Q&A - P4 Math

[smartmummy]

Saravana:

smartmummy:

[quote=\"Saravana\"]Can help me with this question?i can't figure out the answer.Please explain with working.


Carol paid $72 for 2 blouses and 1 dress.5 blouses cost as much as 2 dresses.How much more did she pay for each dress than a blouse?

Thanks
Sara

1 blouse=2/5 dress
blouse [][]
dress [][][][][]

2blouses+1dress=$72
4u+5u=$72
1 u=$8
ans : 3*$8=$24

how do you get 1 blouse =2/5 dress. :?[/quote]

[ruohoo97]

smartmummy:

Saravana:

[quote=\"Saravana\"]Can help me with this question?i can't figure out the answer.Please explain with working.


Carol paid $72 for 2 blouses and 1 dress.5 blouses cost as much as 2 dresses.How much more did she pay for each dress than a blouse?

Thanks
Sara

[/quote]Dear Sara,

5 Blouses= 2 Dresses
2 Blouses + 1 Dress=72
-_______________________
Using the replacing method, you get:-

9 blouses =72 X2
1 Blouse=8
1 Dress=40

40-8=32

[MathIzzzFun]

Saravana:

Can help me with this question?i can't figure out the answer :? :? .Please explain with working.


Carol paid $72 for 2 blouses and 1 dress.5 blouses cost as much as 2 dresses.How much more did she pay for each dress than a blouse?

Thanks :thankyou:
Sara :imdrowning:

One approach is to use the equal fraction method to \"convert\" to units....

5 blouses = 2 dresses
10/2 blouses = 10/5 dresses

1 blouse --> 2 units, 2 blouses --> 4 units
1 dress --> 5 units
5 units - 2 units = 3 units --> 1 dress cost 3 units more than a blouse

2 blouses + 1 dress --> 9 units = $72
1 units --> $8

3 units --> $24,
1 dress cost $24 more than a blouse.


cheers.

[smartmummy]

hi ruohoo97!

pls check ur calculation…
9b=722
1b=82
i think u missed multiply by2?

[ssmummy]

2 blouses + 1 dress –>$72

4 blouses + 2 dresses –> $72 x 2 = $144

2 dresses cost as much as 5 blouses

Therefore,
4 blouses + 5 blouses –> $144
1 blouse –> $144/9 =$16

Since 2 blouses and 1 dress cost $72,
1 dress –> $72 - $16 - $16 = $40

$40 - $16 = $24
For each dress, she paid $24 more.

[htn]

need help for the following:


1) what is the difference between the 5th multiple of 8 and the sum of all the factors of 25?

2) Gina had 12 more fifty-cent coins than one-dollar coins. When she exchanged all of the fifty-cent coins for one-dollar coins, she had 18 one-dollar coins altogether. How many fifty-cent coins did she have?

TIA

[smartmummy]

htn:

need help for the following:


1) what is the difference between the 5th multiple of 8 and the sum of all the factors of 25?

2) Gina had 12 more fifty-cent coins than one-dollar coins. When she exchanged all of the fifty-cent coins for one-dollar coins, she had 18 one-dollar coins altogether. How many fifty-cent coins did she have?

TIA

1) 5th multiple of 8 = 40
sum of all the factors of 25=25+1+5=31
difference 40-31=9
2)ans is 20....couldn't go down to write as using iphone.
fifty-cent [ u |12 ]
one doll [ u]
(u+12)/2+u=18
u+12+2u=36
u=8

[MathIzzzFun]

htn:

need help for the following:


1) what is the difference between the 5th multiple of 8 and the sum of all the factors of 25?

2) Gina had 12 more fifty-cent coins than one-dollar coins. When she exchanged all of the fifty-cent coins for one-dollar coins, she had 18 one-dollar coins altogether. How many fifty-cent coins did she have?

TIA

1)
5th multiple of 8 --> 40
factors of 25 --> 1,5,25 --- total 31
(3 factors only. All square numbers have odd number of factors because one of the factors has a twin)

40-31=9

2) total amount = $18
12 more fifty cents coins --> $6
$18-$6 = $12 --- removing the excess 50-cents so that there are equal number of $1 and 50-cent coins,
$12 / (1+0.50) = 8

number of $1 coins = 8
number of 50-cent coins = 8 + 12 = 20

cheers.

[lotto]

htn:

need help for the following:


1) what is the difference between the 5th multiple of 8 and the sum of all the factors of 25?

2) Gina had 12 more fifty-cent coins than one-dollar coins. When she exchanged all of the fifty-cent coins for one-dollar coins, she had 18 one-dollar coins altogether. How many fifty-cent coins did she have?

TIA

1) 5th multiple of 8 is 5 x 8 = 40
factors of 25 is 1, 5 and 25. so the sum of all factors is 1 + 5 + 25 = 31
difference is 40 - 31 = 9

2) the easiest method to undestand is this assumption i think. or maybe u can try to draw the model
assume the no. of $1 is 2 units.
So the no. of 50cents is 2 units + 12
When u change all the 50 cents to $1, the no. of $1 u will get is 1 unit + 6 (which is half of 2 units + 12)
Total number of $1 u have now is 2 units + 1 unit + 6 = 3 units + 6
3 units + 6 = 12
3 units = 6
1 unit = 2
50-cents = 2 units + 12 = 16 coins

hope it helps :roll:

[ruohoo97]

smartmummy:

hi ruohoo97!

pls check ur calculation....
9b=72*2
1b=8*2
i think u missed multiply by2?

Yes, smartmummy, you are absolutely right!