Q&A - PSLE Math

[suiyuan]

Thank you for your time.


1) Tom’s monthly allowance is $42 more than Eric’s. Eric spends $54 more than Tom every month. Eric’s savings is 1/2 of Tom’s savings. If Tom spends 3/7 of his allowance every month, what is his allowance for the entire year?

2) Siti paid $8.56 for some 26-cents, 30-cents and 50-cent stamps. She bought 4 more 30-cents stamps than 50-cent stamps. There were twice as many 26-cent stamps as 30-cent stamps. How many 26-cent stamps did she buy?

3) Terry walks to school at an average speed of 4km/h every day. One day, after walking a distance of 1km, he realised that his watch was slow. So, he ran at a constant speed and managed to reach the school just on time. Later, he calculated that if he had run at this speed right from the start of the journey, he would have reached school 5 minutes earlier. What was his running speed?

[Vanilla Cake]

Hi suiyuan,

Are these P5 or P6 qns ?

A1 : $ 4032 (Tom's allowance for the entire year)
A2 : 16 each of 26-cent stamps
A3 : 6 km/h (Terry's running speed)

Pls confirm if my answers are correct ?

[suiyuan]

Vanilla Cake:

Hi suiyuan,

Are these P5 or P6 qns ?

A1 : $ 4032 (Tom's allowance for the entire year)
A2 : 16 each of 26-cent stamps
A3 : 6 km/h (Terry's running speed)

Pls confirm if my answers are correct ?

Hi Vanilla Cake

Thank you for your reply.
P6 questions
No answers were given for Q1 and 2
As for Q3, you are correct.

Please share your detailed solutions for these questions.

[corneyAmber]

Hv time for Q1 and Q2 first:


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http://i3.photobucket.com/albums/y74/miamia2004/P6MathStamps-1.jpg\">

[lizawa]

suiyuan:

Thank you for your time.



3) Terry walks to school at an average speed of 4km/h every day. One day, after walking a distance of 1km, he realised that his watch was slow. So, he ran at a constant speed and managed to reach the school just on time. Later, he calculated that if he had run at this speed right from the start of the journey, he would have reached school 5 minutes earlier. What was his running speed?

Time taken to walk 1km = 1/4 hr
Let the constant speed he ran be y km/h, remaining distance be x km
Time taken = x/y hr
Total time taken = (x/y + 1/4)hr

If he runs at this speed from beginning, time taken = (x+1) / y hr. This is 1/12 hr (or 5 min) faster.

(x+1) / y = (x/y+1/4) - 1/12
Solve this equation, the \"x\" will be eliminated and
y = 6km/h

[clover18]

Does anyone have feedback on Math program by Andrew Er or Learning Lab?

[AnnT2009]

[Moderator's note: Topics merged.]


Hi,
I chanced upon this website recently. Need help to solve this question,

Amy took 3 hours to travel from Town P to Town Q. Pansy took 2 hours to travel from Town Q to Town P. Both of them started travelling at 9am. At what time did they pass each other?

Thanks and happy new year.

[csc]

AnnT2009:

Hi,

I chanced upon this website recently. Need help to solve this question,

Amy took 3 hours to travel from Town P to Town Q. Pansy took 2 hours to travel from Town Q to Town P. Both of them started travelling at 9am. At what time did they pass each other?

Thanks and happy new year.

Let me try.

In 1 hour, Amy covered 1/3 of distance.
In 1 hour , Pansy covered 1/2 of distance

In 1 hour both covered 1/3 + 1/2 = 5/6 of distance

5/6 of distance ====== 1 hour
6/6 of distance ====== 1 1/5 hour = 1 hour 12 minutes

Therefore , they passed each other at 10.12 am.

Hope I'm right.

[AnnT2009]

Hi csc,


Your answer is the same as the assessment book.
A little confused, why your calculation is based on 6/6?
How to explain to kid?
Thanks for enlightening a rusty mind.

Thanks.

[csc]

As Amy and Pansy are travelling in the opposite direction, when they meet, they would have covered the total distance from P to Q. That explain the 6/6 - whole distance.


Hope it helps.