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    Tutor MathsGuru: Ask me for your burning Maths questions!

    Scheduled Pinned Locked Moved Primary Schools - Academic Support
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    • D Offline
      Dharma
      last edited by

      YLH88:
      Hi VC, Dharma,


      Thank you so much for the solution !! Am trying to 'disgest' and understand the method

      May need to trouble you again if still blur .. :?
      Hope this will help

      http://www.postimage.org/image.php?v=Ts2JJbS

      1 Reply Last reply Reply Quote 0
      • N Offline
        nettie
        last edited by

        I had another question.


        A 60 km long train enter into an underground tunnel. it is traveling at a speed of 72km/h. It takes 2 mins to emerge entirely from the tunnel. How long is the undergound tunnel?

        1 Reply Last reply Reply Quote 0
        • D Offline
          Dharma
          last edited by

          nettie:
          I had another question.


          A 60 km long train enter into an underground tunnel. it is traveling at a speed of 72km/h. It takes 2 mins to emerge entirely from the tunnel. How long is the undergound tunnel?
          Is the length of the train 60km or 60m?

          1 Reply Last reply Reply Quote 0
          • N Offline
            nettie
            last edited by

            Dharma:
            nettie:

            I had another question.


            A 60 km long train enter into an underground tunnel. it is traveling at a speed of 72km/h. It takes 2 mins to emerge entirely from the tunnel. How long is the undergound tunnel?

            Is the length of the train 60km or 60m?

            I was told verally that it is 60km! i was wondering how can the train be so long! hahaha

            1 Reply Last reply Reply Quote 0
            • D Offline
              Dharma
              last edited by

              nettie:
              Dharma:

              [quote=\"nettie\"]I had another question.


              A 60 km long train enter into an underground tunnel. it is traveling at a speed of 72km/h. It takes 2 mins to emerge entirely from the tunnel. How long is the undergound tunnel?

              Is the length of the train 60km or 60m?

              I was told verally that it is 60km! i was wondering how can the train be so long! hahaha[/quote]When the train emerges entirely from the tunnel of length L(tunnel) in 2 minutes, the distance travelled by the train will be the sum of the length of tunnel L(tunnel) and length of the train, L(train)

              L(tunnel) + L(train) = Speed of train (72km/h) x Time taken (2 mins/60 = 1/30hrs)

              L (tunnel ) = 72/30 km – 60 km = 2.4km – 60km [ IMPOSSIBLE!!!!]

              The length of train is likely to be 60m
              L(tunnel) = 2.4km – 0.06km = 2.34km

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              • H Offline
                Herbie
                last edited by

                Hi I have a speed qn. Can help?


                Town B is located between Town A and C.
                At 2pm, a train left Town B and travelled towards Town C.
                2.5 hr later, another train left Town B for Town A.
                At 6pm, the two trains were 569km apart.
                What was the speed of the train travelling towards Town C if it was going at 35km/h faster than the other train?

                Tx

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                • V Offline
                  Vanilla Cake
                  last edited by

                  Dharma:
                  nettie:

                  [quote=\"Dharma\"]
                  Is the length of the train 60km or 60m?

                  I was told verally that it is 60km! i was wondering how can the train be so long! hahaha

                  When the train emerges entirely from the tunnel of length L(tunnel) in 2 minutes, the distance travelled by the train will be the sum of the length of tunnel L(tunnel) and length of the train, L(train)

                  L(tunnel) + L(train) = Speed of train (72km/h) x Time taken (2 mins/60 = 1/30hrs)

                  L (tunnel ) = 72/30 km – 60 km = 2.4km – 60km [ IMPOSSIBLE!!!!]

                  The length of train is likely to be 60m
                  L(tunnel) = 2.4km – 0.06km = 2.34km[/quote]Hi nettie,
                  Your question is similar to http://www.wendykoh.com/08/primary6-scgssa2-maths.pdf and that question was posted by http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=280&postdays=0&postorder=asc&start=840 on Thu Sep 24, 2009 3:46 pm and the correct method used to solve this problem sum was confirmed by our revered http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=280&postdays=0&postorder=asc&start=840 on Thu Sep 24, 2009 6:58 pm.
                  Pls recheck the source while waiting for Mathsguru' solution.

                  Submitted by VC's mum

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                  • V Offline
                    Vanilla Cake
                    last edited by

                    Herbie:
                    Hi I have a speed qn. Can help?


                    Town B is located between Town A and C.
                    At 2pm, a train left Town B and travelled towards Town C.
                    2.5 hr later, another train left Town B for Town A.
                    At 6pm, the two trains were 569km apart.
                    What was the speed of the train travelling towards Town C if it was going at 35km/h faster than the other train?

                    Tx
                    113 km/h

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                    • H Offline
                      Herbie
                      last edited by

                      huh! Can show the steps?

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                      • V Offline
                        Vanilla Cake
                        last edited by

                        Herbie:
                        huh! Can show the steps?

                        Sure. 😄

                        (ux1.5)+(u+35)4= 569
                        Solve for u and you will get u =78 km/h
                        (78+35) km/h = 113 km/h

                        Pls kindly wait for Dharma/Mathsguru's detailed solution.
                        Thanks.

                        Submitted by VC's mum.

                        1 Reply Last reply Reply Quote 0

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