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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • P Offline
      PapayaDad
      last edited by

      Mr.Lee left town P at 6.45am? did u miss the P?


      Also the correct thread for these is here :

      http://www.kiasuparents.com/kiasu/forum/viewtopic.php?f=69&t=280&start=8950

      1 Reply Last reply Reply Quote 0
      • P Offline
        PapayaDad
        last edited by

        Mr Lee start 6.45 ; speed 60kmh

        At 10.15 (3.5h later) ; Mr Lee travel 60+60+60+30=210km already

        Mrs Chen took 3h (7.15 to 10.15) to travel 210km (catch up Mr Lee)
        Mrs Chen Speen is 70kmh.
        Mrs Chen need to travel another 350km to reach Q ie another 5h

        Another 5h, Lee travel 300km only…still 50km away…

        1 Reply Last reply Reply Quote 0
        • M Offline
          Musicstar
          last edited by

          Hi,


          Can someone enlighten me the below question with two types of method to solve the question but why different answer? Please advise the mistake. I suppose no matter which methods should also get the same answer. Thank you.

          A box contained some twenty-coins and some fifty-cent coins in the ratio 3:4. When 26 fifty-cent coins were taken out and replaced by the same number of twenty-cent coins, the ratio became 4:1. Find the sum of money in the box in the box at first.


          Working No 1
          Since the number of coins did not change, we make the total the same

          Before
          T : F
          3 : 4 (Total = 7u)
          15 : 20 (Total = 35u)

          After
          T : F
          4 : 1 (Total = 5u)
          28 : 7 (Total = 35u)

          13u = 26
          1u = 2

          15u of 20 cent = 15 x 2 x 0.2 = $6
          20u of 50 cent = 20 x 2 x 0.5 = $20

          Total = $26

          Working No 2
          Using units and parts
          20cents : 50cents
          3 units : 4 units
          +65 -26 x 4
          4 parts 1 part

          3u +65 = 4p
          16u -104 = 4p
          3u + 65 = 16u - 104
          16u - 3u = 65 + 104
          13u = 169
          u = 13
          3u = 13 x 3 = 39
          39 x $0.20 = $7.80
          4u = 13 x 4 = 52
          52 x $0.50 = $26
          $7.80 + $26. = $33.80

          1 Reply Last reply Reply Quote 0
          • O Offline
            Oldschool
            last edited by

            Musicstar:
            Hi,


            Can someone enlighten me the below question with two types of method to solve the question but why different answer? Please advise the mistake. I suppose no matter which methods should also get the same answer. Thank you.

            A box contained some twenty-coins and some fifty-cent coins in the ratio 3:4. When 26 fifty-cent coins were taken out and replaced by the same number of twenty-cent coins, the ratio became 4:1. Find the sum of money in the box in the box at first.


            Working No 1
            Since the number of coins did not change, we make the total the same

            Before
            T : F
            3 : 4 (Total = 7u)
            15 : 20 (Total = 35u)

            After
            T : F
            4 : 1 (Total = 5u)
            28 : 7 (Total = 35u)

            13u = 26
            1u = 2

            15u of 20 cent = 15 x 2 x 0.2 = $6
            20u of 50 cent = 20 x 2 x 0.5 = $20

            Total = $26

            Working No 2
            Using units and parts
            20cents : 50cents
            3 units : 4 units
            +65 -26 x 4
            4 parts 1 part

            3u +65 = 4p
            16u -104 = 4p
            3u + 65 = 16u - 104
            16u - 3u = 65 + 104
            13u = 169
            u = 13
            3u = 13 x 3 = 39
            39 x $0.20 = $7.80
            4u = 13 x 4 = 52
            52 x $0.50 = $26
            $7.80 + $26. = $33.80
            Hi,

            This is because in (b), instead of replaced with same number of coins, it is substituted with same amount of coins.

            i.e. 65x20cents= 26x50cents in amount


            But the question said \"same number\" though.

            Regards

            1 Reply Last reply Reply Quote 0
            • M Offline
              Musicstar
              last edited by

              Oldschool,


              Thank you for pointing out to me. I am really careless and did not read the question properly. The two words are really important. If don't have these two words \"the same\" which mean I need to change to the number of coin to the amount.

              Oldschool:
              Musicstar:

              Hi,

              Can someone enlighten me the below question with two types of method to solve the question but why different answer? Please advise the mistake. I suppose no matter which methods should also get the same answer. Thank you.

              A box contained some twenty-coins and some fifty-cent coins in the ratio 3:4. When 26 fifty-cent coins were taken out and replaced by the same number of twenty-cent coins, the ratio became 4:1. Find the sum of money in the box in the box at first.


              Working No 1
              Since the number of coins did not change, we make the total the same

              Before
              T : F
              3 : 4 (Total = 7u)
              15 : 20 (Total = 35u)

              After
              T : F
              4 : 1 (Total = 5u)
              28 : 7 (Total = 35u)

              13u = 26
              1u = 2

              15u of 20 cent = 15 x 2 x 0.2 = $6
              20u of 50 cent = 20 x 2 x 0.5 = $20

              Total = $26

              Working No 2
              Using units and parts
              20cents : 50cents
              3 units : 4 units
              +65 -26 x 4
              4 parts 1 part

              3u +65 = 4p
              16u -104 = 4p
              3u + 65 = 16u - 104
              16u - 3u = 65 + 104
              13u = 169
              u = 13
              3u = 13 x 3 = 39
              39 x $0.20 = $7.80
              4u = 13 x 4 = 52
              52 x $0.50 = $26
              $7.80 + $26. = $33.80

              Hi,

              This is because in (b), instead of replaced with same number of coins, it is substituted with same amount of coins.

              i.e. 65x20cents= 26x50cents in amount


              But the question said \"same number\" though.

              Regards

              1 Reply Last reply Reply Quote 0
              • R Offline
                rocklee
                last edited by

                Anyone can help?


                There were a total of 20800 toys in Factory A and Factory B. After 3/4 of toys in Factory A and 3/5 in Factory B were sold, there were 1040 more toys in B than A. How many toys were there in each factory at first?

                1 Reply Last reply Reply Quote 0
                • C Offline
                  CloudeeDaz
                  last edited by

                  rocklee:
                  Anyone can help?


                  There were a total of 20800 toys in Factory A and Factory B. After 3/4 of toys in Factory A and 3/5 in Factory B were sold, there were 1040 more toys in B than A. How many toys were there in each factory at first?
                  hihi
                  there is a solution http://www.kiasuparents.com/kiasu/forum/viewtopic.php?p=775568#p775568/ 😄

                  1 Reply Last reply Reply Quote 0
                  • C Offline
                    CloudeeDaz
                    last edited by

                    and http://www.kiasuparents.com/kiasu/forum/viewtopic.php?p=23793#p23793%20/

                    1 Reply Last reply Reply Quote 0
                    • M Offline
                      Musicstar
                      last edited by

                      Please help.Thank you


                      Q11) Sally , Yiling and Ali shared a bag of beads. Sally received 3/4 of the bag of beads and 3/4 of a bead. Yiling received 3/4 of the remaining bag of beads and 3/4 of a bead. Ali received the last bead in the bag. How many beads did Sally receive? (No bead was to be divided in any way)

                      Q17 ) Jane and Iris had 255 sweets altogether. Jane had 15 more sweets than Iris. Jane gave away 25% as many sweets as Iris. She was left with twice as many sweets as Iris.
                      (a) How many sweets did Iris give away?
                      (b) How many sweets did Jane have in the end?

                      1 Reply Last reply Reply Quote 0
                      • J Offline
                        jieheng
                        last edited by

                        Musicstar:
                        Please help.Thank you


                        Q11) Sally , Yiling and Ali shared a bag of beads. Sally received 3/4 of the bag of beads and 3/4 of a bead. Yiling received 3/4 of the remaining bag of beads and 3/4 of a bead. Ali received the last bead in the bag. How many beads did Sally receive? (No bead was to be divided in any way)
                        ............................................[---------------1u-------------]
                        [--------------------3u-------------------][3/4][------3p------][3/4][ 1]
                        ...................................................................[---1p--]

                        S [--------------------3u-------------------][3/4]
                        Y [------3p------][3/4]
                        A [ 1]

                        1p --> 1 + 3/4 = 7/4
                        4p --> 7

                        1u --> 3/4 + 4p = 3/4 + 7 = 31/4

                        Sally --> 3u + 3/4 = 3*(31/4) + 3/4 = 96/4 = 24

                        1 Reply Last reply Reply Quote 0

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