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    Tutor MathsGuru: Ask me for your burning Maths questions!

    Scheduled Pinned Locked Moved Primary Schools - Academic Support
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    • I Offline
      iFruit
      last edited by

      Vanilla Cake:
      Thks to Maths Hub and iFruit for your detailed and clear solutions. Sorry, some more questions from APMOPS 2005 that need your help.


      Q3
      The following number is made up of all the digits of the whole numbers 1 to 2005.
      12345678910111213141516..........20042005
      Find the number of zeros in this number.

      Corrected following maths hub solution.. 🙂 Thank Maths hub!

      1) we know between 2000 .... 2005 there are 13 zeros

      2) Now consider numbers 1000 ... 1999

      The 1000's digit is always one so 0 can appear only in 100's, 10's or 1's places.

      If there is only one 0, in those numbers, the other two places can vary between 1 to 9 giving 9x9 = 81 possibilities. Since there are three places we could have 3x81 single zeros between 1000...1999

      Similarly for two zeros, we will have 3x9 times number 0s appearing = 27x2 0's

      3 0's (number 1000 ) = 1 time = 3 0's

      3) Consider numbers 100 to 999

      we get 2x 81 numbers with one zero, 9 numbers with two zeros (18 zeros)

      4) Consider numbers 10..99

      we can have 0 in 1's digit place 9 times

      So that total number of zeros = 13 + 3x81 + 27x2 + 3 + 9x2 + 2x81 +9 = 502

      1 Reply Last reply Reply Quote 0
      • I Offline
        iFruit
        last edited by

        Vanilla Cake:
        T

        Q6
        Allen , Benedict and Carl started at the same instant from the same point using the same route trying to overtake a fourth cyclist Donald traveling at a constant speed ahead of them. Allen and Benedict each took 10 hours and 2 hours respectively to overtake Donald.
        Given that Allen , Benedict and Carl each cycled at the constant speed of 4 km/h, 5 km/h and 10 km/h respectively throughout the journey, find the time, in hours, that Carl took to overtake Donald.
        Allen = A, Benedict = B, Carl = C, Donald = D.

        Assume the initial distance between A,B,C and D is d
        speed of D = s km/h

        So time taken for A to meet D = d/(4-s) = 10 hours ....(1)
        time taken for B to meet D = d/(5-s) = 2hours.....(2)
        time taken for C to meet D = d/(10-s) = ?

        for (1) and (2), we get 10(4-s) = 2(5-s) ---> 20 - 5s = 5 -s ---> s = 15/4

        Then d = 10( 4 -s ) = 10 (4 - 15/4) = 10/4 km

        time taken for C to meet D = d/(10-s) = (10/4) / (10 - 15/4) = 10/25 = 2/5 hours.

        HTH

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        • I Offline
          iFruit
          last edited by

          deleted

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          • M Offline
            Maths Hub
            last edited by

            Vanilla Cake:
            Thks to Maths Hub and iFruit for your detailed and clear solutions. Sorry, some more questions from APMOPS 2005 that need your help.


            Q3
            The following number is made up of all the digits of the whole numbers 1 to 2005.
            12345678910111213141516..........20042005
            Find the number of zeros in this number.

            From 1 to 99-->'0' appears 9 times.
            From 100 to 199-->'0' appears 20 times.
            Similarly, from 200 to 299 -->'0' appears 20 times.

            So from 100 to 999 --> '0' appears 20x9=180 times

            From 1000 to 1999 --> '0' appears 100 times in the hundred digit place, 100 times in the ten digit place, 100 times in the ones digit place. Hence total = 300

            From 2000 to 2005 --> '0' appears 13 times.

            Total '0': 9+180+300+13=502

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            • N Offline
              noob
              last edited by

              Need solution for following question, please help tks


              Alice, Betty and Cecilia shared the cost of a present. Alice paid 1/3 of the total amount of money paid by Betty and Cecilia. Betty paid 1/8 of the amount of money paid by Alice and Cecilia. Alice paid $60 less than Cecilia.
              (a) How much did Betty pay?
              (b) What was the cost of the present?

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              • D Offline
                Daddy
                last edited by

                Hi,


                Need help!

                1. Chloe has a box of beads. 2/7 of the beads are white and the rest are blue and orange beads. The ratio of the number of white beads to the number of blue beads is 6:5. find the ratio of the number of blue beads to orange beads. Give your answer in the simplest form.

                Thanks…
                Daddy.

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                • I Offline
                  iFruit
                  last edited by

                  Daddy:
                  Hi,


                  Need help!

                  1. Chloe has a box of beads. 2/7 of the beads are white and the rest are blue and orange beads. The ratio of the number of white beads to the number of blue beads is 6:5. find the ratio of the number of blue beads to orange beads. Give your answer in the simplest form.

                  Thanks..
                  Daddy.
                  2/7 beads are white. So White: (blue+orange) = 2:5 = 6:15

                  white: Blue = 6:5

                  Observing the above two ratios we deduce

                  whilte:blue:orange = 6:5:10

                  So blue:orange = 5:10 = 1:2

                  1 Reply Last reply Reply Quote 0
                  • I Offline
                    iFruit
                    last edited by

                    noob:
                    Need solution for following question, please help tks


                    Alice, Betty and Cecilia shared the cost of a present. Alice paid 1/3 of the total amount of money paid by Betty and Cecilia. Betty paid 1/8 of the amount of money paid by Alice and Cecilia. Alice paid $60 less than Cecilia.
                    (a) How much did Betty pay?
                    (b) What was the cost of the present?
                    Is there a typo in the question? Perhaps \"Alice paid $70 less than Cecilia\"?

                    Below is working assuming \"Alice paid $70 less than Cecilia\". With $60, it is the same working but we end up with all fractions

                    Alice = A, Betty = B and Cecilia = C.

                    A = 1/3 (B +C) ----> 3A = B+C ---------(1)
                    B = 1/8 (A+C) -----> 8B = A+C ---------(2)
                    C = A + 70---(3)

                    Substituting (3) in (1) and (2) we get

                    3A = B+A+70 -----> 2A = B+70
                    8B = A +A +70----> 8B = 2A +70

                    From the above two we get, 8B = B+70+70 or B = 20

                    The A = 45, C = 115, Total = 115+45+20 = 180

                    HTH

                    1 Reply Last reply Reply Quote 0
                    • N Offline
                      noob
                      last edited by

                      iFruit:
                      noob:

                      Need solution for following question, please help tks


                      Alice, Betty and Cecilia shared the cost of a present. Alice paid 1/3 of the total amount of money paid by Betty and Cecilia. Betty paid 1/8 of the amount of money paid by Alice and Cecilia. Alice paid $60 less than Cecilia.
                      (a) How much did Betty pay?
                      (b) What was the cost of the present?

                      Is there a typo in the question? Perhaps \"Alice paid $70 less than Cecilia\"?

                      Below is working assuming \"Alice paid $70 less than Cecilia\". With $60, it is the same working but we end up with all fractions

                      Alice = A, Betty = B and Cecilia = C.

                      A = 1/3 (B +C) ----> 3A = B+C ---------(1)
                      B = 1/8 (A+C) -----> 8B = A+C ---------(2)
                      C = A + 70---(3)

                      Substituting (3) in (1) and (2) we get

                      3A = B+A+70 -----> 2A = B+70
                      8B = A +A +70----> 8B = 2A +70

                      From the above two we get, 8B = B+70+70 or B = 20

                      The A = 45, C = 115, Total = 115+45+20 = 180

                      HTH

                      No typo error, answer (a) $12 (b) $108

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                      • D Offline
                        Daddy
                        last edited by

                        Hi Ifruit,

                        [quote]2/7 beads are white. So White: (blue+orange) = 2:5 = 6:15

                        white: Blue = 6:5

                        Observing the above two ratios we deduce

                        whilte:blue:orange = 6:5:10
                        [/quote]Compare set of ratio of White & Blue to White , blue & orange.

                        first:
                        White : blue+Orange
                        ....... 2 : 5

                        given:
                        White : Blue
                        ___ 6 :5

                        X3 =>White : blue+Orange
                        ........ 6 : 15
                        seperate blue & orange
                        White : Blue : Orange
                        ___ 6 : 5 : 10

                        reduce ratio of Blue & Orange = 1:2

                        Thanks ..

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