<![CDATA[Maths Olympiad Challenge!!!]]>Hi Parents and Students,


Here's a Challenging question for all of you to solve:

Find the 6 digit number ABCDEF
such that 7 x ABCDEF = 6 x DEFABC where DEFABC is another 6 digit number.

Different letters stand for different single-digit whole numbers.

Have a fun time solving πŸ˜„ !

]]>https://forum.kiasuparents.com/topic/14978/maths-olympiad-challengeRSS for NodeWed, 24 Jun 2026 06:47:23 GMTThu, 21 Oct 2010 17:03:17 GMT60<![CDATA[Reply to Maths Olympiad Challenge!!! on Wed, 17 Nov 2010 06:35:08 GMT]]>

ctct61t:
math hub is good, but too far from my home...

Hi ctct61t, thanks for your comment.

Currently, we have 4 branches (Bishan, Bukit Batok, Kovan, Tampines) in Singapore.

Pls go to our website http://www.mathshub.com.sg/ to find out more about our programmes, schedules and location.

]]>https://forum.kiasuparents.com/post/296275https://forum.kiasuparents.com/post/296275Wed, 17 Nov 2010 06:35:08 GMT<![CDATA[Reply to Maths Olympiad Challenge!!! on Tue, 16 Nov 2010 07:09:17 GMT]]>math hub is good, but too far from my home…

]]>https://forum.kiasuparents.com/post/295747https://forum.kiasuparents.com/post/295747Tue, 16 Nov 2010 07:09:17 GMT<![CDATA[Reply to Maths Olympiad Challenge!!! on Mon, 01 Nov 2010 07:31:40 GMT]]>

Maths Hub:
The next Maths Olympiad Challenge is out.

Pls click on this link for the challenge: http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=14953&start=10 πŸ˜‰
My P5 child's answer: 858

]]>https://forum.kiasuparents.com/post/286819https://forum.kiasuparents.com/post/286819Mon, 01 Nov 2010 07:31:40 GMT<![CDATA[Reply to Maths Olympiad Challenge!!! on Mon, 01 Nov 2010 06:07:00 GMT]]>The next Maths Olympiad Challenge is out.

Pls click on this link for the challenge: http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=14953&start=10 πŸ˜‰

]]>https://forum.kiasuparents.com/post/286750https://forum.kiasuparents.com/post/286750Mon, 01 Nov 2010 06:07:00 GMT<![CDATA[Reply to Maths Olympiad Challenge!!! on Sun, 24 Oct 2010 10:52:12 GMT]]>

ksi:
Not easy to see that both sides divisible by 13 to reduce to 538 and 461 leh.....at least not for old mummy like me... πŸ˜‰


6994 ABC = 5993 DEF

538 ABC = 461 DEF

πŸ˜“ πŸ˜“ πŸ˜“
Trying out a few more numbers, I am sure everyone can get the answer too πŸ˜„

]]>https://forum.kiasuparents.com/post/281356https://forum.kiasuparents.com/post/281356Sun, 24 Oct 2010 10:52:12 GMT<![CDATA[Reply to Maths Olympiad Challenge!!! on Sun, 24 Oct 2010 10:48:10 GMT]]>

iFruit:
mujin:

[quote=\"mujin\"]
Let me try:

ABCDEF = 461538 πŸ˜„


My working :

ABCDEF x 7 = DEFABC x 6

[(ABC x 1000) + DEF] x 7 = [(DEF x 1000) + ABC] x 6

7000 ABC + 7 DEF = 6000 DEF + 6 ABC

6994 ABC = 5993 DEF

538 ABC = 461 DEF

538 (461) = 461 (538)

whereby (461) = (ABC) and
(538) = DEF

so.. ABCDEF = 461538

Hope I am right

πŸ˜„ πŸ˜„ πŸ˜„

Nice One :)[/quote]Thanks πŸ˜„

]]>https://forum.kiasuparents.com/post/281354https://forum.kiasuparents.com/post/281354Sun, 24 Oct 2010 10:48:10 GMT<![CDATA[Reply to Maths Olympiad Challenge!!! on Fri, 22 Oct 2010 17:05:51 GMT]]>

ChiefKiasu:
Maths Hub:

Pls refer to http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=14953 for the next Maths Olympiad Challenge!!!


Umm... seems like it is not much of a challenge for the super bright parents and kids we have here right on KiasuParents.com. Maybe need to turn up the difficult by a couple of dozen notches?

Indeed we will 'up' the difficulty as we move along.

]]>https://forum.kiasuparents.com/post/280939https://forum.kiasuparents.com/post/280939Fri, 22 Oct 2010 17:05:51 GMT<![CDATA[Reply to Maths Olympiad Challenge!!! on Fri, 22 Oct 2010 17:03:56 GMT]]>

ksi:
Not easy to see that both sides divisible by 13 to reduce to 538 and 461 leh.....at least not for old mummy like me... πŸ˜‰


6994 ABC = 5993 DEF

538 ABC = 461 DEF

πŸ˜“ πŸ˜“ πŸ˜“
One can use the divisibility check and see that 6994 is not divisible by 3, 4, 5, 11. (Consequently not divisible by 6, 8, 9 as well)

From there, together with the knowledge that ABC is a three digit number, we can try dividing 6994 by some other number.

With some perseverance, this question can be solved. πŸ˜„

]]>https://forum.kiasuparents.com/post/280936https://forum.kiasuparents.com/post/280936Fri, 22 Oct 2010 17:03:56 GMT<![CDATA[Reply to Maths Olympiad Challenge!!! on Fri, 22 Oct 2010 16:08:42 GMT]]>

Maths Hub:
Pls refer to http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=14953 for the next Maths Olympiad Challenge!!!

Umm... seems like it is not much of a challenge for the super bright parents and kids we have here right on KiasuParents.com. Maybe need to turn up the difficult by a couple of dozen notches?

]]>https://forum.kiasuparents.com/post/280914https://forum.kiasuparents.com/post/280914Fri, 22 Oct 2010 16:08:42 GMT<![CDATA[Reply to Maths Olympiad Challenge!!! on Fri, 22 Oct 2010 15:47:20 GMT]]>Pls refer to http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=14953 for the next Maths Olympiad Challenge!!!

]]>https://forum.kiasuparents.com/post/280907https://forum.kiasuparents.com/post/280907Fri, 22 Oct 2010 15:47:20 GMT<![CDATA[Reply to Maths Olympiad Challenge!!! on Fri, 22 Oct 2010 15:44:11 GMT]]>Not easy to see that both sides divisible by 13 to reduce to 538 and 461 leh.....at least not for old mummy like me... πŸ˜‰


6994 ABC = 5993 DEF

538 ABC = 461 DEF

πŸ˜“ πŸ˜“ πŸ˜“

]]>https://forum.kiasuparents.com/post/280905https://forum.kiasuparents.com/post/280905Fri, 22 Oct 2010 15:44:11 GMT<![CDATA[Reply to Maths Olympiad Challenge!!! on Fri, 22 Oct 2010 15:27:05 GMT]]>

iFruit:
mujin:

[quote=\"mujin\"]
Let me try:

ABCDEF = 461538 πŸ˜„


My working :

ABCDEF x 7 = DEFABC x 6

[(ABC x 1000) + DEF] x 7 = [(DEF x 1000) + ABC] x 6

7000 ABC + 7 DEF = 6000 DEF + 6 ABC

6994 ABC = 5993 DEF

538 ABC = 461 DEF

538 (461) = 461 (538)

whereby (461) = (ABC) and
(538) = DEF

so.. ABCDEF = 461538

Hope I am right

πŸ˜„ πŸ˜„ πŸ˜„

Nice One :)[/quote]Well done! This is indeed correct!

]]>https://forum.kiasuparents.com/post/280900https://forum.kiasuparents.com/post/280900Fri, 22 Oct 2010 15:27:05 GMT<![CDATA[Reply to Maths Olympiad Challenge!!! on Fri, 22 Oct 2010 14:03:45 GMT]]>

mujin:
mujin:

[quote=\"Maths Hub\"]Hi Parents and Students,


Here's a Challenging question for all of you to solve:

Find the 6 digit number ABCDEF
such that 7 x ABCDEF = 6 x DEFABC where DEFABC is another 6 digit number.

Different letters stand for different single-digit whole numbers.

Have a fun time solving πŸ˜„ !

Let me try:

ABCDEF = 461538 πŸ˜„


My working :

ABCDEF x 7 = DEFABC x 6

[(ABC x 1000) + DEF] x 7 = [(DEF x 1000) + ABC] x 6

7000 ABC + 7 DEF = 6000 DEF + 6 ABC

6994 ABC = 5993 DEF

538 ABC = 461 DEF

538 (461) = 461 (538)

whereby (461) = (ABC) and
(538) = DEF

so.. ABCDEF = 461538

Hope I am right

πŸ˜„ πŸ˜„ :D[/quote]Nice One πŸ™‚

]]>https://forum.kiasuparents.com/post/280876https://forum.kiasuparents.com/post/280876Fri, 22 Oct 2010 14:03:45 GMT<![CDATA[Reply to Maths Olympiad Challenge!!! on Fri, 22 Oct 2010 13:00:39 GMT]]>

mujin:
Maths Hub:

Hi Parents and Students,


Here's a Challenging question for all of you to solve:

Find the 6 digit number ABCDEF
such that 7 x ABCDEF = 6 x DEFABC where DEFABC is another 6 digit number.

Different letters stand for different single-digit whole numbers.

Have a fun time solving πŸ˜„ !

Let me try:

ABCDEF = 461538 πŸ˜„


My working :

ABCDEF x 7 = DEFABC x 6

[(ABC x 1000) + DEF] x 7 = [(DEF x 1000) + ABC] x 6

7000 ABC + 7 DEF = 6000 DEF + 6 ABC

6994 ABC = 5993 DEF

538 ABC = 461 DEF

538 (461) = 461 (538)

whereby (461) = (ABC) and
(538) = DEF

so.. ABCDEF = 461538

Hope I am right

πŸ˜„ πŸ˜„ πŸ˜„

]]>https://forum.kiasuparents.com/post/280848https://forum.kiasuparents.com/post/280848Fri, 22 Oct 2010 13:00:39 GMT<![CDATA[Reply to Maths Olympiad Challenge!!! on Fri, 22 Oct 2010 12:53:36 GMT]]>

Maths Hub:
Hi Parents and Students,


Here's a Challenging question for all of you to solve:

Find the 6 digit number ABCDEF
such that 7 x ABCDEF = 6 x DEFABC where DEFABC is another 6 digit number.

Different letters stand for different single-digit whole numbers.

Have a fun time solving πŸ˜„ !
Let me try:

ABCDEF = 461538 πŸ˜„

]]>https://forum.kiasuparents.com/post/280846https://forum.kiasuparents.com/post/280846Fri, 22 Oct 2010 12:53:36 GMT<![CDATA[Reply to Maths Olympiad Challenge!!! on Fri, 22 Oct 2010 09:53:46 GMT]]>

Jojo_2010:
7 X ABCDEF = 6 X DEFABC


A=6
B=5
C=4
D=7
E=2
F=3

7X6X5X4X7X2X3=6X7X2X3X6X5X4=30240.
Am i rite?
Not Correct
For your equation above, LHS is not equal to RHS.

Anyway, ABCDEF is a 6 digit number, not a product of 6 single digit number.

]]>https://forum.kiasuparents.com/post/280796https://forum.kiasuparents.com/post/280796Fri, 22 Oct 2010 09:53:46 GMT<![CDATA[Reply to Maths Olympiad Challenge!!! on Fri, 22 Oct 2010 05:35:27 GMT]]>7 X ABCDEF = 6 X DEFABC


A=6
B=5
C=4
D=7
E=2
F=3

7X6X5X4X7X2X3=6X7X2X3X6X5X4=30240.

Am i rite?

]]>https://forum.kiasuparents.com/post/280583https://forum.kiasuparents.com/post/280583Fri, 22 Oct 2010 05:35:27 GMT