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    O-Level Chemistry

    Scheduled Pinned Locked Moved Secondary Schools - Academic Support
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    • Z Offline
      Zhou.012490s Studio
      last edited by

      Hi another question to attempt:


      A liquid is to be electrolysed and two test tubes full of the liquid are placed over carbon electrodes. The diagram below shows the apparatus after a current has passed for some time.

      http://i57.tinypic.com/2ikccx1.jpg\">

      Which one of the following could be the liquid undergoing electrolysis?

      A. concentrated aqueous copper (II) sulfate
      B. concentrated aqueous sodium chloride
      C. an aqueous solution of sugar
      D. dilute hydrochloric acid

      (p/s: look carefully on the volume displaced by gasses in both test tubes)


      :? :idea:

      1 Reply Last reply Reply Quote 0
      • Z Offline
        Zhou.012490s Studio
        last edited by

        Another question to attempt:


        The equation for the reductino of iron ore in the blast furnace is:

        Fe2O3 (s) + 3CO2 --------> 2Fe (l) + 3CO2 (g)

        When 40 tonnes of the iron ore were reduced, 14 tonnes of molten iron were produced. What is the percentage of this reduction?

        _____

        We enter to learn, leave to achieve. Happy trying!

        1 Reply Last reply Reply Quote 0
        • Z Offline
          Zhou.012490s Studio
          last edited by

          Zhou's Studio:
          Hi another question to attempt:


          A liquid is to be electrolysed and two test tubes full of the liquid are placed over carbon electrodes. The diagram below shows the apparatus after a current has passed for some time.

          http://i57.tinypic.com/2ikccx1.jpg\">

          Which one of the following could be the liquid undergoing electrolysis?

          A. concentrated aqueous copper (II) sulfate
          B. concentrated aqueous sodium chloride
          C. an aqueous solution of sugar
          D. dilute hydrochloric acid


          Hi hi the above answer is D.

          To differentiate the answers, look for the hints concentrated and dilute as both types of solution will yield different products at anode and cathode. If is concentrated sodium chloride, Cl2 gas will be discharged at anode and not Oxygen gas.
          writing half equation:
          Anode: 2Cl- ----> Cl2 +2e
          Cathode: 2H+ + 2e. ------> H2

          So 1 mole of chlorine gas release will also release 2 electrons and hence 1 mole of hydrogen gas. Hence this is not the answer as the test tube of anode and cathode has the gas liberated at 1:2

          For option A, copper will deposited on the anode and not gas, this is because copper is preferable discharged compared to H+.

          For option D, because it is dilute HCL, the half equation will be:

          Anode: 4OH- ------> 2H2O + O2 + 4e
          Cathode: 2H+ + 2e -------> H2

          As 4e releases for 1 mole of O2, (hypothetically) 2 mole of H2 gas will be released. Both gases are not soluble, hence this explains the volume of gas collected in anode and cathode is 1:2.


          For this question, students has to be aware on the difference of dilute and concentrated ions affect the yields. Also the preferential discharge nature of both cations and anions. Lastly stoichiometry. But very important is read the questions and the diagram carefully. Analyze and think through step by step. šŸ˜‚ :rahrah:

          Lastly And most importantly, practise and practise!






          (p/s: look carefully on the volume displaced by gasses in both test tubes)


          :? :idea:

          1 Reply Last reply Reply Quote 0
          • Z Offline
            Zhou.012490s Studio
            last edited by

            Zhou's Studio:
            Another question to attempt:


            The equation for the reductino of iron ore in the blast furnace is:

            Fe2O3 (s) + 3CO2 --------> 2Fe (l) + 3CO2 (g)

            When 40 tonnes of the iron ore were reduced, 14 tonnes of molten iron were produced. What is the percentage yield of this reduction?

            _____

            We enter to learn, leave to achieve. Happy trying!

            Here is the answer:

            1. Read the question carefully, what is the question asking?
            YES, it means what is the percentage of recovery of Iron (Fe) from iron ore.

            2. What should we do?
            Calculate the mass of Fe in iron ore first.

            Mass percentage of Fe in iron ore = Mr of Fe / Total Mr of Fe2O3
            = 56 x2 / (56x2)+(16x3)

            = 0.70 x 100% = 70%
            Mass of Fe in Iron ore = 0.7 x 40 tonnes

            = 28 tonnes

            3. Now calculate the percent yield = mass of product / mass of reactants

            therefore, percentage yield will be = 14 tonnes / 28 tonnes
            = 0.5 x 100% = 50%


            Hope you all understand it.

            1 Reply Last reply Reply Quote 0
            • P Offline
              PurelyChemistry
              last edited by

              Need help with O level Chemistry?

              Send me a text at 82620671 to join WA chatgroup for Q&A for Chemistry.

              1 Reply Last reply Reply Quote 0
              • zbearZ Offline
                zbear
                last edited by

                PSLEmom:
                Any holiday lessons for Sec 4 / O level batch of 2015 at any of the tuition centres?


                PSLEmom, is it time to change your name to Olevelmum???? šŸ˜‰

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                • M Offline
                  Misaka
                  last edited by

                  Hi, may i know if anyone has the suggested answer scheme for O Level Chemistry MCQ 2014? My answers are as follows,


                  1-10 : CAABAACDDB

                  11-20 : DDBADABCCC

                  21-30 : CDCDCABCAC

                  31-40 : BBBBDBCBDD

                  1 Reply Last reply Reply Quote 0
                  • K Offline
                    KSP2013777
                    last edited by

                    Somebody can help me to know my understanding correct or not?


                    Question - Is the number of atoms in 0.5 mol of oxygen gas and 0.5 mol of iron the same?

                    I think answer is not correct because Oxygen gas is made up of molecules (O2)

                    That means, 0.5 mol of oxygen gas have 0.5 x 2 x 6 x 10^23 = 6 x 10^23 oxygen atoms.

                    But, 0.5 mol of iron have 0.5 x 6 x 10^23 = 3 x 10^23 iron atoms.

                    So, answer is no, am I right? pls ans when u hv time.

                    1 Reply Last reply Reply Quote 0
                    • S Offline
                      soseducation
                      last edited by

                      KSP2013777:
                      Somebody can help me to know my understanding correct or not?


                      Question - Is the number of atoms in 0.5 mol of oxygen gas and 0.5 mol of iron the same?

                      I think answer is not correct because Oxygen gas is made up of molecules (O2)

                      That means, 0.5 mol of oxygen gas have 0.5 x 2 x 6 x 10^23 = 6 x 10^23 oxygen atoms.

                      But, 0.5 mol of iron have 0.5 x 6 x 10^23 = 3 x 10^23 iron atoms.

                      So, answer is no, am I right? pls ans when u hv time.

                      Yes, you are right. The key word in the question is ATOMS. not molecules not ions. Oxygen itself is made up of two atoms since it is diatomic and you have to take that into consideration. šŸ˜„

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                      • K Offline
                        KSP2013777
                        last edited by

                        soseducation, thanks. I so scared my answer is wrong

                        1 Reply Last reply Reply Quote 0

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