<?xml version="1.0" encoding="UTF-8"?><rss xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:content="http://purl.org/rss/1.0/modules/content/" xmlns:atom="http://www.w3.org/2005/Atom" version="2.0"><channel><title><![CDATA[sec 3 e math]]></title><description><![CDATA[<p dir="auto">can help me solve this question<br /><br /><br />[5x^3y^4/4xy^3] x [(25x^4y)^-1/(2xy)^-2]<br /><br />ans:   125/16x^4<br /><br />thks</p>
]]></description><link>https://forum.kiasuparents.com/topic/32209/sec-3-e-math</link><generator>RSS for Node</generator><lastBuildDate>Sun, 26 Apr 2026 17:26:31 GMT</lastBuildDate><atom:link href="https://forum.kiasuparents.com/topic/32209.rss" rel="self" type="application/rss+xml"/><pubDate>Sat, 18 Feb 2012 13:14:59 GMT</pubDate><ttl>60</ttl><item><title><![CDATA[Reply to sec 3 e math on Sun, 19 Feb 2012 09:56:35 GMT]]></title><description><![CDATA[<p>I suspect your question contains error. It's quite unlikely that you'll have something like \" 5x to the power of 3<b><b>y to the power of 4</b></b>\"  for an emaths problem..</p>]]></description><link>https://forum.kiasuparents.com/post/713277</link><guid isPermaLink="true">https://forum.kiasuparents.com/post/713277</guid><dc:creator><![CDATA[mum_sugoku]]></dc:creator><pubDate>Sun, 19 Feb 2012 09:56:35 GMT</pubDate></item></channel></rss>