2017 - Raffles - SA1 Maths
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Before
SP \tU + 152
T \tU
After:
SP \tU + 152 – 301 = U -149
T\t(U + 152 – 301) * 4 = (4U – 596)
Total amount before and after is the same:
U + 152 + U = U – 149 + (4U – 596)
2U + 152 = 5U -745
3U = 897
U = 299
Total they have altogether = 2U + 152 = 750
Ps: You might want to go to this part of the forum to post your specific syllabus questions. They are sorted into subjects & levels & there are a lot more gurus there to help you out.
https://www.kiasuparents.com/kiasu/askq/ -
301-152=149
Before:
SP: U+301
T: U+149
After:
SP: U
T : 4U=U+149+301=U+450
U=450/3=150
Total=150x5=750 -
Thank you very much for your replies.
Is there a model drawing approach to solve this problem? It is easier to be solved in algebra as you have highlighted above but what school expects is the solution with model drawing.
Once again great effort and really appreciate it.
Best regards
Suma -
Suma Vaddadi:
That is the model approach.Thank you very much for your replies.
Is there a model drawing approach to solve this problem? It is easier to be solved in algebra as you have highlighted above but what school expects is the solution with model drawing.
Once again great effort and really appreciate it.
Best regards
Suma
You have to draw out the models then write out the equations.
For the drawings, substitute the U for a box and put U inside.
Even in modeling, you still need to use equations (single unknown).
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