Tutor MathsGuru: Ask me for your burning Maths questions!
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Ngserene617:
A:B+C:T =1:3:4------ 3:9:12Hi kindly assist me for the below 3 stated questions, thanks.
3. 3 sisters, Amy, Bonnie and Cindy shared to buy a present for their mother. Amy paid 1/3 of the amount which Bonnie and Cindy paid. Bonnie paid 1/5 of the amount which Amy and Cindy paid. If Cindy paid $30 more than Bonnie, how much did the present cost?
Thanks kindly help me to solve this !
B:A+C:T= 1:5:6 -------2:10:12
A:B:C= 3:2:[9-2]
5 units--- $30
12 units---?[$72]
Is the answer $72/-? -
Ngserene617:
Concept - Total unchanged3. 3 sisters, Amy, Bonnie and Cindy shared to buy a present for their mother. Amy paid 1/3 of the amount which Bonnie and Cindy paid. Bonnie paid 1/5 of the amount which Amy and Cindy paid. If Cindy paid $30 more than Bonnie, how much did the present cost?
A : B+C
1 : 3
3 : 9
B : A+C
1 : 5
2 : 10
A: 3u
B: 2u
7u
C-D=(7-2)u= 5u
5u=$30
Total cost of present = (3+2+7)u= 12u= $30/5x12= $72Ngserene617:
Pls kindly state the level (P6 or P5) of your questions and source.Thanks kindly help me to solve this !
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mathsguru:
Original Title: Let MathsGuru Answer Your Burning Maths Questions!
:welcome:
Dear Parents,
Are you frustrated/stuck when helping your child solve his/her Maths questions? Are you inclined to use Algebra most of the time? Do you have difficulty trying to use diagrams or other heuristic methods (that Primary School students learn) to solve?
:idea: Post your questions here and see how MathsGuru solve them to the best of her ability. Detailed solutions will be posted back in this thread.
Hi mathguru can u help me for this question 3;
3. 3 sisters, Amy, Bonnie and Cindy shared to buy a present for their mother. Amy paid 1/3 of the amount which Bonnie and Cindy paid. Bonnie paid 1/5 of the amount which Amy and Cindy paid. If Cindy paid $30 more than Bonnie, how much did the present cost?
Thanks
So start asking and watch this space!!
Cheers :celebrate: ,
MathsGuru
P/S (Disclaimer, in case you're wondering...):
Although MathsGuru is a full-time Maths tutor, this thread is meant to be an absolutely free resource for parents (or even children) with no strings attached. Just someone who's passionate about Maths and wanna spread the fun in learning Maths with others.
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Ngserene617, have you looked at Almighty’s and VanillaCake’s solution?
Is the answer $72? -
Dear maths guru
Good evening.
Please help me on the following P6 maths:
1) There are 2/5 as many girls as boys in a class. What fraction of the pupils in the class are boys?
2) Mr. Chong and Mr. Tan had $87. Mr. Tan and Mr. Ng had $115. If the amount of money Mr.Chong had was 3/7 of the amount Mr. Ng had, how much did Mr. Tan have?
3) At a party, there were some ballons. 25 balloons burst and 10% of the remaining balloons flew away. If only 60% of the balloons were left, how many balloons were there at first.
4) Packets A, B and C each contained some cement. 1/3 of the cement was transferred from Packet A to Packet B. Then 1/3 of the cement was transferred from Packet B to Packet C. Finally 1/3 of the cement was transferred from Packet C to Packet A. In the end there were 12 kg of cement in each packet. What was the mass of cement in Packet B at first?
5)A club had 150 members last year, This year, the number of male members reduced by 20%. As a result, there are now as many male members as female members. How many members does the club has this year?
6) A car and a lorry which were 80km apart started to travel towards each other at the same time. The car was 40Km/h faster than the lorry. They went past each other after 2/5 hours.
a) How far did the lorry travel when it passed the car?
b) Find the speed of the lorry.
Many thanks
firebird -
Almighty:
Amy => 1/4 = 3/12
A:B+C:T =1:3:4------ 3:9:12Ngserene617:
Hi kindly assist me for the below 3 stated questions, thanks.
3. 3 sisters, Amy, Bonnie and Cindy shared to buy a present for their mother. Amy paid 1/3 of the amount which Bonnie and Cindy paid. Bonnie paid 1/5 of the amount which Amy and Cindy paid. If Cindy paid $30 more than Bonnie, how much did the present cost?
Thanks kindly help me to solve this !
B:A+C:T= 1:5:6 -------2:10:12
A:B:C= 3:2:[9-2]
5 units--- $30
12 units---?
Is the answer $72/-?
Bonnie => 1/6 = 2/12
Cindy => 7/12
7u- 2u = 5u = $30
12u = $72 -
ksi:
Hi VanillaCake's & Almighty,Ngserene617, have you looked at Almighty's and VanillaCake's solution?
Is the answer $72?
I do not have the ans yet for this queston:( I must wait till my kid get back the paper then be able to know the ans just need to pass up so I must help her solve and understand the question! Thanks so much for both of u tat help me ::) Anyway, once I got the ans will let both of u know again ! -
2) Mr. Chong and Mr. Tan had $87. Mr. Tan and Mr. Ng had $115. If the amount of money Mr.Chong had was 3/7 of the amount Mr. Ng had, how much did Mr. Tan have?
C+T = 87
T+N = 115
N-C = 28
Difference of N and C = 7-3 = 4
4 parts -> 28
1 part -> 7
7 parts -> $49 -> Mr Ng
3 parts -> $21 -> Mr Chong
Hence Mr Tan has (87-21) = $66 or (115-49) = $66 -
firebird:
1) There are 2/5 as many girls as boys in a class. What fraction of the pupils in the class are boys?
G: B
2 : 5
Fraction of the pupils in the class that are boys = 5/7firebird:
2) Mr. Chong and Mr. Tan had $87. Mr. Tan and Mr. Ng had $115. If the amount of money Mr.Chong had was 3/7 of the amount Mr. Ng had, how much did Mr. Tan have?
[][][]
T:
N: [][][][][][][]
C+T=$87
T+N=$115
T+N-(C+T)=7u-3u
$(115-87)=4u
4u=$28
u=$7
T=$87-C = $87-3units = $87-3($7)=$87-$21=$66
Amount of money that Mr Tan had = $66firebird:
60% of total = 90% of the remaining balloon3) At a party, there were some ballons. 25 balloons burst and 10% of the remaining balloons flew away. If only 60% of the balloons were left, how many balloons were there at first.
66⅔% of total = 100% of the remaining balloon
66⅔% = 2/3
1/3 of total = 25
Total = 25x3=75
At first, there were 75 balloons
Check
At first - 75 balloons
25 balloon burst
Left = 75-25=50 balloons
10% of the remaining balloons flew away = 10/100x50= 5 balloons
Final remainder =50 balloons - 5 balloons = 45 balloons
45/75x100% = 60% of the balloons were left. -
firebird:
4) Packets A, B and C each contained some cement. 1/3 of the cement was transferred from Packet A to Packet B. Then 1/3 of the cement was transferred from Packet B to Packet C. Finally 1/3 of the cement was transferred from Packet C to Packet A. In the end there were 12 kg of cement in each packet. What was the mass of cement in Packet B at first?
Concept - Total unchanged
End
A=12 kg
B=12 kg
C=12 kg
2/3 of C = 12 kg
C=18 kg
A=6 kg
B=12 kg
2/3of B=12kg
B=18 kg
C=12 kg
A=6 kg
2/3(A)=6 kg
A=9 kg
B=(18-3) kg = 15 kg
C=12 kg
At first, mass of cement in packet B = 15 kg
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