Herbie
                        last edited by

                        Hi

                        I have one qn
                        Zachery set off from the port at 6.30am and took 8 hr to reach the resort.
                        Robbie set off from the port 45 mins later than Zachery and took 5 hr to reach the resort. At what time did Robbie catch up with Zachery??

                        Many thanks!

                        1 Reply Last reply Reply Quote 0

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