<?xml version="1.0" encoding="UTF-8"?><rss xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:content="http://purl.org/rss/1.0/modules/content/" xmlns:atom="http://www.w3.org/2005/Atom" version="2.0"><channel><title><![CDATA[Profit&#x2F; Loss Q]]></title><description><![CDATA[<p dir="auto">Hi , I need help on this<br /><br /><br />Mr Lee bought a flat at $540,000 and he sold it to Mr Ong at a loss . Mr Ong then sold it at a profit to Mr Tan at $535,000. If the loss percentage on the cost of Mr Lee is equal to the percentage profit of Mr Ong on his cost, find the price Mr Ong paid for the flat . Thank You</p>
]]></description><link>https://forum.kiasuparents.com/topic/40553/profit-loss-q</link><generator>RSS for Node</generator><lastBuildDate>Sun, 19 Apr 2026 06:51:16 GMT</lastBuildDate><atom:link href="https://forum.kiasuparents.com/topic/40553.rss" rel="self" type="application/rss+xml"/><pubDate>Thu, 13 Sep 2012 13:03:46 GMT</pubDate><ttl>60</ttl><item><title><![CDATA[Reply to Profit&#x2F; Loss Q on Fri, 28 Sep 2012 09:34:45 GMT]]></title><description><![CDATA[<p dir="auto">Oh I forgot to add a note:<br /><br />The above type of P/L qns typically require a clear understanding of how to apply the cost base (ie 100%) correctly, and changing the base appropriately. <br />Pls feel free to let me know if I can be of any further help. I’ll try my best to respond ASAP. <br />Cheers!</p>
]]></description><link>https://forum.kiasuparents.com/post/862561</link><guid isPermaLink="true">https://forum.kiasuparents.com/post/862561</guid><dc:creator><![CDATA[Jtutor]]></dc:creator><pubDate>Fri, 28 Sep 2012 09:34:45 GMT</pubDate></item><item><title><![CDATA[Reply to Profit&#x2F; Loss Q on Fri, 28 Sep 2012 09:26:18 GMT]]></title><description><![CDATA[<p>Hi gijg,<br /><br />I just joined as a newbie yesterday so I guess it might be too late for the solution you wanted. Nevermind I'm happy to share my workings as follow:<br /><br />Let x be the % of loss or profit. <br />1st selling price (at a loss of x%) = (100-x)/100 * 540,000 = 5400 (100-x)<br />2nd selling price (at a profit of x%) = [5400 (100-x)/ 100] * (100+x) = 535,000<br />Simplify: 54 (100^2 - x^2) = 535,000<br />Solve for x =&gt; 9.62%<br />Hence, price that Mr Ong paid (1st selling price) =&gt; $488,052<br /><br />Hope the above helps! <img src="https://forum.kiasuparents.com/assets/plugins/nodebb-plugin-emoji/emoji/android/1f609.png?v=f4f27f6278e" class="not-responsive emoji emoji-android emoji--wink" style="height:23px;width:auto;vertical-align:middle" title=";)" alt="😉" /></p>]]></description><link>https://forum.kiasuparents.com/post/862552</link><guid isPermaLink="true">https://forum.kiasuparents.com/post/862552</guid><dc:creator><![CDATA[Jtutor]]></dc:creator><pubDate>Fri, 28 Sep 2012 09:26:18 GMT</pubDate></item></channel></rss>