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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • T Offline
      tianzhu
      last edited by

      pensiveowl:
      Could someone pls help with this one as well - thanks


      The ratio of the number of green marbles to the red marbles in a box is 6 : 5. After 60 green marbles and 60 red marbles were removed from the box. the ratio of the number of green marbles to red marbles became 9 : 7. How many red marbles were there in the box at first?
      Hi

      The number of green marbles and red marbles removed from the box are the same.

      Hence the difference between the number of green marbles and red marbles stay the same before and after.

      At first.
      Green: Red ------ 6:5 -------12:10
      Difference ----- 1 ------ 2

      In the end
      Green: Red ------ 9:7
      Difference ----- 2

      Make the difference the same.

      3 units ------ 60
      1 unit ------ 20

      At first, red marbles -------10*20 -------200

      Best wishes

      1 Reply Last reply Reply Quote 0
      • MathIzzzFunM Offline
        MathIzzzFun
        last edited by

        pensiveowl:
        Could someone pls help with this one as well - thanks


        The ratio of the number of green marbles to the red marbles in a box is 6 : 5. After 60 green marbles and 60 red marbles were removed from the box. the ratio of the number of green marbles to red marbles became 9 : 7. How many red marbles were there in the box at first?
        Hi

        the two questions are similar, but for q2, the concept of \"same gap\" can be applied to solve.

        q1. Mr Ho and Mrs Lee took part in a chess competition. Mr Ho played against 1/3 as many men as women. Mrs Lee played against 2/5 as many men as women. How many women took part in the chess competition?

        Mr Ho played 1/3 as many men as women --> men : women = 1u : 3u
        ..total number of men = 1u + 1

        Mrs Ho played 2/5 as many men as women
        --> men : women = 1u + 1 : 3u -1 = 2 : 5

        cross-multiply: 5u+5 = 6u -2, 1u = 7

        Number of men = 1u + 1 = 8
        Number of women = 3u = 21

        q2. The ratio of the number of green marbles to the red marbles in a box is 6 : 5. After 60 green marbles and 60 red marbles were removed from the box. the ratio of the number of green marbles to red marbles became 9 : 7. How many red marbles were there in the box at first?

        at first, green : red = 6u : 5u
        in the end, green : red = 6u - 60 : 5u - 60 = 9 : 7
        so, 42u - 420 = 45u - 540, 3u = 120, 1u = 40

        At first, red marbles = 5u = 200

        using \"same gap/difference\":

        in the end, green : red = 9u : 7u (gap 2u)
        at first, green : red = 6 : 5 = 12u : 10 u (gap 2u)
        so 3u = 60, 1u = 20

        Number of red marbles at first = 10u = 200

        cheers.

        1 Reply Last reply Reply Quote 0
        • P Offline
          pensiveowl
          last edited by

          tianzhu:
          pensiveowl:

          Could someone pls help with this one as well - thanks


          The ratio of the number of green marbles to the red marbles in a box is 6 : 5. After 60 green marbles and 60 red marbles were removed from the box. the ratio of the number of green marbles to red marbles became 9 : 7. How many red marbles were there in the box at first?

          Hi

          The number of green marbles and red marbles removed from the box are the same.

          Hence the difference between the number of green marbles and red marbles stay the same before and after.

          At first.
          Green: Red ------ 6:5 -------12:10
          Difference ----- 1 ------ 2

          In the end
          Green: Red ------ 9:7
          Difference ----- 2

          Make the difference the same.

          3 units ------ 60
          1 unit ------ 20

          At first, red marbles -------10*20 -------200

          Best wishes


          Thanks Tianzhu!

          1 Reply Last reply Reply Quote 0
          • T Offline
            TT2
            last edited by

            Hi, how to do this qn?


            Given that p:(q+r)=1:3, r:(q+s)=1:2 and p:s=2:5.
            (a) find p:q:r:s
            (b) find (r+q):(p+s)

            Thank you

            1 Reply Last reply Reply Quote 0
            • T Offline
              TT2
              last edited by

              Hi, need help on another speed qn…


              Ahmad started traveling from town P towards town Q at 7am. After traveling for some time, he passed Steve who was traveling at an average speed of 80 km/h on the opposite direction. After traveling for another 2 hrs, Ahmad reached town Q while Steve was still 40km away from town P.

              (a) if Ahmad reached town Q at 1pm, what was his average speed?
              (b) if Steve started his journey from town Q, at what time did he leave town Q?

              Thank you.

              1 Reply Last reply Reply Quote 0
              • T Offline
                tianzhu
                last edited by

                TT2:
                Hi, how to do this qn?


                Given that p:(q+r)=1:3, r:(q+s)=1:2 and p:s=2:5.
                (a) find p:q:r:s
                (b) find (r+q):(p+s)

                Thank you
                Hi

                Please refer to Vanilla Cake’s post @ page 432.

                http://www.kiasuparents.com/kiasu/forum/viewtopic.php?f=69&t=280&start=4310

                Best wishes

                1 Reply Last reply Reply Quote 0
                • T Offline
                  TT2
                  last edited by

                  tianzhu:
                  TT2:

                  Hi, how to do this qn?


                  Given that p:(q+r)=1:3, r:(q+s)=1:2 and p:s=2:5.
                  (a) find p:q:r:s
                  (b) find (r+q):(p+s)

                  Thank you

                  Hi

                  Please refer to Vanilla Cake’s post @ page 432.

                  http://www.kiasuparents.com/kiasu/forum/viewtopic.php?f=69&t=280&start=4310

                  Best wishes

                  Got it. Thank you, tianzhu

                  1 Reply Last reply Reply Quote 0
                  • MathIzzzFunM Offline
                    MathIzzzFun
                    last edited by

                    TT2:
                    Hi, need help on another speed qn...


                    Ahmad started traveling from town P towards town Q at 7am. After traveling for some time, he passed Steve who was traveling at an average speed of 80 km/h on the opposite direction. After traveling for another 2 hrs, Ahmad reached town Q while Steve was still 40km away from town P.

                    (a) if Ahmad reached town Q at 1pm, what was his average speed?
                    (b) if Steve started his journey from town Q, at what time did he leave town Q?

                    Thank you.
                    Hi

                    Draw a diagram to show the journey - name the meeting point X.
                    From X, after Steve travelled for 2h, he was 40 km from P.
                    So, distance PX = 40 km + 2 x 80 km/h = 200 km

                    Ahmad reached Town Q at 1pm, so total journey time = 6h, time taken to travel from Town P to meeting point X = 4h.

                    So, Ahmad's speed = 200km/4 h = 50 km/h

                    Steve met Ahmad at 7am + 4h = 11am
                    Time taken for Steve to travel from Town Q to meeting point X
                    = 50/80 x 2h = 1h 15min

                    He left Town Q at (11am - 1h 15min) = 9.45 am

                    cheers.

                    cheers.

                    1 Reply Last reply Reply Quote 0
                    • P Offline
                      pensiveowl
                      last edited by

                      MathIzzzFun:
                      pensiveowl:

                      Could someone pls help with this one as well - thanks


                      The ratio of the number of green marbles to the red marbles in a box is 6 : 5. After 60 green marbles and 60 red marbles were removed from the box. the ratio of the number of green marbles to red marbles became 9 : 7. How many red marbles were there in the box at first?

                      Hi

                      the two questions are similar, but for q2, the concept of \"same gap\" can be applied to solve.

                      q1. Mr Ho and Mrs Lee took part in a chess competition. Mr Ho played against 1/3 as many men as women. Mrs Lee played against 2/5 as many men as women. How many women took part in the chess competition?

                      Mr Ho played 1/3 as many men as women --> men : women = 1u : 3u
                      ..total number of men = 1u + 1

                      Mrs Ho played 2/5 as many men as women
                      --> men : women = 1u + 1 : 3u -1 = 2 : 5

                      cross-multiply: 5u+5 = 6u -2, 1u = 7

                      Number of men = 1u + 1 = 8
                      Number of women = 3u = 21

                      q2. The ratio of the number of green marbles to the red marbles in a box is 6 : 5. After 60 green marbles and 60 red marbles were removed from the box. the ratio of the number of green marbles to red marbles became 9 : 7. How many red marbles were there in the box at first?

                      at first, green : red = 6u : 5u
                      in the end, green : red = 6u - 60 : 5u - 60 = 9 : 7
                      so, 42u - 420 = 45u - 540, 3u = 120, 1u = 40

                      At first, red marbles = 5u = 200

                      using \"same gap/difference\":

                      in the end, green : red = 9u : 7u (gap 2u)
                      at first, green : red = 6 : 5 = 12u : 10 u (gap 2u)
                      so 3u = 60, 1u = 20

                      Number of red marbles at first = 10u = 200

                      cheers.

                      Thanks MathIzzzFun!

                      1 Reply Last reply Reply Quote 0
                      • T Offline
                        TT2
                        last edited by

                        MathIzzzFun:
                        TT2:

                        Hi, need help on another speed qn...


                        Ahmad started traveling from town P towards town Q at 7am. After traveling for some time, he passed Steve who was traveling at an average speed of 80 km/h on the opposite direction. After traveling for another 2 hrs, Ahmad reached town Q while Steve was still 40km away from town P.

                        (a) if Ahmad reached town Q at 1pm, what was his average speed?
                        (b) if Steve started his journey from town Q, at what time did he leave town Q?

                        Thank you.

                        Hi

                        Draw a diagram to show the journey - name the meeting point X.
                        From X, after Steve travelled for 2h, he was 40 km from P.
                        So, distance PX = 40 km + 2 x 80 km/h = 200 km

                        Ahmad reached Town Q at 1pm, so total journey time = 6h, time taken to travel from Town P to meeting point X = 4h.

                        So, Ahmad's speed = 200km/4 h = 50 km/h

                        Steve met Ahmad at 7am + 4h = 11am
                        Time taken for Steve to travel from Town Q to meeting point X
                        = 50/80 x 2h = 1h 15min

                        He left Town Q at (11am - 1h 15min) = 9.45 am

                        cheers.

                        cheers.

                        :thankyou: MathIzzzfun

                        1 Reply Last reply Reply Quote 0

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