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    O-Level Additional Math

    Scheduled Pinned Locked Moved Secondary Schools - Academic Support
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    • E Offline
      Eddow
      last edited by

      Haha x^ab times y^ab will not give you x^2ab mah..


      (x^ab-9)(y^ab+9)= (x^ab)(y^ab) - (9)(y^ab) + (9)(x^ab) -(9)(9)

      =(xy)^ab -9(y^ab) +9(x^ab) - 81[/quote]

      oh.. you're assuming +9(x^ab) - 81. And I'm assuming -9(x^ab) +81, that's why ans diff.

      It's just printing error in the original question. šŸ˜‚

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      • E Offline
        Eddow
        last edited by

        bigmac:
        Here is the question:


        Find the smallest number which when divided by 24 and 36 leaves a remainder of 11.

        Solution given by the book:
        LCM: 2X2X2X3X3
        =8X9=72

        Thus, require number = 72 + 11 = 83

        Can explain to me why need to add the 11.

        Thanks alot.
        .

        Because there is a remainder of 11.
        If you only find the LCM of 24 and 36, you will get the 72.

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        • E Offline
          Eddow
          last edited by

          carebear:
          How to do 3+4+5+6.....+200


          and 10+12+14+16+.....+400?

          TIA.
          :oops:
          First, find how many number are there from 3 to 200 (both inclusive)
          (200-3) + 1 = 198 numbers.

          flip the sentence to become 200+199+198+...+4+3
          Add this new sentence to the question, you'll get 203+203+203+...+203

          198 x 203 = 40194
          40194 /2 = 20097 (have to divide cos you've made a duplicate)

          For the next question , same way of doing, try it.
          but to find how many numbers there are :
          (400-10)/2 + 1 = 196 numbers
          (reason why divide by 2 is you are skipping 1 number in between)

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          • J Offline
            JadeDry
            last edited by

            Eddow:
            mum_sugoku:

            [quote=\"JadeDry\"]@ Eddow & Pinkapple


            I checked the question, it still is: 9(x to the power of ab) - ((xy) to the power of ab) - 9(y to the power of ab) - 81

            I would appreciate more help if you do not mind.

            Which is the simplest form?:

            (4X- 8Y) or 4(X-2Y)

            And why?

            Thanks in advance.

            If question is .... \"+\" ((xy) to the power of ab).... instead of \"-\", then solution is (x^ab -9) (y^ab +9)..

            I suspect printing error in the question. If it's ....+81, then answer should be (x^ab +9) (9 - y^ab)

            For question like this...Which is the simplest form?:
            (4X- 8Y) or 4(X-2Y) .
            If the question is asking you to FACTORISE, then correct ans is 4(x-2y).[/quote]If I am asked to simplify is the correct answer also 4(X-2y)?

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            • E Offline
              Eddow
              last edited by

              JadeDry:

              If I am asked to simplify is the correct answer also 4(X-2y)?
              This is factorise form already. Can I have the question ? If the question has brackets and ask you to simplfy, then you have to expand all and the ans should be 4x-8y.

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              • P Offline
                pinkapple
                last edited by

                yup.

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                • M Offline
                  mum_sugoku
                  last edited by

                  Eddow:
                  oh.. you're assuming +9(x^ab) - 81. And I'm assuming -9(x^ab) +81, that's why ans diff.


                  It's just printing error in the original question. šŸ˜‚
                  Agree with you - I also tried a few \"+\" & \"-\" combinations, but none can give answer that matches the question exactly :scratchhead:

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                  • W Offline
                    wkong
                    last edited by

                    Hi I have two questions from my son:


                    1. Find the smallest whole number that is not a factor of 12345…31

                    2. Find the largest prime number that divides this number

                    1
                    23…59+123*4…*60

                    Thank you in advance.

                    1 Reply Last reply Reply Quote 0
                    • F Offline
                      FrekiWang
                      last edited by

                      wkong:
                      Hi I have two questions from my son:


                      1. Find the smallest whole number that is not a factor of 1*2*3*4*5......*31

                      2. Find the largest prime number that divides this number

                      1*2*3....*59+1*2*3*4.....*60

                      Thank you in advance.
                      1. 37
                      2. 61

                      I have to say that your son's trainer (most probably maths olympiad) is a failure >_< as these are very simple questions at competition level.

                      1 Reply Last reply Reply Quote 0
                      • W Offline
                        wkong
                        last edited by

                        FrekiWang:
                        wkong:

                        Hi I have two questions from my son:


                        1. Find the smallest whole number that is not a factor of 1*2*3*4*5......*31

                        2. Find the largest prime number that divides this number

                        1*2*3....*59+1*2*3*4.....*60

                        Thank you in advance.

                        1. 37
                        2. 61

                        I have to say that your son's trainer (most probably maths olympiad) is a failure >_< as these are very simple questions at competition level.

                        Thanks Freki for your help. My DS wasn't trained for maths olympiad. This is part of his sch maths homework given by his sch teacher.

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