<?xml version="1.0" encoding="UTF-8"?><rss xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:content="http://purl.org/rss/1.0/modules/content/" xmlns:atom="http://www.w3.org/2005/Atom" version="2.0"><channel><title><![CDATA[Table Method 2A - Quantity Amount Table in Fraction]]></title><description><![CDATA[<p>Lesson 3 - Equal Fraction Method<br /><br /><br />In some problem sums,  the fractions are equal.<br /><br />Look at this example.<br /><br /><img src="\&quot;https://s18.postimg.org/ldb6ozxuh/20180309_110047-1.jpg\&quot;" /><img src="\&quot;&lt;a" />https://s18.postimg.org/ldb6ozxuh/20180309_110047-1.jpg\"&gt;<br /><br />We shall first find the LCM of the Numerators. <br /><br /><img src="\&quot;https://s18.postimg.org/adpzdfhq1/20180309_110047-2.jpg\&quot;" /><img src="\&quot;&lt;a" />https://s18.postimg.org/adpzdfhq1/20180309_110047-2.jpg\"&gt;<br /><br />Take note of the Denominators.  They are units each person have.<br /><br /><img src="\&quot;https://s18.postimg.org/9bfsuyyxl/20180309_110047-3.jpg\&quot;" /><img src="\&quot;&lt;a" />https://s18.postimg.org/9bfsuyyxl/20180309_110047-3.jpg\"&gt;<br /><br />So the Ratio of Alan : Ben = 14 : 25.<br /><br />Let's do the following sums. <br /><br /><br /><img src="\&quot;https://s18.postimg.org/6hcnhmzd5/20180309_110723-1.jpg\&quot;" /><img src="\&quot;&lt;a" />https://s18.postimg.org/6hcnhmzd5/20180309_110723-1.jpg\"&gt;<br /><br /><img src="\&quot;https://s18.postimg.org/pz7axl40p/20180309_110730-1.jpg\&quot;" /><img src="\&quot;&lt;a" />https://s18.postimg.org/pz7axl40p/20180309_110730-1.jpg\"&gt;<br /><br /><img src="\&quot;https://s18.postimg.org/o7ec2o589/20180309_110735-1.jpg\&quot;" /><img src="\&quot;&lt;a" />https://s18.postimg.org/o7ec2o589/20180309_110735-1.jpg\"&gt;<br /><br /><img src="\&quot;https://s18.postimg.org/o7ec2npsp/20180309_110742-1.jpg\&quot;" /><img src="\&quot;&lt;a" />https://s18.postimg.org/o7ec2npsp/20180309_110742-1.jpg\"&gt;</p>]]></description><link>https://forum.kiasuparents.com/topic/90830/table-method-2a-quantity-amount-table-in-fraction</link><generator>RSS for Node</generator><lastBuildDate>Tue, 14 Jul 2026 02:41:54 GMT</lastBuildDate><atom:link href="https://forum.kiasuparents.com/topic/90830.rss" rel="self" type="application/rss+xml"/><pubDate>Fri, 09 Mar 2018 03:08:41 GMT</pubDate><ttl>60</ttl><item><title><![CDATA[Reply to Table Method 2A - Quantity Amount Table in Fraction on Fri, 09 Mar 2018 02:54:12 GMT]]></title><description><![CDATA[<p>Lesson 2 - Common Ratio Method <br /><br /><br />In some problem sums, the ratios are not directly related as in ABC Ratio.<br /><br />Let's see this example.<br /><br /><img src="\&quot;https://s18.postimg.org/elkrmcbhl/20180309_104821-1.jpg\&quot;" /><img src="\&quot;&lt;a" />https://s18.postimg.org/elkrmcbhl/20180309_104821-1.jpg\"&gt;<br /><br />Tom is the Common item. We shall write him as the denominator. <br /><br /><img src="\&quot;https://s18.postimg.org/h46gmhf21/20180309_104821-2.jpg\&quot;" /><img src="\&quot;&lt;a" />https://s18.postimg.org/h46gmhf21/20180309_104821-2.jpg\"&gt;<br /><br />Then we find the LCM of Tom.<br /><br />So the whole problem sum will be like this.<br /><br /><img src="\&quot;https://s18.postimg.org/ul3f5eujd/20180309_104821-3.jpg\&quot;" /><img src="\&quot;&lt;a" />https://s18.postimg.org/ul3f5eujd/20180309_104821-3.jpg\"&gt;<br /><br />We shall always write the LCM on the bottom left side of our working.<br /><br />Ready for some problem solving? <br /><br /><img src="\&quot;https://s18.postimg.org/bg05vsl21/20180309_105315-1.jpg\&quot;" /><img src="\&quot;&lt;a" />https://s18.postimg.org/bg05vsl21/20180309_105315-1.jpg\"&gt;<br /><br /><img src="\&quot;https://s18.postimg.org/bsrk1yvm1/20180309_105322-1.jpg\&quot;" /><img src="\&quot;&lt;a" />https://s18.postimg.org/bsrk1yvm1/20180309_105322-1.jpg\"&gt;<br /><br /><img src="\&quot;https://s18.postimg.org/grf2ghrp5/20180309_105328-1.jpg\&quot;" /><img src="\&quot;&lt;a" />https://s18.postimg.org/grf2ghrp5/20180309_105328-1.jpg\"&gt;<br /><br /><img src="\&quot;https://s18.postimg.org/4pjomcaqx/20180309_105336-1.jpg\&quot;" /><img src="\&quot;&lt;a" />https://s18.postimg.org/4pjomcaqx/20180309_105336-1.jpg\"&gt;</p>]]></description><link>https://forum.kiasuparents.com/post/1837156</link><guid isPermaLink="true">https://forum.kiasuparents.com/post/1837156</guid><dc:creator><![CDATA[Khong Pek Mao]]></dc:creator><pubDate>Fri, 09 Mar 2018 02:54:12 GMT</pubDate></item></channel></rss>