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    Tutor MathsGuru: Ask me for your burning Maths questions!

    Scheduled Pinned Locked Moved Primary Schools - Academic Support
    4.3k Posts 374 Posters 1.6m Views 1 Watching
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    • S Offline
      speedmaths.012624com
      last edited by

      Vanilla Cake:
      Hi Mathsguru,

      Pls help my P5 younger sister to solve this 4-mark question from http://www.orlesson.org/orp/09Ma/2009-Math-SA1-ACS.pdf using models. Thank you.

      The volume of water in bottle P was 3/5 of that in bottle Q. After 60 ml of water was added to bottle P and 20 ml was poured away from bottle Q, the amount of water in bottle P was 3/4 that in bottle Q. What was the amount in each bottle at first?

      Other than models, what are your recommended method/s to tackle such problem sum?
      Hi Vanilla Cake,

      The volume of water in bottle P was 3/5 of that in bottle Q.
      After 60 ml of water was added to bottle P and 20 ml was poured away from bottle Q, the amount of water in bottle P was 3/4 that in bottle Q.
      What was the amount in each bottle at first?

      Let’s CHANGE the question (but still using the SAME numbers) to:

      In a shop, the ratio of the number of apples to the number of oranges was 3:5, at first.
      The shopkeeper bought 60 more apples, and sold 20 oranges.
      As a result, the ratio of the number of apples to the number of oranges became 3:4.
      How many apples and how many oranges, were there in the shop at first?

      This is a typical Double-Ratio Question, quite common in the PSLE.

      Using the Bags and Boxes Method (which can solve ALL such Double-Ratio Questions):
      (Once you are familiar with the method, you can cut down some of the steps below)


      At first, the apples / oranges were kept in Bags.
      Each Bag contains the same number of apples / oranges.
      There were 3 Bags of apples, and 5 Bags of oranges, at first.

      After 60 apples were added, and 20 oranges were removed,
      the apples / oranges were then kept in Boxes.
      Each Box contains the same number of apples / oranges.
      There were 3 Boxes of apples, and 4 Boxes of oranges.

      Apples:
      3 bags + 60 apples = 3 Boxes
      (x 4)
      12 bags + 240 apples = 12 Boxes

      Oranges:
      5 bags – 20 oranges = 4 Boxes
      (x 3)
      15 bags – 60 oranges = 12 Boxes

      12 Boxes = 12 bags + 240 apples = 15 bags – 60 oranges
      12 bags + 240 apples = 15 bags – 60 oranges
      0 bags + 240 apples = 3 bags – 60 oranges
      240 apples = 3 bags – 60 oranges
      300 apples / oranges = 3 bags
      1 Bag = 100 apples / oranges
      There were 3 Bags of apples, and 5 Bags of oranges, at first.

      There were 300 apples, and 500 oranges, at first. (ANSWER)

      1 Reply Last reply Reply Quote 0
      • D Offline
        Dharma
        last edited by

        Vanilla Cake:
        Hi Mathsguru,

        Pls help my P5 younger sister to solve this 4-mark question from http://www.orlesson.org/orp/09Ma/2009-Math-SA1-ACS.pdf using models. Thank you.

        The volume of water in bottle P was 3/5 of that in bottle Q. After 60 ml of water was added to bottle P and 20 ml was poured away from bottle Q, the amount of water in bottle P was 3/4 that in bottle Q. What was the amount in each bottle at first?

        Other than models, what are your recommended method/s to tackle such problem sum?
        Hi Vanilla Cake,

        Your sister may wish to look at this while waiting for Mathsguru’s solution.


        http://www.postimage.org/image.php?v=gxEDrbJ

        1 Reply Last reply Reply Quote 0
        • O Offline
          OK Lor
          last edited by

          Hi Mathsguru,


          The product of two numbers, A and B, is 108. The difference betweeen A and B is a common factor of A and B. Find the values of A and B.

          Thanks.

          1 Reply Last reply Reply Quote 0
          • D Offline
            Dharma
            last edited by

            OK Lor:
            Hi Mathsguru,


            The product of two numbers, A and B, is 108. The difference betweeen A and B is a common factor of A and B. Find the values of A and B.

            Thanks.
            108 = 2 X 2 X 3 X 3 X 3 = 12 X 9
            A = 12, B = 9 (A – B = 12- 9 = 3)
            3 is a common factor of both 12 and 9.

            1 Reply Last reply Reply Quote 0
            • H Offline
              Herbie
              last edited by

              Hi, Maths Guru and all


              Can help to solve the qn below?

              Amy and Tommy each have some money. If Amy spends $50 per day and Tommy spends $60 per day, Amy would still have $500 left when Tommy has spent all his money.
              If Amy spends $60 per day and Tommy spends $50 per day, Amy would still have $280 left when Tommy spent al his money. How much money does Tommy have?

              Tx

              1 Reply Last reply Reply Quote 0
              • C Offline
                ck123
                last edited by

                Hi all


                I need help with the model for this question.

                The number of marbles in Box A, Box B and Box C was 195.
                John added 60 marbles to those in Box A, doubled the number of marbles in Box B and halved the number of marbles in Box C.
                The ratio of the number of marbles becomes 4:1:2.
                What is the total number of marbles in the three boxes now?

                Thanks

                1 Reply Last reply Reply Quote 0
                • V Offline
                  Vanilla Cake
                  last edited by

                  Herbie:
                  Amy and Tommy each have some money. If Amy spends $50 per day and Tommy spends $60 per day, Amy would still have $500 left when Tommy has spent all his money.

                  If Amy spends $60 per day and Tommy spends $50 per day, Amy would still have $280 left when Tommy spent al his money. How much money does Tommy have?
                  Hi Herbie,
                  Your question is similar to this http://www.postimage.org/image.php?v=gxtwwpi which Mathsguru had provided clear explanations.

                  1st case
                  Amy : Tommy
                  5 : 6
                  25 : 30

                  2nd case
                  Amy : Tommy
                  6 : 5
                  36 : 30

                  Draw models for better visualisation,
                  1st case
                  Amy: 25 units + a long block to indicate $500 left
                  Tommy : 30 units

                  2nd case
                  Amy: 36 units + a long block to indicate $280 left
                  Tommy: 30 units

                  Make sure that total length of both blocks for Amy in 1st/2nd case must be the same.

                  25 units+$500=36 units+$280
                  11 units = $220
                  1 unit = $20

                  Tommy has 30 units = $600

                  Check
                  1st case - 10 days
                  Amy -> $1000-(10x$50) = $500
                  Tommy=> $600-(10x60) = 0

                  2nd case - 12 days
                  Amy -> $1000-(12x60) = $280
                  Tommy -> $600-(12x50) = 0

                  1 Reply Last reply Reply Quote 0
                  • V Offline
                    Vanilla Cake
                    last edited by

                    Dharma:
                    Hi Vanilla Cake,


                    Your sister may wish to look at this while waiting for Mathsguru’s solution.

                    http://www.postimage.org/image.php?v=gxEDrbJ
                    Hi Dharma,
                    Thanks for your effort and time. Your alternative approach is the same method that I had taught her but she wants to learn the model solution by Mathsguru.😢

                    Hi Guan Hui/speedmaths.com,
                    Thanks for your solutions.

                    Hi Mathsguru,
                    From http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=6113&postdays=0&postorder=asc&start=100 and his http://chillycrab.webs.com/, is it possible for you to compile all your questions and solutions from this thread into a blog/website for others to learn from you?

                    1 Reply Last reply Reply Quote 0
                    • V Offline
                      Vanilla Cake
                      last edited by

                      ck123:
                      I need help with the model for this question.


                      The number of marbles in Box A, Box B and Box C was 195.
                      John added 60 marbles to those in Box A, doubled the number of marbles in Box B and halved the number of marbles in Box C.
                      The ratio of the number of marbles becomes 4:1:2.
                      What is the total number of marbles in the three boxes now?
                      Hi ck123,
                      Thank you for posting this http://www.orlesson.org/orp/09Ma/2009-Math-SA1-RGS.pdf.My P5 younger sister also cannot understand the given worked solution. 😢

                      While waiting for help, please see whether my method is useful or not?
                      Draw the model for \"after\" scenario:

                      After
                      Box A : 8 equal blocks
                      Box B : 2 equal blocks
                      Box C : 4 equal blocks

                      Before
                      Box A : 8 equal blocks - 60
                      Box B : 1 block
                      Box C : 8 equal blocks

                      8 blocks-60+1 block+8 blocks = 195
                      17 blocks = 255
                      1 block = 15

                      1 block is the same as 1 unit

                      Total marbles in the three boxes now : (8+2+4) blocks = 14 blocks
                      14 blocks = 14x15 = 210

                      Mod : Pls merge this thread with http://www.kiasuparents.com/kiasu/forum/viewtopic.php?p=160403#160403 so that Mathsguru can post a clear and well-illustrated model solution.

                      Thanks.

                      1 Reply Last reply Reply Quote 0
                      • O Offline
                        OK Lor
                        last edited by

                        Dharma:
                        OK Lor:

                        Hi Mathsguru,


                        The product of two numbers, A and B, is 108. The difference betweeen A and B is a common factor of A and B. Find the values of A and B.

                        Thanks.

                        108 = 2 X 2 X 3 X 3 X 3 = 12 X 9
                        A = 12, B = 9 (A – B = 12- 9 = 3)
                        3 is a common factor of both 12 and 9.

                        Hi Dharma,

                        Thanks.

                        1 Reply Last reply Reply Quote 0

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