Tutor MathsGuru: Ask me for your burning Maths questions!

[super star]

pls help me with this problem.

There were 500 beads in 4 jars-PQR&S.If the number of beads inP was halved,the number of beads in Q was increased by 18,the number of beads in R was tripled &the number of beads in S was decreasede by 24, the four jars would have the same number of beads .what is the difference in the number of beads between jars P &Q?

[CTong]

Pls help to solve. Thanks.


James had 20 goldfishes and 30 guppies in a fish tank. 20% of the guppies died. James bought another 16 goldfishes.
a) What percentage of the fish were guppies?
b) What was the increase in percentage of goldfish?

[YLH88]

Hi all,


I need help with the below questions :? :

1) ABCD is a rectangle. X is a point on AB. XB is 3/4 of AB.
The area of AXCD is 90 cm2. Find the area of XBC.

http://postimage.org/image/1c1ogtk3o/

2) John had $180 more than Raymond at first.
Both bought a different printer with some of their money.
In the end, Raymond was left with $20 more than John.
If John's printer cost 50% more than Raymond's printer,
how much does John's printer cost ?


3) At 9am, John was cycling from Point A to Point B.
At the same time, Mary was cycling from Point B to Point A using the same route as John.
Cycling at a speed of 4km/h faster than Mary, they would pass each other 300 m away from the midpoint.

a) What time did they pass each other ?

b) If John took another 3 minutes to reach Point B, what time would Mary reach Poiint A ?


4) At a conference made up of speakers and participants,
there were 20% more men than women.
The ratio of male speakers to female speakers was 8:5.
There was an equal number of male and female participants.

a) Find the ratio of male speakers to male participants at the conference.

b) Halfway, 40 male participants left the conference and another 60 female participants joined the conference.
In the end, there were 3/4 as many male participants as female participants remaining behind.
How many speakers were there at the conference ?

Thank you very much!

[Vanilla Cake]

beauty queen:

How do i solve Maha Bodhi PSLE prelim 2010 paper 2 question 6. it is the apples and pear question sorry i dont have the picture available but the picture states that a apple costs 40 cents and pear costs 60 cents


Mrs Gopal and Mrs Ari went to the supermarket. Both women decided to spend all their money on either apples or pears and they would not buy the same fruit. If Mrs Gopal bought only pears, she would have 9 more fruit than Mrs Ari. If she bought only apples, she would have 41 more fruits than Mrs Ari. How much money has Mrs Gopal than Mrs Ari.

Thank you for helping me in both this question and previous ones :thankyou:

Refer to:
http://psle2010a.blogspot.com/2010/09/decimal-p6-2010-sa2-maha-bodhi-p2-q6.html.
http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=280&postdays=0&postorder=asc&start=1770 dated 14 Sep 2010 18:22
http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=280&postdays=0&postorder=asc&start=1770 dated 15 Sep 2010 11:43
http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=280&postdays=0&postorder=asc&start=1780 dated 16 Sep 2010 08:03

[Vanilla Cake]

YLH88:

2) John had $180 more than Raymond at first.

Both bought a different printer with some of their money.
In the end, Raymond was left with $20 more than John.
If John's printer cost 50% more than Raymond's printer,
how much does John's printer cost ?

3) At 9am, John was cycling from Point A to Point B.
At the same time, Mary was cycling from Point B to Point A using the same route as John.
Cycling at a speed of 4km/h faster than Mary, they would pass each other 300 m away from the midpoint.
a) What time did they pass each other ?
b) If John took another 3 minutes to reach Point B, what time would Mary reach Poiint A ?

4) At a conference made up of speakers and participants,
there were 20% more men than women.
The ratio of male speakers to female speakers was 8:5.
There was an equal number of male and female participants.
a) Find the ratio of male speakers to male participants at the conference.
b) Halfway, 40 male participants left the conference and another 60 female participants joined the conference.
In the end, there were 3/4 as many male participants as female participants remaining behind.
How many speakers were there at the conference ?

Hi YLH88,

Pls note that your questions 2, 3 and 4 had been posted by http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=6373&postdays=0&postorder=asc&start=2510 on 14 Sep 2010 02:51.
As it's getting late now and I have to wake up early tomorrow morning, I refer you to the links/solutions by Uncle Dharma.
Sorry, not enough time to think and solve your question 1. Pls wait for others to help. I think the answer for your Q1-> Area of XBC = 54 cm²

http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=6373&postdays=0&postorder=asc&start=2510 for your questions 2, 3 and 4 dated 14 Sep 2010 08:23 and http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=6373&postdays=0&postorder=asc&start=2520.

Are all these questions from Catholic High School (Primary) 2010 P6 Prelim 3?

Good night.
:snooze:

[Vanilla Cake]

super star:

There were 500 beads in 4 jars-PQR&S.If the number of beads inP was halved,the number of beads in Q was increased by 18,the number of beads in R was tripled &the number of beads in S was decreasede by 24, the four jars would have the same number of beads .what is the difference in the number of beads between jars P &Q?

Working backwards
In the end
P: u
Q: u
R: u
S: u

At first
P: 2u
Q: u-18
R: u/3
S: u+24

2u+u-18+u/3+u+24=500
4u+u/3=494
12u+u=1452
13u=1482
u=114

Difference ->2u-( u-18 )=2u-u+18=u+18=114+18=132
Difference in the number of beads between jars P &Q = 132

[Vanilla Cake]

super star:

A box contain some 50 cent coins,some 20 cent coins & some 10 cent coins in the ratio of 3:2:1 respectively.3/4 of the 50 cent coins were taken & replaced by the same number of 10 cent coins.Then180 twenty cent coins were taken out & replaced by same number of ten cent coins.In the end,the ratio of the 50 centcoins ,twenty cent coins & ten cent coins become 3:4:17 respectively.

(a)what is the total number of coins taken out of the box?
(b)what is the total value of coins taken out of the box?

Before
50¢ -> 3u
20¢ -> 2u
10¢ -> u

After
50¢ -> 0.75u (3p)
20¢ -> 2u-180 (4p)
10¢ -> 3.25u+180 (17p)

0.75u -> 3p
u -> 4p

2u-180=u
u=180
2.25u = 2.25x180=405
405+180=585
(a) Total number of coins taken out of the box = 585

405x$0.50+180x$0.20
$202.50+$36=$238.50

(b) Total value of coins taken out of the box = $238.50

Did this in a rush (otherwise I will be late for school), pls help to check the calculations.

[Dharma]

YLH88:

Hi all,


I need help with the below questions :? :

1) ABCD is a rectangle. X is a point on AB. XB is 3/4 of AB.
The area of AXCD is 90 cm2. Find the area of XBC.

http://postimage.org/image/1c1ogtk3o/


Thank you very much!

http://postimage.org/image/28adtcfgk/

[Dharma]

Vanilla Cake:

super star:

A box contain some 50 cent coins,some 20 cent coins & some 10 cent coins in the ratio of 3:2:1 respectively.3/4 of the 50 cent coins were taken & replaced by the same number of 10 cent coins.Then180 twenty cent coins were taken out & replaced by same number of ten cent coins.In the end,the ratio of the 50 centcoins ,twenty cent coins & ten cent coins become 3:4:17 respectively.

(a)what is the total number of coins taken out of the box?
(b)what is the total value of coins taken out of the box?

Before
50¢ -> 3u
20¢ -> 2u
10¢ -> u

After
50¢ -> 0.75u (3p)
20¢ -> 2u-180 (4p)
10¢ -> 3.25u+180 (17p)

0.75u -> 3p
u -> 4p

2u-180=u
u=180
2.25u = 2.25x180=405
405+180=585
(a) Total number of coins taken out of the box = 585

405x$0.50+180x$0.20
$202.50+$36=$238.50

(b) Total value of coins taken out of the box = $238.50

Did this in a rush (otherwise I will be late for school), pls help to check the calculations.

50 cents : 60u – 45u = 15u
20 cents : 40u - 180
10 cents : 20u + 45u + 180 = 65u + 180

3p = 15u
4p = 20u

40u – 180 = 20u
20u = 180
1u = 9

a)\tTotal no. of coins taken out = 45u + 180 = 45(9) + 180 = 585
b)\tValue of coins taken out = 405(50) + 180(20) = = 23850 cents = $238.50

[YLH88]

Hi VC,


Thank you for the link and solution. Yes, these are from Catholic High Prelim 2 and they are really challenging ....

Hi Dharma,

I'm not able to open up your attachment for Qn 1