Q&A - PSLE Math
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Please help.Thank you
Q11) Sally , Yiling and Ali shared a bag of beads. Sally received 3/4 of the bag of beads and 3/4 of a bead. Yiling received 3/4 of the remaining bag of beads and 3/4 of a bead. Ali received the last bead in the bag. How many beads did Sally receive? (No bead was to be divided in any way)
Q17 ) Jane and Iris had 255 sweets altogether. Jane had 15 more sweets than Iris. Jane gave away 25% as many sweets as Iris. She was left with twice as many sweets as Iris.
(a) How many sweets did Iris give away?
(b) How many sweets did Jane have in the end? -
Musicstar:
............................................[---------------1u-------------]Please help.Thank you
Q11) Sally , Yiling and Ali shared a bag of beads. Sally received 3/4 of the bag of beads and 3/4 of a bead. Yiling received 3/4 of the remaining bag of beads and 3/4 of a bead. Ali received the last bead in the bag. How many beads did Sally receive? (No bead was to be divided in any way)
[--------------------3u-------------------][3/4][------3p------][3/4][ 1]
...................................................................[---1p--]
S [--------------------3u-------------------][3/4]
Y [------3p------][3/4]
A [ 1]
1p --> 1 + 3/4 = 7/4
4p --> 7
1u --> 3/4 + 4p = 3/4 + 7 = 31/4
Sally --> 3u + 3/4 = 3*(31/4) + 3/4 = 96/4 = 24 -
Musicstar:
J [-----------------][15]Please help.Thank you
Q17 ) Jane and Iris had 255 sweets altogether. Jane had 15 more sweets than Iris. Jane gave away 25% as many sweets as Iris. She was left with twice as many sweets as Iris.
(a) How many sweets did Iris give away?
(b) How many sweets did Jane have in the end?
I. [-----------------]
J [][---------------][15]
I. [][][][][---------]
J [][----][15][----][15]
I. [][][][][15][----]
J [][][][][15][][][][15] --> 7u + 30
I. [][][][][15][][][] --> 7u + 15
7u + 30 + 7u + 15 --> 255
14u --> 210
1u --> 15
a)
No of sweets that Iris gave away = 4u = 4*15 = 60
b)
No of sweets that Jane had in the end = 6u + 30 = 6*15 + 30 = 120 -
Hi,
Can someonehelp to explain to me my doubt. Why u= 2u -1040 , 4u = 4 (2u-1040 ) & 5u +8u -4160. Thank you very much.small:
Thanks again ks2me, you are great...ks2me:
![](\"http://i724.photobucket.com/albums/ww246/ks2me/P6MathRiceSacks-1.jpg\")
http://i724.photobucket.com/albums/ww246/ks2me/P6MathRiceSacks-1.jpg\">
No wonder I not able to get the answer due to my wrong calculation; 1920 x 5 = 9100.
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Musicstar:
[/quote]Hi,
Thanks again ks2me, you are great...
Can someonehelp to explain to me my doubt. Why u= 2u -1040 , 4u = 4 (2u-1040 ) & 5u +8u -4160. Thank you very much.small:
[quote=\"ks2me\"]
No wonder I not able to get the answer due to my wrong calculation; 1920 x 5 = 9100.
Hi,
There is a difference in the 2 \"u\".
One is small \"u\" and the other is big \"U\".
So, for clarity you can replace one of it with P and it will end up as UP method.
http://www.flickr.com/photos/94858125@N03/8662494378/in/photostream/
Hope this help.
Regards -
rocklee:
Toys unsold:Anyone can help?
There were a total of 20800 toys in Factory A and Factory B. After 3/4 of toys in Factory A and 3/5 in Factory B were sold, there were 1040 more toys in B than A. How many toys were there in each factory at first?
Factory A --> 2 units -- 1/4 of total
total in Factory A at first --> 8 units
Factory B --> 2 units + 1040 = 2 x ( 1 unit +520) --- 2/5 of total
total in Factory B at first = 5 x ( 1 unit + 520 ) = 5 units + 2600
At first, total number of toys:
13 units + 2600 = 20800
1 unit --> 1400
At first,
Factory A --> 11 200 toys
Factory B --> 9 600 toys
cheers. -
How to get 7u each? I do not understand.
jieheng:
J [-----------------][15]Musicstar:
Please help.Thank you
Q17 ) Jane and Iris had 255 sweets altogether. Jane had 15 more sweets than Iris. Jane gave away 25% as many sweets as Iris. She was left with twice as many sweets as Iris.
(a) How many sweets did Iris give away?
(b) How many sweets did Jane have in the end?
I. [-----------------]
J [][---------------][15]
I. [][][][][---------]
J [][----][15][----][15]
I. [][][][][15][----]
J [][][][][15][][][][15] --> 7u + 30
I. [][][][][15][][][] --> 7u + 15
7u + 30 + 7u + 15 --> 255
14u --> 210
1u --> 15
a)
No of sweets that Iris gave away = 4u = 4*15 = 60
b)
No of sweets that Jane had in the end = 6u + 30 = 6*15 + 30 = 120 -
How to get 7u each? I do not understand.
jieheng:
J [-----------------][15]Musicstar:
Please help.Thank you
Q17 ) Jane and Iris had 255 sweets altogether. Jane had 15 more sweets than Iris. Jane gave away 25% as many sweets as Iris. She was left with twice as many sweets as Iris.
(a) How many sweets did Iris give away?
(b) How many sweets did Jane have in the end?
I. [-----------------]
J [][---------------][15]
I. [][][][][---------]
J [][----][15][----][15]
I. [][][][][15][----]
J [][][][][15][][][][15] --> 7u + 30
I. [][][][][15][][][] --> 7u + 15
7u + 30 + 7u + 15 --> 255
14u --> 210
1u --> 15
a)
No of sweets that Iris gave away = 4u = 4*15 = 60
b)
No of sweets that Jane had in the end = 6u + 30 = 6*15 + 30 = 120 -
Musicstar:
At first,Please help.Thank you
Q17 ) Jane and Iris had 255 sweets altogether. Jane had 15 more sweets than Iris. Jane gave away 25% as many sweets as Iris. She was left with twice as many sweets as Iris.
(a) How many sweets did Iris give away?
(b) How many sweets did Jane have in the end?
Iris's sweets --> (255-15) / 2 = 120
Jane's sweets --> 120 + 15 = 135
In the end,
Number of sweets given away, Jane : Iris --> 1 unit : 4 units
Number of sweets left, Jane : Iris --> 2 parts : 1 part
Jane's sweets --> 1 unit + 2 parts = 135 --- (1)
Iris's sweets --> 4 units + 1 part = 120 ----- (2)
(2) x 2 --> 8 units + 2 parts = 240 ---- (3)
(3) - (1) --> 7 units = 105, 1 unit --> 15
1 part --> 120 - 4 x 15 = 60
Number of sweets given away by Iris --> 4 x 15 = 60
Number of sweets Jane had, in the end --> 2 x 60 = 120
cheers.
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