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    Tutor MathsGuru: Ask me for your burning Maths questions!

    Scheduled Pinned Locked Moved Primary Schools - Academic Support
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    • J Offline
      jieheng
      last edited by

      lazy me:
      Hi math guru,

      Pls help me with this question:

      There were 450 plastic chairs n metal chairs at a furniture store. After 60% of the plastic chairs n 1/6 of the metal chairs were sold, the total number of chairs left was 232. How many plastic chairs were sold?
      ---------at a store--------sold---------left
      PC---------5u--------------3u------------2u
      MC---------6p--------------1p-----------5p
      Total-----450-------------218----------232

      1p + 3u --> 218
      6*(1p + 3u) --> 6*218
      6p + 18u --> 1308
      6p + 5u + 13u --> 1308
      450 + 13u --> 1308
      13u --> 858
      1u --> 66

      Number of plastic chairs were sold = 3u = 3*66 = 198

      1 Reply Last reply Reply Quote 0
      • N Offline
        nnchia
        last edited by

        Hi, need help on this question:-


        Mrs. Tan bought 4 times as many toy guns as teddy bears. She spent $1750 altogether. A toy gun cost $10 less than a teddy bear. The total cost of toy guns was $490 more than the total cost of teddy bears.
        (a) How much did Mrs. Tan spend on the teddy bears?
        (b) How much did on teddy bear cost?

        (Answer: (a) - $630, (b) - $18)

        I could solve this via algebra but very lengthy so looking for a simpler solution! Thanks!

        1 Reply Last reply Reply Quote 0
        • J Offline
          jieheng
          last edited by

          nnchia:
          Hi, need help on this question:-


          Mrs. Tan bought 4 times as many toy guns as teddy bears. She spent $1750 altogether. A toy gun cost $10 less than a teddy bear. The total cost of toy guns was $490 more than the total cost of teddy bears.
          (a) How much did Mrs. Tan spend on the teddy bears?
          (b) How much did on teddy bear cost?

          (Answer: (a) - $630, (b) - $18)

          I could solve this via algebra but very lengthy so looking for a simpler solution! Thanks!
          toy guns 4u
          teddy bears 1u

          total cost of teddy bears (1u) = (1750 - 490) / 2 = 630

          a) the amount of money that Mrs. Tan spend on the teddy bears is $630

          total cost of toy guns (4u) = 630 + 490 = 1120

          the cost of toy guns (1u) = 1120 / 4 = 280

          Difference between the cost of 1u of teddy bears and toy guns
          =630 - 280
          =350

          Given the difference between the cost of 1 pc of teddy bear and toy gun
          =10

          No of teddy bears = 350 / 10 = 35

          the cost of one teddy bear = 630 / 35 = 18

          b) the cost of one teddy bear is $18

          1 Reply Last reply Reply Quote 0
          • N Offline
            nnchia
            last edited by

            Thank you so much for your reply!

            1 Reply Last reply Reply Quote 0
            • L Offline
              lazy me
              last edited by

              Tq jieheng for ur help!

              1 Reply Last reply Reply Quote 0
              • H Offline
                Herbie
                last edited by

                Hi! I need help in this qn.


                In how many years will a sum double itself at 7.5% simple interest?
                Tq

                1 Reply Last reply Reply Quote 0
                • H Offline
                  Herbie
                  last edited by

                  Hi! I need help in this qn.


                  In how many years will a sum double itself at 7.5% simple interest?
                  Tq

                  1 Reply Last reply Reply Quote 0
                  • nhps2012N Offline
                    nhps2012
                    last edited by

                    Can someone help me to solve this question? TIA


                    What is the maximum number of cylinders of height 6cm and diameter 4cm be placed into a box measures 21cm by 6cm by 12cm.

                    :thankyou:

                    1 Reply Last reply Reply Quote 0
                    • J Offline
                      jieheng
                      last edited by

                      Herbie:
                      Hi! I need help in this qn.


                      In how many years will a sum double itself at 7.5% simple interest?
                      Tq
                      Amount = Principal + Interest

                      A = P + I
                      = P + (PRT)/100
                      = P ( 1 + R%*T)

                      When a sum double itself , A = 2P

                      2P = P ( 1 + 7.5%*T)

                      2 = 1 + 7.5%*T

                      T = 13 1/3 years = 13 years 4 months

                      1 Reply Last reply Reply Quote 0
                      • N Offline
                        nnchia
                        last edited by

                        http://i43.tinypic.com/2e4vi1v.jpg\">

                        Hi, need help on this question. Thanks!

                        1 Reply Last reply Reply Quote 0

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