PSLE Maths 2012

[Mwf3]

The man and women qn(qn29 of booklet b), the answer is 44. Why not 28? Because if you take 110-28=82. 82 cannot be decided by 3(women), so 28 is wrong and the only possible answer is 44. I have checked and confirmed with my tutors.

[CrimsonSunset]

@Mwf3:


110 ppl in queue. According to question,
At least 3 women between 2 men. So, arrangement: M W W W / M W W W…

110 / 4= 27 R2

There is a remainder of 2 ppl, one of them is a man, the other a woman.
so ans is 28, no argument.

XD

Also, if you go about the method that you stated, 110-28=82
82-1=81
81/3= 27

So 28 is the answer.

*No offense, but ur mistake was bcos u did not take into account the remainder

[Haneyi]

Mwf3:

The man and women qn(qn29 of booklet b), the answer is 44. Why not 28? Because if you take 110-28=82. 82 cannot be decided by 3(women), so 28 is wrong and the only possible answer is 44. I have checked and confirmed with my tutors.

Hello, 28 is the correct answer. If you draw it out, you will see that if you use 44, there will be no women at all between some of the men, making it:

M W W W M M W W W M M W W W M

However, if you use 28, it will be like this:
M W W W M W W W M W W W

Hope this helps. ^^

[AIM]

[quote="Clairifina"]How on earth do you do the last question for paper 2?[/quote

Hey the Anwers is 20425 and 1700

[whywhy]

Hi Crimsonsunset

can u show the table method to do that killer 2009 question? thank u.

[whywhy]

one group MwwwMwww

13 groups x 8 = 104 people
+ another MwwwMw = 110 people
13 groups x 2 men = 26 men
26 + 2 = 28 men.
hope tis is correct.

[whywhy]

one group MwwwMwww

13 groups x 8 = 104 people
+ another MwwwMw = 110 people
13 groups x 2 men = 26 men
26 + 2 = 28 men.
hope tis is correct.

[CrimsonSunset]

@whywhy

e.g. Jim bought some chocolates and gave half to Ken. Ken bought some sweets and gave half to Jim. When Jim ate 12 sweets while Ken ate 18 chocolates, the ratio of Jim’s number of sweet to number of chocolate is 1: 7 while the ratio of Ken’s number of sweets to number of chocolate is 1: 4. How many sweets did Ken buy?


Let 1c be half the number of chocolates that Jim bought and 1s be half the number of sweets Ken bought.

Jim\t
Ratio of Choco:Sweets (At first)
1c : 1s\t
(At first)
1c : 1s
1c : 1s - 12
7 : 1 (In the end)

Ken
Ratio of Choco:Sweets \t
1c – 18 : 1s
4 : 1 (In the end)

Cross Multiply:
1c = 7s – 84

1c – 18 = 4s
-> 7s – 84 – 18 = 4s (Substitution)
-> 3s = 102
102/3 * 2= 68


Sorry, this is not as neat/simplistic as the real table mthod, but u get the idea.

[shengp]

Jankhan:

Im from the best class and yet there are some who left the quetions blank!

mine too! even the top scorer said that it was a tricky paper
:faint: :faint: :faint:

[weatherbee]

I heard that paper 1 is easy but paper 2 is difficult.