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    O-Level Additional Math

    Scheduled Pinned Locked Moved Secondary Schools - Academic Support
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    • A Offline
      ADoc
      last edited by

      Here’s a quick guide to understanding proportionality & solving formulating / solving proportion statements/equations (E Math Paper I)


      By definition, a proportion is a mathematical statement or equation stating that two ratios are equal, i.e. a/b = c/d

      But this is definition isn’t really useful at first glance to understand and solve proportionality.

      Let’s understand these first:

      (1) Direct Proportion
      when we say A is proportional to B, we mean as A increases, B increases as well, vice versa.

      Example: The more money I have, the more I-phone apps I can buy.

      (2) Inverse Proportion
      when we say A is inversely proportional to B, we mean as A increase, B decreases.
      Or, as A decreases, B increases.

      Example: The more time I spend playing on my I-phone, the lesser time I have for revision.

      Now that we have sorted out definitions (1) & (2), next is about the proportionality constant (usually denoted as k).

      Example:
      y is directly proportional to x,
      this means y ∝ x
      to formulate a proportion statement, we rewrite as y = kx
      Why is there a need for the proportionality constant k?
      We only know that as y increases, x increases, however we do not know the exact magnitude of increment (or decrease). The constant k is the unknown that will allow us to equate y to x. So now we can happily remove the ∝ symbol and replace it by =

      Example:
      if y is inversely proportional to x³
      we rewrite as y ∝ (1/x³). Convince yourself that as x increases, we are dividing by a larger number, hence y decreases. Thus an inverse proportional relationship.

      similarly, we can arbitrarily insert the constant k to formulate an equation such that, y = k(1/x³)

      Solving for K usually requires the question to provide a pair of values of x & y for example.

      Example:
      given that y = 2 when x = 4, and y is ∝ x
      y = kx –> 2 = k(4) –> k = 1/2

      given that y = 2 when x = 4, and y is ∝ 1/x
      y = k(1/x) –> 2 = k(1/2) –> 2 = k/2 –> k = 4 (cross-multiplication is a common technique for solving inverses)

      Hope these basics are useful. Cheers! There are many more variations and techniques, and styles of questions. I find it difficult to explain thru typing. Besides, the post will get incredibly long and boring! ha! Tks for the understanding.

      1 Reply Last reply Reply Quote 0
      • A Offline
        ADoc
        last edited by

        Just an add-on. The understanding of proportional is exceptionally useful for Physics (and other subjects of cos).


        For example, the all-time favourite of D-S-T.
        we know that D = S x T
        with a constant S, the longer the D, the more T is required.
        or, S = D / T, with a constant D, the longer T one takes to travel, it translate to a lower average S.

        Density = Mass / Volume

        For a constant M, the bigger the V, the lower the D, for example.

        Pressure = Force / Area
        The larger the A with a constant F, the lower the P.

        Essentially, students must learn to appreciate the physics formula in this manner to be effective and efficient in their learning.

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        • L Offline
          leeven
          last edited by

          Hi GuanHui


          how to find the lowest postive integer of x and X+1 . both divisible by 7

          1 Reply Last reply Reply Quote 0
          • B Offline
            blitz
            last edited by

            http://img.photobucket.com/albums/v257/tbctbc/DSC00960.jpg\">


            The upper part of a solid wooden right circular cone is cut off leaving the frustum shown in the diagram. The height of the original cone, VO is 18cm and the base radius, OA is 9cm.

            The radius, BC, of the base of the upper part is 6cm.

            Taking pi to be 3.142, calculate
            (a) the length of OC
            (b) the total surface ara of the frustum

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            • F Offline
              FrekiWang
              last edited by

              blitz:
              http://img.photobucket.com/albums/v257/tbctbc/DSC00960.jpg\">


              The upper part of a solid wooden right circular cone is cut off leaving the frustum shown in the diagram. The height of the original cone, VO is 18cm and the base radius, OA is 9cm.

              The radius, BC, of the base of the upper part is 6cm.

              Taking pi to be 3.142, calculate
              (a) the length of OC
              (b) the total surface ara of the frustum
              (a) Since VCB and VOA are similar, we have
              VC/VO=CB/OA
              VC/18=6/9
              solve, we get VC=12.
              OC=VO-VC=6cm

              (b) Curved surface area of a cone = pi x r x L
              VB = square root of (VC square + BC square) = 13.416
              VA = square root of (VO square + OA square) = 20.125
              Curved surface area of the frustum
              =curved surface area of larger cone - curved surface area of larger cone
              = 3.142 x 9 x 20.125 - 3.142 x 6 x 13.416
              = 316.18
              Upper base of the frustum
              = 3.142 x 6 x 6
              = 113.11
              Lower base of the frustum
              = 3.142 x 9 x 9
              = 254.50
              Total = 316.18+113.11+254.50 = 684cm^2 (correct to 3s.f.)

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              • F Offline
                FrekiWang
                last edited by

                leeven:
                Hi GuanHui


                how to find the lowest postive integer of x and X+1 . both divisible by 7
                It is not possible to have x and x+1 both divisible by 7, please check.

                1 Reply Last reply Reply Quote 0
                • B Offline
                  blitz
                  last edited by

                  FrekiWang:
                  blitz:

                  http://img.photobucket.com/albums/v257/tbctbc/DSC00960.jpg\">


                  The upper part of a solid wooden right circular cone is cut off leaving the frustum shown in the diagram. The height of the original cone, VO is 18cm and the base radius, OA is 9cm.

                  The radius, BC, of the base of the upper part is 6cm.

                  Taking pi to be 3.142, calculate
                  (a) the length of OC
                  (b) the total surface ara of the frustum

                  (a) Since VCB and VOA are similar, we have
                  VC/VO=CB/OA
                  VC/18=6/9
                  solve, we get VC=12.
                  OC=VO-VC=6cm

                  (b) Curved surface area of a cone = pi x r x L
                  VB = square root of (VC square + BC square) = 13.416
                  VA = square root of (VO square + OA square) = 20.125
                  Curved surface area of the frustum
                  =curved surface area of larger cone - curved surface area of larger cone
                  = 3.142 x 9 x 20.125 - 3.142 x 6 x 13.416
                  = 316.18
                  Upper base of the frustum
                  = 3.142 x 6 x 6
                  = 113.11
                  Lower base of the frustum
                  = 3.142 x 9 x 9
                  = 254.50
                  Total = 316.18+113.11+254.50 = 684cm^2 (correct to 3s.f.)

                  Thanks so much! But I dont understand how to prove that the triangles are similiar

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                  • S Offline
                    suiyuan
                    last edited by

                    Hi


                    Please help.

                    Thank you

                    Secondary Two Maths.

                    Factorise

                    1) -6x^2 + x + 1

                    2) -5x^2 + 63x - 36

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                    • J Offline
                      jieheng
                      last edited by

                      suiyuan:
                      Hi


                      Please help.

                      Thank you

                      Secondary Two Maths.

                      Factorise

                      1) -6x^2 + x + 1

                      2) -5x^2 + 63x - 36

                      1) -6x^2 + x + 1 = (3x+1)(-2x+1)

                      2) -5x^2 + 63x - 36 = (5x-3)(-x+12)

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                      • K Offline
                        kittybank
                        last edited by

                        Hi Guan Hui,


                        Could you help solve this?

                        Solve the pair of simultaneous equation for the values of x and y.
                        xy=1/3
                        xy+x-y=1/2

                        Ans: x=-1/2, y= -2/3 or x=2/3, y=1/2

                        Thanks a million!

                        1 Reply Last reply Reply Quote 0

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