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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • T
      tianzhu
      last edited by

      Q1)3675m is the correct answer.


      Best wishes

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      • L
        lizawa
        last edited by

        tianzhu:
        Maths Questions from http://www.channelnewsasia.com/discussion/forum.htm


        3. A group of people met at a party. Each person shook hands with everyone else. Mr Li shook hands with 3 times as many men as women. Mrs Li shook hands with 4 times as many men as women. How many men and how many women were there at the party?
        Answer : no. of men = 16; no. of women = 5

        See working :

        http://www.postimage.org/image.php?v=gx2w0utS

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        • S
          suiyuan
          last edited by

          Q47

          Please help to establish the number pattern for Q47 in this link.
          http://www.wendykoh.com/08/primary6-aitongca1-maths.pdf

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          • L
            lizawa
            last edited by

            suiyuan:
            Q47

            Please help to establish the number pattern for Q47 in this link.
            http://www.wendykoh.com/08/primary6-aitongca1-maths.pdf
            Stage Squares
            1 ===> 1
            2 ===> square (2+1) - (1*4) = 5
            3 ===> square (3+2) - ((2+1) *4) = 13
            4 ===> square (4+3) - ((3+2+1)*4) = 25
            5 ====> square (5+4) - ((4+3+2+1)*4) = 41
            10 ===> square (10+9) - ((9+8+7+6+5+4+3+2+1) *4) = 181
            100 ==> square (100+99) - ((99+98+97+...+1)*4) = 19801

            nth stage == > square (n+(n-1)) - ((sum of (n-1, n-2, n-3....1)*4)

            So you take the area of the whole figure at each stage- (no of squares cut of each edge * 4 edges).

            to solve 99+98+...1 at primary level, no need to teach AP/GP,
            just re-arrange 1+2+.. 99 and place them under 99+98... +1
            So you get 1 term as (99+1), (98+2) etc. ie. each term is 100. Total 99 terms. So sum = (100*99) / 2

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            • A
              ApronMama
              last edited by

              suiyuan:
              Q47

              Please help to establish the number pattern for Q47 in this link.
              http://www.wendykoh.com/08/primary6-aitongca1-maths.pdf
              How about this series ? Answer same as Lizawa's

              Stage Squares
              1 ===> 1
              2 ===> 1+4(2-1) = 5
              3 ===> 1+4(2-1)+4(3-1) = 13
              4 ===> 1+4(2-1)+4(3-1)+4(4-1)=25
              5 ===> 1+4(2-1)+4(3-1)+4(4-1)+4(5-1)=41
              .
              .
              10 ===>1+4(2-1)+4(3-1)+4(4-1)+4(5-1)+...+4(9-1)=181
              .
              .
              nth ===>1+4(2-1)+....+4(n-1)

              if n=100, we get
              100 ===>1+4(2-1)+....+4(100-1)
              =1+4*1+4*2+...+4*99
              =1+4(1+2+....+99)
              =1+4(4950)
              =19801
              { to do 1+2+3+...+99 same as Lizawa's method to pair up (1+99), (2+98),... you get 49*pairs of 100 +50 = 4950}

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              • L
                lizawa
                last edited by

                Hi Apronmama,


                Maybe yours is an easier method. I assume calculator can be used. But just realized that last year’s P6 still no calculator allowed.

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                • T
                  tianzhu
                  last edited by

                  Thank You for your help.


                  What is the number pattern for Q46 of this link?
                  http://www.wendykoh.com/08/primary6-aitongsa1-maths.pdf

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                  • S
                    sms
                    last edited by

                    tianzhu:
                    Thank You for your help.


                    What is the number pattern for Q46 of this link?
                    http://www.wendykoh.com/08/primary6-aitongsa1-maths.pdf
                    Is the answer 35?.

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                    • T
                      tianzhu
                      last edited by

                      Another look at Q3


                      http://farm4.static.flickr.com/3268/3211341130_6bb582e540_o.jpg\">

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                      • T
                        tianzhu
                        last edited by

                        AnnT2009:
                        Hi csc,


                        Sorry! Still confused, don't they meet somewhere in the middle of the journey.

                        Thanks for your patience.
                        Hi, hope this helps.

                        http://farm4.static.flickr.com/3379/3222658500_6fe616c3ee_o.jpg\">

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