<?xml version="1.0" encoding="UTF-8"?><rss xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:content="http://purl.org/rss/1.0/modules/content/" xmlns:atom="http://www.w3.org/2005/Atom" version="2.0"><channel><title><![CDATA[Pri School Exam Hub]]></title><description><![CDATA[<p dir="auto">CHEWY MATH TUITION CENTRE <br /><br />Unleash Their Potential!<br /><br />Chewy Math is founded in October 2014. We believe in the potential in every child to do well. Through the star chart and reward system, we aim to make learning easy yet fun. With a smaller class size and step by step learning approach, we help the children to understand the creative and fun concepts. We also encourage the children to think on their feet and being able to solve the question independently. They will thus gain confidence and do even better and their potential will be unleashed.</p>
]]></description><link>https://forum.kiasuparents.com/topic/57726/pri-school-exam-hub</link><generator>RSS for Node</generator><lastBuildDate>Tue, 23 Jun 2026 05:34:51 GMT</lastBuildDate><atom:link href="https://forum.kiasuparents.com/topic/57726.rss" rel="self" type="application/rss+xml"/><pubDate>Thu, 29 Jan 2015 07:02:03 GMT</pubDate><ttl>60</ttl><item><title><![CDATA[Reply to Pri School Exam Hub on Mon, 01 Jul 2013 15:41:06 GMT]]></title><description><![CDATA[<p>Concept: Repeated Identity <br /><br /><br />Mary and Jenny had a number of stickers in the ratio 4: 1. Jenny and Grace had a number of stickers in the ratio 2: 3. If they have a total of 169 stickers altogether, how many stickers does Mary have? <br /><br />Exam tips!!<br />1. Highlight the key words<br />2. Identify the concept: Repeated identity<br />3. Write down the info provided in the question<br /><br />Whose name is repeated twice? <b><b>JENNY!!</b></b><br />M : J       <br />4 : <b><b>1</b></b> (multiply by 2 to make Jenny's ratio the same)  <br />    <br />J : G  <br /><b><b>2</b></b> : 3<br /><br />Put the ratio together to compare<br /><span style="color:#FF4000">M : J : G<br />8 : 2 : 3</span><br />Total units = 8 + 2 + 3 = 13<br /><br />13 units -&gt; 169 stickers<br />1 unit -&gt; 13 stickers<br />8 units -&gt; <b><b>104 stickers</b></b><br />Mary has 104 stickers<br /><br />** Repeated identity questions can be in the form of percentages, fractions and ratio.</p>]]></description><link>https://forum.kiasuparents.com/post/1027499</link><guid isPermaLink="true">https://forum.kiasuparents.com/post/1027499</guid><dc:creator><![CDATA[Adele Yeo]]></dc:creator><pubDate>Mon, 01 Jul 2013 15:41:06 GMT</pubDate></item><item><title><![CDATA[Reply to Pri School Exam Hub on Mon, 01 Jul 2013 15:27:00 GMT]]></title><description><![CDATA[<p>Hi jwxh, <br /><br /><br />Thank you for the qn. I welcome more questions <img src="https://forum.kiasuparents.com/assets/plugins/nodebb-plugin-emoji/emoji/android/1f603.png?v=f4f27f6278e" class="not-responsive emoji emoji-android emoji--smiley" style="height:23px;width:auto;vertical-align:middle" title="=)" alt="😃" /><br /><br />A stapler cost $8. A dictionary cost $12.50. Tom bought 9 staplers and dictionaries. He paid $31 more for the staplers than the dictionaries. How many dictionaries did tom buy?[/quote]<br /><br /><br />Method 1: Algebra<br />Let the number of stapler be x. Let the number of dictionary be y.<br />Equation 1: x + y =9<br />Equation 2: 8x - 12.5y = 31<br /><br />From eqn 1, we can say that x = 9 - y<br />Then we substitute x = 9 - y into eqn 2. <br />8 (9 - y) - 12.5y = 31<br />72 - 8y - 12.5y = 31<br />12.5y + 8y = 72 - 31 <br />20.5y = 41<br /><b><b>y = 2</b></b><br />Thus, he bought two dictionaries. <br /><br />Method 2: Assumption method<br />Assume that Tom has spent all his money on staplers<br />9 x $8 = $72<br /><br />Take out the $31 more that he spent on staplers <br />$72 - $31 = $41<br /><br />Now we can add up the amount of a stapler and a dictionary<br />$12.50 + $8 = $20.50 (1 set of stapler and dictionary)<br /><br />Divide <br />$41 / $20.50 = <b><b>2</b></b><br />Thus, he bought two dictionaries. <br /><br /><br />EXAM TIPS: If you have time, you can check the answer. <br />Dictionary: 2 x $12.50 = $25 <br />Staplers: 7 x 8 = $56<br />Difference: $56 - $25 = $31</p>]]></description><link>https://forum.kiasuparents.com/post/1027484</link><guid isPermaLink="true">https://forum.kiasuparents.com/post/1027484</guid><dc:creator><![CDATA[Adele Yeo]]></dc:creator><pubDate>Mon, 01 Jul 2013 15:27:00 GMT</pubDate></item><item><title><![CDATA[Reply to Pri School Exam Hub on Wed, 26 Jun 2013 02:49:31 GMT]]></title><description><![CDATA[<p dir="auto">besides guess and check, what is the shortcut solution for below question. tks<br /><br /><br />A stapler cost $8. A dictionary cost $12.50. Tom bought 9 staplers and dictionaries. He paid $31 more for the staplers than the dictionaries. How many dictionaries did tom buy?</p>
]]></description><link>https://forum.kiasuparents.com/post/1024353</link><guid isPermaLink="true">https://forum.kiasuparents.com/post/1024353</guid><dc:creator><![CDATA[jwxh]]></dc:creator><pubDate>Wed, 26 Jun 2013 02:49:31 GMT</pubDate></item><item><title><![CDATA[Reply to Pri School Exam Hub on Tue, 25 Jun 2013 12:33:21 GMT]]></title><description><![CDATA[<p>2) Concept: Constant difference (Ratio)<br /><br /><br />The ratio of Martin's age to Jeremy's age is 1:4. In 15 years time, the new ratio is 2:3. How old is Martin now?<br /><br />Note: The age difference/ age gap always remain the same. <br />Thus, we have to make both difference the same.  <br /><b><b>1:4</b></b> (difference is 3 units)<br />2:3 = <b><b>6:9</b></b> (multiply by 3 to have the difference of 3 units) <br /><br />Difference: <br />Martin: 1 unit to 6 units (Diff: 5u)<br />Jeremy: 4 units to 9 units (Diff: 5u)<br />Thus, the 5 units will be the growth of 15 years<br />5 units =&gt; 15<br />1 unit =&gt; 3<br />Martin is <b><b>3 years old </b></b>now.</p>]]></description><link>https://forum.kiasuparents.com/post/1024106</link><guid isPermaLink="true">https://forum.kiasuparents.com/post/1024106</guid><dc:creator><![CDATA[Adele Yeo]]></dc:creator><pubDate>Tue, 25 Jun 2013 12:33:21 GMT</pubDate></item></channel></rss>