Tutor MathsGuru: Ask me for your burning Maths questions!
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Hi,
I have a question on P5 Maths, really do not know how to do. Thanks in advance for helping.
Francis,Gif and Hakim shared a sum of money.Hakim decided to give Francis 2/3 of his money.Then, Francis gave Gif 3/4 of his money and Gif gave 3/7 of his money to Hakim. In the end, the amount of money they had was in the ratio 3:6:8. If Hakim had $55 more than Francis at first, how much money did Gif have in the end?
Thanks. -
Jan111:
Hi is the answer $15 for GifHi,
I have a question on P5 Maths, really do not know how to do. Thanks in advance for helping.
Francis,Gif and Hakim shared a sum of money.Hakim decided to give Francis 2/3 of his money.Then, Francis gave Gif 3/4 of his money and Gif gave 3/7 of his money to Hakim. In the end, the amount of money they had was in the ratio 3:6:8. If Hakim had $55 more than Francis at first, how much money did Gif have in the end?
Thanks.
I used \"unit\" method and worked backward and obtained the ratio at first to be :
F : G : H = 10 : 3 : 21
Hope some one can help to post the flow on how to convert to the same unit by working backwards.
I am zero when it comes to posting picture. Very sorry.
PS
Sorry, $15 if for Gif (at first) didn't read question. Careless as ever, sure die if I take PSLE now. -
atutor2001:
Sorry about the picture too..but here is the working.
Hi is the answer $15 for GifJan111:
Hi,
I have a question on P5 Maths, really do not know how to do. Thanks in advance for helping.
Francis,Gif and Hakim shared a sum of money.Hakim decided to give Francis 2/3 of his money.Then, Francis gave Gif 3/4 of his money and Gif gave 3/7 of his money to Hakim. In the end, the amount of money they had was in the ratio 3:6:8. If Hakim had $55 more than Francis at first, how much money did Gif have in the end?
Thanks.
I used \"unit\" method and worked backward and obtained the ratio at first to be :
F : G : H = 10 : 3 : 21
Hope some one can help to post the flow on how to convert to the same unit by working backwards.
I am zero when it comes to posting picture. Very sorry.
At the End
-------------
Francis = 3u
Gif = 6u
Hakim = 8u
1 step back
------------
Francis = 3u
Gif = 7/4x6u = 21u/2
Hakim = 8u โ 21u/2 x 3/7 =7u/2
2 steps back
-------------
Francis = 4 x 3u = 12u
Gif = 21u/2 โ 9u = 3u/2
Hakim = 7u/2
3 steps back
-------------
Francis = 12 โ (21u/2 x 2/3 ) = 5u = 10u/2
Gif = = 3u/2
Hakim = 7u/2 x 3 = 21u/2
21u/2 - 10u/2 = 55 ----> u = 10
Gif at the end = 6u = 6x10 = 60
Easier to understand this if drawn in a table..
HTH -
firebird:
1) John had $180 more than Raymond at first. Both bought a different printer with some of their money. In the end Rayamond was left with $20 more than John. If John's printer cost 50% more than Raymond's printer, how much does John's printer cost?
This question is from Catholic High School (Primary) 2010 P6 Prelim Paper 2 Q11 [3 marks]
John had $180 more than Raymond at first. Both bought a different printer with some of their money. In the end, Raymond was left with $20 more than John. If John's printer cost 50% more than Raymond's printer, how much does John's printer cost?firebird:
This question is from Catholic High School (Primary) 2010 P6 Prelim Paper 2 Q15 [5 marks]2) At 9am John was cycling from Point A to Point B. At the same time, Mary was cycling from point B to point A using the same route as John. Cycliing at a speed of 4km/h faster than Mary, they would pass each other 300 meter away from the mid point.
a) What time did they pass each other?
b) If John took another 3 minutes to reach Point B, what time would Mary reach Poin A?
At 9 a.m., John was cycling from Point A to Point B. At the same time, Mary was cycling from Point B to Point A using the same route as John. Cycling at a speed of 4km/h faster than Mary, John would pass Mary 300m away from the midpoint.
a) What time did they pass each other?
b) If John took another 3 minutes to reach Point B, what time would Mary reach Point A?firebird:
This question is from Catholic High School (Primary) 2010 P6 Prelim Paper 2 Q17 [5 marks]3) Daniel had 40% more stickers than Brandon. Daniel and Brandon each gave 20% of their stickers to Calvin. As a result, Calvin's stickers increased by 80%. If Daniel has 20 more stickers than Calvin in the end, how many stickers did Brandon have at first?
firebird:
This question is from Catholic High School (Primary) 2010 P6 Prelim Paper 2 Q18 [5 marks]4) At a conference made up of speakers and participants, there were 20% more men than women. The ratio of male speakers to female speakers was 8:5. There was an equal number of male and female participants.
a) Find the ratio of male speakers to male participants at the conference.
b) Halfway, 40 male participants left the conference and another 60 female participants joined the conference. In the end, there were 3/4 as many male participants remaining behind. How many speakers were there at the conference?
At a conference made up of speakers and participants, there were 20% more men than women. The ratio of male speakers to female speakers was 8:5. There was an equal number of male and female participants.
a) Find the ratio of male speakers to male participants at the conference.
b) Halfway, 40 male participants left the conference and another 60 female participants joined the conference. In the end, there were 3/4 as many male participants as female participants remaining behind. How many speakers were there at the conference?
This post is made to reflect the original questions and its source for reference purpose. Solutions for the above questions by Uncle Dharma can be found http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=6373&postdays=0&postorder=asc&start=2510. -
iFruit:
thank uCJM:
There are some coins in a box made up of 20-cent and $1 coins. There are thrice as many 20-cent coins as $1 coins. If the total amount of money in the box is $48, how many coins are there altogether ?
Let number of $1 coins = u
Number of 20-cent coins = 3u
value of coins = u+0.2(3u) = 1.6u = 48
u = 48/1.6 = 30
Total coins = 4u = 120
HTH -
iFruit:
yeah u are right ...
1M + 1/4 G = 150CJM:
1 Carton of marbles and 1/4 carton of golf balls cost $150.
3 Cartons of marbles and 11/16 carton of golf balls cost $130.
How much is the cost of 1 1/2 carton of golf balls ?
so,
3M + 3/4G = 450------->(1)
we also have
3M + 11/16G = 130 ------>(2)
From (1) and (2)
3/4G - 11/16G = 320
1/16 G = 320
3/2 G = 24/16G = 24x320 = $7680
That means you can get rich just by buying marbles
There is probably a typo somewhere in the problem.
it shd be 1 carton of marbles n 1/4 of golf balls cost $50 not $150. -
atutor2001 & IFruit , very clear steps๏ผ Thank you very much.
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Dear all
I would appreciate if you could enlighten me on the following Maths Qns:
1. A box contained some blue pens and red pens in the ratio of 11:3. After 28 blue pens were removed from the box and 7 red pens were added in the box, the ratio of the number of blue pens to the number of red pens in the box was 7:4. How many pens were there in the box at first?
2. Ali, Bala, Clyde and Dingyi shared a box of pens. Ali received 20% of the total number of pens which Bala, Clyde and Dingyi received altogether. Bala received 50% of the total number of pens which Ali, Clyde and Dingyi received altogether. Clyde received 80% of the total number of pens which Ali, Bala and Dingyi received altogether. Dingyi received 6 pens. How many pens were in the box at first?
Thanks in advance. -
sachiko:
Hi, this is NY 2009 SA2 Q16. You may refer the following link for the answer:Dear all
I would appreciate if you could enlighten me on the following Maths Qns:
2. Ali, Bala, Clyde and Dingyi shared a box of pens. Ali received 20% of the total number of pens which Bala, Clyde and Dingyi received altogether. Bala received 50% of the total number of pens which Ali, Clyde and Dingyi received altogether. Clyde received 80% of the total number of pens which Ali, Bala and Dingyi received altogether. Dingyi received 6 pens. How many pens were in the box at first?
Thanks in advance.
http://www.onsponge.com/forum/35-thinkingmathonsponge/3436-p5-math-unchanged-total.html -
sachiko:
Hi,Dear all
I would appreciate if you could enlighten me on the following Maths Qns:
1. A box contained some blue pens and red pens in the ratio of 11:3. After 28 blue pens were removed from the box and 7 red pens were added in the box, the ratio of the number of blue pens to the number of red pens in the box was 7:4. How many pens were there in the box at first?
Thanks in advance.
I will try to help solve qn 1. Hopefully the answer is correct.
B --> 11u - 28 = 7p
R --> 3u + 7 = 4p
Change 11u - 28 = 7p to 44u - 112 = 28p
Change 3u + 7 = 4p to 21u + 49 = 28p
44u - 112 = 21u + 49
44u - 21u = 49 + 112
23u = 161
u = 7
At first, there are 11u + 3u = 14u
14 x 7 = 98 pens at first
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