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    Tutor MathsGuru: Ask me for your burning Maths questions!

    Scheduled Pinned Locked Moved Primary Schools - Academic Support
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    • F Offline
      firebird
      last edited by

      Dear Dharma


      Good morning sir.

      Many thanks for your solutions.

      As mention by you, I have missed some part in Question 4 b). Iam retyping it as follows:

      At a conference made up of speakers and participants, there were 20% more men than women. The ratio of male speakers to female speakers was 8:5. There was an equal number of male and female participants.

      a) Find the ratio of male speakers to male participants at the conference.

      b) Halfway 40 male participants left the conference and another 60 female participants joined the conference. In the end, there were 3/4 as many male participants as female participants remaining behind, How many speakers were there at the conference?


      Very sorry for the error

      Thank you
      Firebird

      1 Reply Last reply Reply Quote 0
      • F Offline
        firebird
        last edited by

        Dear VC mum


        I do not know any of the answers as the questions were given by my son’s school.

        There was some ommission of important word while typing. Possibily, the differences in answers due to this typo error.

        Kindly refer to the one retyped. I am very sorry for the trouble.

        With best regards
        Firebird

        1 Reply Last reply Reply Quote 0
        • D Offline
          Dharma
          last edited by

          firebird:
          Dear Dharma


          Good morning sir.

          Many thanks for your solutions.

          As mention by you, I have missed some part in Question 4 b). Iam retyping it as follows:

          At a conference made up of speakers and participants, there were 20% more men than women. The ratio of male speakers to female speakers was 8:5. There was an equal number of male and female participants.

          a) Find the ratio of male speakers to male participants at the conference.

          b) Halfway 40 male participants left the conference and another 60 female participants joined the conference. In the end, there were 3/4 as many male participants as female participants remaining behind, How many speakers were there at the conference?


          Very sorry for the error

          Thank you
          Firebird
          Q3)

          Good morning firebird.

          Male : Women = 6 : 5
          Male speakers : Female speaker = 8 : 5
          Male participants : Female participants = 1 : 1
          8u + 1p/(5u + 1p) = 6/5
          40u + 5p = 30u + 6p
          10u = 1p
          a) Male speakers : Male participants = 8u : 1p = 8u : 10u = 4 : 5
          b)
          1p – 40/(1p + 60) = ¾
          4p – 160 = 3p + 180
          1p = 340
          10u = 340
          Total number of speakers = 13u = 13 x 34 = 442

          1 Reply Last reply Reply Quote 0
          • corneyAmberC Offline
            corneyAmber
            last edited by

            YLH88:

            Hi,

            From Observer's solution, I'm still abit confused on how the following steps are derived :

            a) why need to add 4 to 8035 ?
            The Jan 1 in 1981 falls on day 4.

            2003 - 1981 = 22 years
            22/4 = 5 leap years (max)
            22 x 365 + 5 =8035 days
            8035 + 4 = 8039 --> ??
            8039/7 = 1148 r 3


            ans : It was 3.


            b) why need to add 4 to 25 x 365 + 6 ?
            Same as above

            2006 - 1981 = 25 years
            25/4 = 6 leap years (max)
            25 x 365 + 6 + 4 = 9135 --> ??
            9135/7 = 1305 or 1304 r 7

            ans : It was 7.

            c) why need to add 7 + 4 to 31 x 365 + 31 + 7 + 4 ?
            +4 is same as above
            +7 is the number of leap years
            +31 because there are 31 days in Jan and the question asks for 1st Feb


            2012 - 1981 = 31 years
            31/4 = 7 leap years (max)
            31 x 365 + 31 + 7 + 4 = 11357 days --> ??
            11357/7 = 1622 r 3

            3 --> Wednesday

            ans : It is Wednesday.


            Thank you very much!

            1 Reply Last reply Reply Quote 0
            • H Offline
              Herbie
              last edited by

              Hi beauty queen


              $10-$3/10 = $0.70 (cost of pencil)

              I dun understand the above sentence why $3/10?

              Can explain???

              Uncle Dharma can help??

              Many thanks!

              1 Reply Last reply Reply Quote 0
              • Y Offline
                YLH88
                last edited by

                ksi:
                YLH88:


                Hi,

                From Observer's solution, I'm still abit confused on how the following steps are derived :

                a) why need to add 4 to 8035 ?
                The Jan 1 in 1981 falls on day 4.

                2003 - 1981 = 22 years
                22/4 = 5 leap years (max)
                22 x 365 + 5 =8035 days
                8035 + 4 = 8039 --> ??
                8039/7 = 1148 r 3


                ans : It was 3.


                b) why need to add 4 to 25 x 365 + 6 ?
                Same as above

                2006 - 1981 = 25 years
                25/4 = 6 leap years (max)
                25 x 365 + 6 + 4 = 9135 --> ??
                9135/7 = 1305 or 1304 r 7

                ans : It was 7.

                c) why need to add 7 + 4 to 31 x 365 + 31 + 7 + 4 ?
                +4 is same as above
                +7 is the number of leap years
                +31 because there are 31 days in Jan and the question asks for 1st Feb


                2012 - 1981 = 31 years
                31/4 = 7 leap years (max)
                31 x 365 + 31 + 7 + 4 = 11357 days --> ??
                11357/7 = 1622 r 3

                3 --> Wednesday

                ans : It is Wednesday.


                Thank you very much!

                Hi ksi,
                Thank you so much for the explanation!!

                Hi VC's mum,
                Thanks for the advise but ksi has kindly provided the explanation 🙂

                1 Reply Last reply Reply Quote 0
                • F Offline
                  firebird
                  last edited by

                  Dear Dharma , Vanilla cake & VC mum


                  Many thanks. You have cleared my doubts.

                  With best regards
                  Firebird

                  1 Reply Last reply Reply Quote 0
                  • D Offline
                    Dharma
                    last edited by

                    Herbie:
                    Hi beauty queen


                    $10-$3/10 = $0.70 (cost of pencil)

                    I dun understand the above sentence why $3/10?

                    Can explain???

                    Uncle Dharma can help??

                    Many thanks!
                    3B + 7P = $10
                    1B – 1P = $1
                    3B – 3P = $3
                    10P = ($10 - $3)
                    1P = ($10 - $3)/10 = $0.70
                    1B = $0.70 + $1 = $1.70

                    1 Reply Last reply Reply Quote 0
                    • H Offline
                      Herbie
                      last edited by

                      Hi Uncle Dharma


                      Can explain why 1B - 1P = $1???

                      Many thanks!

                      1 Reply Last reply Reply Quote 0
                      • D Offline
                        Dharma
                        last edited by

                        Herbie:
                        Hi Uncle Dharma


                        Can explain why 1B - 1P = $1???

                        Many thanks!
                        Hi Herbie,

                        If you buy 1 extra book you need $0.40 more but if you buy 1 extra pencil you have $0.60 left.

                        So, difference in price of 1 book and 1 pencil is $ 0.40 + $0.60 = $1.00

                        1 Reply Last reply Reply Quote 0

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