Tutor MathsGuru: Ask me for your burning Maths questions!
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YLH88:
Hope this will helpHi VC, Dharma,
Thank you so much for the solution !! Am trying to 'disgest' and understand the method
May need to trouble you again if still blur .. :?
http://www.postimage.org/image.php?v=Ts2JJbS -
I had another question.
A 60 km long train enter into an underground tunnel. it is traveling at a speed of 72km/h. It takes 2 mins to emerge entirely from the tunnel. How long is the undergound tunnel? -
nettie:
Is the length of the train 60km or 60m?I had another question.
A 60 km long train enter into an underground tunnel. it is traveling at a speed of 72km/h. It takes 2 mins to emerge entirely from the tunnel. How long is the undergound tunnel? -
Dharma:
I was told verally that it is 60km! i was wondering how can the train be so long! hahaha
Is the length of the train 60km or 60m?nettie:
I had another question.
A 60 km long train enter into an underground tunnel. it is traveling at a speed of 72km/h. It takes 2 mins to emerge entirely from the tunnel. How long is the undergound tunnel? -
nettie:
I was told verally that it is 60km! i was wondering how can the train be so long! hahaha[/quote]When the train emerges entirely from the tunnel of length L(tunnel) in 2 minutes, the distance travelled by the train will be the sum of the length of tunnel L(tunnel) and length of the train, L(train)
Is the length of the train 60km or 60m?Dharma:
[quote=\"nettie\"]I had another question.
A 60 km long train enter into an underground tunnel. it is traveling at a speed of 72km/h. It takes 2 mins to emerge entirely from the tunnel. How long is the undergound tunnel?
L(tunnel) + L(train) = Speed of train (72km/h) x Time taken (2 mins/60 = 1/30hrs)
L (tunnel ) = 72/30 km – 60 km = 2.4km – 60km [ IMPOSSIBLE!!!!]
The length of train is likely to be 60m
L(tunnel) = 2.4km – 0.06km = 2.34km -
Hi I have a speed qn. Can help?
Town B is located between Town A and C.
At 2pm, a train left Town B and travelled towards Town C.
2.5 hr later, another train left Town B for Town A.
At 6pm, the two trains were 569km apart.
What was the speed of the train travelling towards Town C if it was going at 35km/h faster than the other train?
Tx -
Dharma:
When the train emerges entirely from the tunnel of length L(tunnel) in 2 minutes, the distance travelled by the train will be the sum of the length of tunnel L(tunnel) and length of the train, L(train)
I was told verally that it is 60km! i was wondering how can the train be so long! hahahanettie:
[quote=\"Dharma\"]
Is the length of the train 60km or 60m?
L(tunnel) + L(train) = Speed of train (72km/h) x Time taken (2 mins/60 = 1/30hrs)
L (tunnel ) = 72/30 km – 60 km = 2.4km – 60km [ IMPOSSIBLE!!!!]
The length of train is likely to be 60m
L(tunnel) = 2.4km – 0.06km = 2.34km[/quote]Hi nettie,
Your question is similar to http://www.wendykoh.com/08/primary6-scgssa2-maths.pdf and that question was posted by http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=280&postdays=0&postorder=asc&start=840 on Thu Sep 24, 2009 3:46 pm and the correct method used to solve this problem sum was confirmed by our revered http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=280&postdays=0&postorder=asc&start=840 on Thu Sep 24, 2009 6:58 pm.
Pls recheck the source while waiting for Mathsguru' solution.
Submitted by VC's mum -
Herbie:
113 km/hHi I have a speed qn. Can help?
Town B is located between Town A and C.
At 2pm, a train left Town B and travelled towards Town C.
2.5 hr later, another train left Town B for Town A.
At 6pm, the two trains were 569km apart.
What was the speed of the train travelling towards Town C if it was going at 35km/h faster than the other train?
Tx -
huh! Can show the steps?
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Herbie:
huh! Can show the steps?
Sure.
(ux1.5)+(u+35)4= 569
Solve for u and you will get u =78 km/h
(78+35) km/h = 113 km/h
Pls kindly wait for Dharma/Mathsguru's detailed solution.
Thanks.
Submitted by VC's mum.
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