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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • MathIzzzFunM Offline
      MathIzzzFun
      last edited by

      Winx5015:
      Hi, got problem with math questions again . Sigh... 😞


      (1) Adrian, Ben and Calvin share 436 marbles. After Adrian gave away 2/5 of his marbles, the ratio of the number of marbles he has to Ben became 4:9. When Calvin lost 1/3 of his marbles, the total number of marbles the children has was 352. How many marbles did Calvin have at first?

      Thanks πŸ™‚
      Hi

      After Adrian gave away 2/5 of his marbles :
      Adrian's marbles : Ben's marbles --> 4 : 9 --> 12u : 27u --total 39u
      Number given away by Adrian --> 8u

      Calvin's marble --> 3p, lost --> 1p
      Marbles given away & lost, 8u + 1p = 436-352 = 84 -- (1)
      Marbles left, 39u + 2p = 352 ---(2)
      Solving (1) & (2), 1u --> 8, 1p --> 20

      Number of marbles Calvin had at first --> 3 x 20 = 60

      cheers.

      1 Reply Last reply Reply Quote 0
      • MathIzzzFunM Offline
        MathIzzzFun
        last edited by

        Winx5015:
        Hi, got problem with math questions again . Sigh... 😞


        (2) Jodie has 20% more red beads than green beads. She has 50 more orange beads than red beads. She mixed 20% of each of the coloured beads to make a total of 22 bracelets. She had used 298 red and orange beads for all the bracelets. How many beads were there in each bracelet?

        Thanks πŸ™‚
        Hi
        Red beads --> 60u, 20% --> 12u
        Green beads --> 50u, 20% --> 10u
        Orange beads --> 60u + 50, 20% --> 12u + 10
        24u + 10 --> 298, 1u --> 12

        Total beads used --> 298 + 10 x 12 = 418
        Number of beads in each bracelet --> 418 / 22 = 19

        cheers.

        1 Reply Last reply Reply Quote 0
        • A Offline
          anneshirleygilbert
          last edited by

          Hi MathIzzzFun,


          I have some trouble interpreting this question:

          The sum of 4 numbers is 80.If you add 3 to the first number, subtract 3 from the second number,multiply the third number by 3 d divide the fourth number by 3,the result will be equal.What is the difference between the largest and the smallest of the original numbers.

          How do you interpret "the result will be equal"? You have made the end of each number equals 15, giving a total of 60. I interpreted it as the end total result is equal to the beginning total of 80 and got a mixed fraction answer. How do you know what’s the right way of interpreting the question? We get into such muddles sometimes. Pls help.


          hi

          Hi
          after multiplying 3rd number by 3 –> 3u

          1st number –> 3u-3
          2nd number –> 3u +3
          3rd number –> 1u
          4th number –> 9u
          Total –> 16u = 80
          1u –> 5

          1st number –> 12
          2nd number –> 18
          3rd number –> 5
          4th number –> 45

          cheers.

          1 Reply Last reply Reply Quote 0
          • W Offline
            Winx5015
            last edited by

            Hi MathIzzzFun, thank you and have a nice day πŸ™‚

            1 Reply Last reply Reply Quote 0
            • MathIzzzFunM Offline
              MathIzzzFun
              last edited by

              anneshirleygilbert:
              Hi MathIzzzFun,


              I have some trouble interpreting this question:

              The sum of 4 numbers is 80.If you add 3 to the first number, subtract 3 from the second number,multiply the third number by 3 d divide the fourth number by 3,the result will be equal.What is the difference between the largest and the smallest of the original numbers.

              How do you interpret \"the result will be equal\"? You have made the end of each number equals 15, giving a total of 60. I interpreted it as the end total result is equal to the beginning total of 80 and got a mixed fraction answer. How do you know what's the right way of interpreting the question? We get into such muddles sometimes. Pls help.


              hi

              Hi
              after multiplying 3rd number by 3 --> 3u

              1st number --> 3u-3
              2nd number --> 3u +3
              3rd number --> 1u
              4th number --> 9u
              Total --> 16u = 80
              1u --> 5

              1st number --> 12
              2nd number --> 18
              3rd number --> 5
              4th number --> 45

              cheers.
              \"If you add 3 to the first number, subtract 3 from the second number,multiply the third number by 3 d divide the fourth number by 3,the result will be equal\"--> my interpretation is:
              1st number + 3
              = 2nd number - 3
              = third number x 3
              = fourth number/3
              = 3u (since the 3rd number was multiplied by 3)
              so, this gives,
              1st number --> 3u -3
              2nd number --> 3u + 3
              3rd number --> 3u/3 = 1u
              4th number --> 3u x 3 = 9u

              cheers.

              1 Reply Last reply Reply Quote 0
              • S Offline
                Shimmer
                last edited by

                1)At 9a.m, John was cycling from A to B . At the same time, Mary was cycling from Point B to A using the same route as John. Cycling at a speed of 4km/h faster than Mary, John would pass Mary 300 m away from midpoint.

                A)What time did that pass each other?
                B) If John took another 3 min to reach B, what time would Mary reach B?

                1 Reply Last reply Reply Quote 0
                • S Offline
                  Shimmer
                  last edited by

                  In the 6A and B,the total number of girls was 100% more than boys. The ratio of boy to girl in 6A is 3:4 and the ratio of boy to girl in 6B is 1:6. If there were 8 more girls in 6a than 6b, find the no. of pupils in 6a.

                  1 Reply Last reply Reply Quote 0
                  • S Offline
                    Shimmer
                    last edited by

                    John had $180 more than Ail at first. Both bought a different printer with some money. In the end, Ail was left with $20 more than John. If John’s printer cost 50% more than Ali’s printer,how much does John printer cost?

                    1 Reply Last reply Reply Quote 0
                    • MathIzzzFunM Offline
                      MathIzzzFun
                      last edited by

                      Shimmer:
                      John had $180 more than Ail at first. Both bought a different printer with some money. In the end, Ail was left with $20 more than John. If John's printer cost 50% more than Ali's printer,how much does John printer cost?


                      Hi

                      http://i46.tinypic.com/2aj6wqx.png\">

                      cheers.

                      1 Reply Last reply Reply Quote 0
                      • MathIzzzFunM Offline
                        MathIzzzFun
                        last edited by

                        Shimmer:
                        In the 6A and B,the total number of girls was 100% more than boys. The ratio of boy to girl in 6A is 3:4 and the ratio of boy to girl in 6B is 1:6. If there were 8 more girls in 6a than 6b, find the no. of pupils in 6a.


                        Hi

                        6A, Boys: Girls = 3:4 --> 9:12
                        6B, Boys: Girls = 1:6 --> 2:12

                        There were 8 more girls in 6A than 6B,
                        6A, Boys: Girls --> 9u + 6 : 12u + 8 -- total --> 21u + 14
                        6B, Boys: Girls --> 2u : 12u

                        Total number of girls was 100% more than boys,
                        24u + 8 = 2 x (11u +6)
                        1u --> 2

                        Total number of pupils in 6A --> 21 x 2 + 14 = 56

                        cheers.

                        1 Reply Last reply Reply Quote 0

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