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    Tutor MathsGuru: Ask me for your burning Maths questions!

    Scheduled Pinned Locked Moved Primary Schools - Academic Support
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    • M Offline
      Maths Monster
      last edited by

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        Maths Monster
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          Maths Monster
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          • A Offline
            Almighty
            last edited by

            [quote="Maths Monster"]


            Footnote:

            This type of "Before and After" problem appears in various forms and can be solved easily. Teach the child to use a combination of model and simple algebra to form the equation. My advice is to draw all the 3 states, ie the beginning and the other two states where each gave the other some money. Then the child can start in one state and insert the ratio he/she is given, ie Ali has 5x of Lucy after Lucy gave him $8. Then the child will populate the other states using the given information. Lastly, using the other ratio, ie Lucy has 1/3 of the amount Ali has after Ali gave her $12, to form the equation which when solved will lead to the answer.

            How do the child know where to put the unit "u"? The purpose of the "u" is to equate ratio/fraction/percentage. Teach the child to look for the ratio/fraction/percentage given in the question. In this question, there are two ratios, ie 5x or 3x. I used the 5x to start but either can be used. I would encourage to try using the 3x and derive the answer.

            The problem many children or parents faced is when the model becomes too complex, ie too many congested boxes while trying to align them can be quite a task. This often discourage and frustrate the child. The method shown is more elegant as it doesn’t need to divide the boxes nor require alignment of the boxes. You can find good examples of using combination of Model and Algebra in this book: "The Singapore Model Method For Learning Mathematics - by the Singapore Ministry of Education". It can be found in most library or book store. Hope this helps!

            It helped me a lot Maths monster.Now i picked qts like this n iam doing in yr method.I find it very simple comparitively. I am very weak in complex model drawings. Based on this method can u explaing this problem which was done in this website ina different way.I want to try in yr way…But getting stuck…pl.help
            Tom had $144 more than Ali at first. After Tom spent 25% of his money and Ali spent 1/3 of his money. Tom had $122 more than Ali. How much did Tom have at first?
            Thankyou very much for all other answers too.

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            • A Offline
              Almighty
              last edited by

              Maths Monster:
              Almighty:

              Question :8 - speed -EDITED

              Tom, Bob and Kel;vin started running at the same point X at the same time round a circular track. Tom ran in a clockwise direction but Bob and Kelvin ran in an anti-clockwise direction. Tom took 7 minutes to complete each round. He met Bob after every 4 minutes and he met Kelvin after every 2 minutes. Each of them ran at the same uniform speed throughout.
              a) What was the ratio of Toms speed to Kelvin's speed to Bob's speed?Ans:4:10:3.
              b) When Tom and Bob met again at X after 21 minutes, Tom had already run 4200m. What was the distance ran by Kelvin when Tom met Bob at X after 21 minutes?
              section B cannot understand the method.pl.brief.Ans:3500m

              http://www.postimage.org/image.php?v=PqxSqjr

              Tom ran 1 round in 7 mins. His speed is 1/7 round per min.

              In 2 mins, he ran 2/7 round.
              In the same time, Kelvin ran 5/7 round to meet Tom
              Kelvin speed is 5/7 / 2 = 5/14 round per min.

              In 4 mins, he ran 4/7 round.
              In the same time, Bob ran 3/7 round to meet Tom
              Bob speed is 3/7 / 4 = 3/28 round per min.

              a) Ratio of speed:
              Tom : Kelvin : Bob
              1/7 : 5/14 : 3/28
              4 : 10 : 3

              b) Tom and Bob meet every 4 mins, ie in the multiply of 4.
              21 / 4 = 5.25, therefore we use 6x4 = 24 mins
              After 24 mins, Tom ran 24/7 rounds = 4200m
              Each round = 4200 x 7/24 = 1225m

              Therefore, in 24 mins, Kelvin ran 5/14 x 24 x 1225 = 10,500m

              Hi mathsmonster.The answer for section b is different from the one gn in the answerkey:It states the follw:
              21 min = 4200m
              7min = 4200/21x7
              1 round = 1400m
              Kelvin completed 2.5 rounds in 7 min, so, 2.5 x 1400 = 3500m.(ANS)
              I dint understand the part writted in red. Pl.explain.Sorry 2 trouble u again..

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              • A Offline
                Almighty
                last edited by

                Thankyou Dharma for helping me…

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                • A Offline
                  Almighty
                  last edited by

                  Almighty:
                  Question :5Pattern II -photo print


                  http://www.postimage.org/image.php?v=PqxRqXS
                  Hi MAthmonster,Dharma,Ksi & others......
                  Reposting...If this qt had missed yr eye...Since i posted many qt last night.
                  Pl.try to help me on this too..

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                  • M Offline
                    Maths Monster
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                      Maths Monster
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                      • Y Offline
                        YLH88
                        last edited by

                        Hi Maths Monster,


                        Thank you so much for your help!

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