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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • P Offline
      Pen88n
      last edited by

      pixiedust:
      Hi Tianzhu, thanks. It is from worksheet given by ds's school.

      May I know the thinking process to derive the answer ?
      I am not Tianzhu, but maybe I can help to clarify how to derive the answer.

      The 1st clue comes from A x 4 = D. D is a single digit number, so A can only be 1 or 2. Again D x 4 = a number with a last digit A. By substituting 1 and 2 into the 2 equations, you can derived that A = 2 and D = 8

      Now that we know A = 2 and D = 8, we also know that B x 4 = C, C will be a single digit, so B is 1 and C is > 4. C x 4 + 3 = a number that ends with a digit 1. By substituting, you will find that C = 7

      1 Reply Last reply Reply Quote 0
      • MathIzzzFunM Offline
        MathIzzzFun
        last edited by

        pixiedust:
        Hi Tianzhu, thanks. It is from worksheet given by ds's school.

        May I know the thinking process to derive the answer ?
        Hi

        Just to add some points. Two concepts will be useful in solving this puzzle :
        1. Any number x even number = even number
        2. Even number + ODD number = odd number


        http://postimage.org/image/2ia1jqch0/


        cheers.

        1 Reply Last reply Reply Quote 0
        • P Offline
          pixiedust
          last edited by

          Thank you Pen88n & MathIzzzFun ! I need a bit of time to think through your explanations but they surely helped. Thanks very much !

          1 Reply Last reply Reply Quote 0
          • ozoraO Offline
            ozora
            last edited by

            tianzhu:
            ozora:


            Is my model correct? and I got stuck.

            D [ 40 ][ 70]
            A [20][ ]

            D [20][ 130 ]
            A [20][20][ ]

            Hi ozora.

            Good Morning.

            This is a question involving “case1 case 2 scenarios”.

            In doing this question, it’s important to note that the number of words to be learnt by Doris and Annie remains the same in both cases.

            The first slide shows the thought process. You may use MD or UM to solve this question. In this case, I am using the MD way. As usual, I am drawing more models than necessary to show the flow of events.

            Hope this helps.

            Best wishes

            http://farm6.static.flickr.com/5063/5615048270_0b36426626_z.jpg\">

            http://farm6.static.flickr.com/5142/5614468685_555807d62e_z.jpg\">

            thanks for the guide

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            • ozoraO Offline
              ozora
              last edited by

              MathIzzzFun:
              ozora:

              Need guidance.

              Doris and Annie have each planned a list of words to learn,
              If Doris learnt 40 words per day while Annie learnt 20 words per day, Doris would have 70 words left to learn while Annie had completed learning all the words.
              If Doris learnt 20 words per day while Annie learnt 40 words per day, Doris would have 130 words left to learn while Annie had completed learning all the words.
              How many words do Doris and Annie have to learn respectively?

              Is my model correct? and I got stuck.

              D [ 40 ][ 70]
              A [20][ ]

              D [20][ 130 ]
              A [20][20][ ]

              Hi

              MD is as follows:

              [] =words learnt

              Scenario 1
              D [][][][][70]
              A [][]

              Scenario 2
              D [][130]
              A [][]

              Comparing the models for \"D\"
              [][][] = 60
              [] = 20

              So, number of words to be learnt:
              D = 4 x 20 + 70 = 150
              A = 2 x 20 = 40

              cheers.

              thanks for the guide too

              1 Reply Last reply Reply Quote 0
              • ozoraO Offline
                ozora
                last edited by

                Hi all

                I used algebra to solve this problem but is it possible to use model to solve the problem? If yes, how?
                Twice of a number is greater than two-third of that number by 28.
                I got the answer 21.
                Thanks

                1 Reply Last reply Reply Quote 0
                • Y Offline
                  Yu Xuan
                  last edited by

                  ozora:
                  Hi all

                  I used algebra to solve this problem but is it possible to use model to solve the problem? If yes, how?
                  Twice of a number is greater than two-third of that number by 28.
                  I got the answer 21.
                  Thanks
                  Hi

                  Model is pretty easy to understand in this case;

                  Let the number be 3 units, hence twice the number will be 6 units, and 2/3 the number will be 2 units

                  [N][N][N][N][N][N]
                  [N][N]-----28 ------

                  4 units -->28
                  1 unit --> 28 ÷ 4 = 7
                  3 units --> 7 x 3 = 21

                  Yu Xuan

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                  • L Offline
                    lizawa
                    last edited by

                    ozora:
                    Hi all

                    I used algebra to solve this problem but is it possible to use model to solve the problem? If yes, how?
                    Twice of a number is greater than two-third of that number by 28.
                    I got the answer 21.
                    Thanks
                    Yes, it's possible to use model.

                    Twice of a number : draw 6 boxes
                    2/3 of the number : draw 2 boxes

                    The difference is 4 boxes (or 4u)

                    4u = 28
                    1u = 7

                    the number is 3u, so 3u = 3* 7 = 21.

                    1 Reply Last reply Reply Quote 0
                    • J Offline
                      jieheng
                      last edited by

                      fxchow:


                      Hi JieHeng,

                      Thanks for your solution.

                      fxchow
                      Hi fxchow ,

                      You are welcome.

                      Regards,

                      1 Reply Last reply Reply Quote 0
                      • T Offline
                        tianzhu
                        last edited by

                        ozora:
                        thanks for the guide

                        Hi

                        You're welcome.

                        Best wishes.

                        1 Reply Last reply Reply Quote 0

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