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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • MathIzzzFunM Offline
      MathIzzzFun
      last edited by

      Winx5015:
      Hi,can anyone help me solve the following questions.


      2)The distance between point A and point B of an island is 50km.At 11am, Afiq left point A and cycled towards point B.Benny left point A half an hour later and cycled towards point B.Benny's cycling speed was 4km/h faster than Afiq's.At 1pm,Benny caught up with Afiq.When Benny was 10km away from point B,he stopped to wait for Afiq.
      a)What was Benny's speed?
      b))How far was Afiq from Benny when Benny stopped to wait for him?

      Thanks:)
      Time taken for Benny to catch up with Afiq --> from 1130 to 1300 --> 1.5h
      Time taken by Afiq, when Benny caught up --> from 1100 to 1300 --> 2h
      Time ratio of Benny : Afiq --> 1.5 : 2 = 3 :4
      Speed ratio of Benny : Afiq --> 4u : 3u
      1u --> 4km/h
      a) Benny's speed--> 16 km/h

      When Benny stopped to wait for Afiq,
      distance he cycled --> 50 km-10km = 40km

      time taken --> 40/16 = 2.5h
      2.5h-1.5h = 1h --> Benny and Afiq cycled for 1h after they \"met\"
      b) 1h x 4km/h = 4km --> Afiq was 4km behind Benny when Benny stopped.

      cheers.

      1 Reply Last reply Reply Quote 0
      • Z Offline
        zanen
        last edited by

        Hi I’m Zan En’s sister and would like to ask this qns on her behalf. Mrs Leong had white and orange ping pong balls in the ratio 7:5. She then replaced several white ping pong balls with orange ones keeping the total number of ping pong balls the same. The ratio of the number of white ping pong balls to orange ping pong balls became 3:5.

        (a) If the total number of ping pong balls is not more than 30, how many white ping pong balls did Mrs Leong have at first? (b) How many new orange ping pong balls were used to replace the white ones?

        1 Reply Last reply Reply Quote 0
        • T Offline
          tianzhu
          last edited by

          zanen:
          Hi I'm Zan En's sister and would like to ask this qns on her behalf. Mrs Leong had white and orange ping pong balls in the ratio 7:5. She then replaced several white ping pong balls with orange ones keeping the total number of ping pong balls the same. The ratio of the number of white ping pong balls to orange ping pong balls became 3:5.

          (a) If the total number of ping pong balls is not more than 30, how many white ping pong balls did Mrs Leong have at first? (b) How many new orange ping pong balls were used to replace the white ones?
          Hi

          White:Orange ------ 7:5(12)------- 14:10 (24)

          White:Orange ------ 3:5(8) ------- 9:15(24)

          Number of white balls@first ------- 14

          Number of orangeballs@replacing white balls ------- 15-10 ------ 5

          Best wishes

          1 Reply Last reply Reply Quote 0
          • T Offline
            tianzhu
            last edited by

            Shimmer:
            One more question pls!


            Dean,Ellen and Andy shared a box of sweets in the ratio of 3:4:5 and there was 4 left .They put the 4 sweets into a second box which contained 1/8 fewer sweets than the first box, and shared the sweets in the same ratio as before,and this time there were no remainder.
            A)Find the total number of sweets they shared in the first round.
            B)Find the total number of sweets each child received in both rounds of sharing.
            Hi

            Where is this question from?

            What are the answers in the WS?

            I think there is a possibility of multiple answers.

            One set of possible answers

            a) 60 sweets

            b) 30,40,50

            Best wishes

            1 Reply Last reply Reply Quote 0
            • T Offline
              tianzhu
              last edited by

              Winx5015:

              1)There were a total of 800 paper clips in 3 containers, A, B and C.Alex transferred 3/8 of the paper clips from container A to container B.He then transferred 40 paper clips from container B to container C.As a result, the number of paper clips in container C is 1/5 the number of paper clips in container A There were 264 paper clips in container B at first. How many paper clips were there in container A at first?
              Hi

              It’s useful to draw a simple diagram to show the flow.

              After the transfer

              A ------- 5 units

              B ------- 224 + 3 units (40 transferred to C, hence 264-40 ----- 224, and 3 units received from A)

              C ------- 1 unit (1/5 the number of paper clips in container A)

              9 units + 224 ------- 800

              1unit ------- 64

              A ------- 8*64 -------- 512

              Best wishes

              1 Reply Last reply Reply Quote 0
              • S Offline
                Shimmer
                last edited by

                tianzhu:
                Shimmer:

                One more question pls!


                Dean,Ellen and Andy shared a box of sweets in the ratio of 3:4:5 and there was 4 left .They put the 4 sweets into a second box which contained 1/8 fewer sweets than the first box, and shared the sweets in the same ratio as before,and this time there were no remainder.
                A)Find the total number of sweets they shared in the first round.
                B)Find the total number of sweets each child received in both rounds of sharing.

                Hi

                Where is this question from?

                What are the answers in the WS?

                I think there is a possibility of multiple answers.

                One set of possible answers

                a) 60 sweets

                b) 120 sweets

                Best wishes[/quote

                This question was given by my TUTION teacher.
                Y

                1 Reply Last reply Reply Quote 0
                • A Offline
                  anneshirleygilbert
                  last edited by

                  Hi MathIzzzFun,


                  I really appreciate you staying up so late to help me with the question on the big and small beads. Thank you so much.

                  Anne

                  1 Reply Last reply Reply Quote 0
                  • MathIzzzFunM Offline
                    MathIzzzFun
                    last edited by

                    Shimmer:
                    One more question pls!


                    Dean,Ellen and Andy shared a box of sweets in the ratio of 3:4:5 and there was 4 left .They put the 4 sweets into a second box which contained 1/8 fewer sweets than the first box, and shared the sweets in the same ratio as before,and this time there were no remainder.
                    A)Find the total number of sweets they shared in the first round.
                    B)Find the total number of sweets each child received in both rounds of sharing.
                    This looks more like a MO question than a PSLE question.

                    3+4+5 =12
                    Number of sweets in 1st box, after removing 4 sweets = 12 units
                    Number of sweets in 2nd box, after adding 4 sweets = 12 parts
                    Number of sweets in 1st box : 2nd box
                    = 12 units + 4 : 12 parts - 4
                    = 8 :7

                    equalize: 84 units + 28 = 96 parts - 32
                    7 units + 5 = 8 parts
                    8 units - 8 parts = 1 unit - 5

                    smallest possible value of 1 unit --> 1 unit - 5 = 0
                    1 unit --> 5 (subsequent values : 13, 21, 29 ....)
                    1 part --> 5

                    a) Total number of sweets shared in first round (smallest number)
                    = 12 units = 12 x 5 = 60
                    b) Total number of sweets shared in both rounds = 12 units + 12 parts = 120
                    Dean --> 3/12 X 120 = 30 sweets
                    Ellen --> 4/12 x 120 = 40 sweets
                    Andy --> 5/12 x 120 = 50 sweets

                    Other possible answers:

                    http://i48.tinypic.com/2zrqlb8.png\">

                    cheers.

                    1 Reply Last reply Reply Quote 0
                    • S Offline
                      student101
                      last edited by

                      I tried different way to solve below problem for last couple of days. Pls help me as I feel very difficult to get the solution:


                      At a fitness carnival, 1600 people participated in a Mass dance & Taji. 30% of 1300 Mass dance participants were adults and 40% of Taji participants were children. During the break, some Mass dance participants went on to particiapte in Taji, while some Taji participants went on to particiapte in Mass dance. After the change, 25% of the mass dance participants and 75% of the Taji particiapants were adults. How many Mass dance participants were there after the change?

                      1 Reply Last reply Reply Quote 0
                      • A Offline
                        AceTutors123
                        last edited by

                        --- :scratchhead: ---

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