Tutor MathsGuru: Ask me for your burning Maths questions!

[Daddy]

Hi,


Pls help…

1. Henry and Timmy had a total of $940. After Henry spent 3/7 of his money and Timmy spent $180, Timmy had 5/8 as much money as henry. how much money did Henry hsve st first ?

2. Siti has 720 beads. 45% of them are pink and the rest are blue. If she decides to buy some more pink beads so that the number of pink beads is increased to 75% of the total number of beads, how many more pink beads must she buy?

Thanks…
Daddy

[Mathmaniac]

Daddy:

Hi,


Pls help..

1. Henry and Timmy had a total of $940. After Henry spent 3/7 of his money and Timmy spent $180, Timmy had 5/8 as much money as henry. how much money did Henry hsve st first ?

2. Siti has 720 beads. 45% of them are pink and the rest are blue. If she decides to buy some more pink beads so that the number of pink beads is increased to 75% of the total number of beads, how many more pink beads must she buy?

Thanks..
Daddy

1. After spending 3/7, Henry has 4/7=16/28 left.
Timmy has 5/8 of Henry = 10/16
Total units = 10+28=38
$940-$180=$760
1 unit=$760/38=$20
Henry has 28x$20=$560 at first.

[Mathmaniac]

Daddy:

Hi,


2. Siti has 720 beads. 45% of them are pink and the rest are blue. If she decides to buy some more pink beads so that the number of pink beads is increased to 75% of the total number of beads, how many more pink beads must she buy?

Thanks..
Daddy

45%x720=324 pink
720x75%=540
540-324=216
25%x?=216
?=864

[wkong]

Hi All,


Need help for the following questions:-

1. A group of pupils helped to carry bundles of newspapers from a lorry to a storeroom. The number of girls was of the number of boys. Each boy \tcarried 260 more bundles of newspapers than the girls in all.
\t(a)\tHow many pupils were there in the group?
\t(b)\tHow many bundles of newspapers were collected?

2. Box A contains only 20-cent coins and Box B contains only 50-cent coins. The number of coins in Box A is twice that in Box B. The amount of \tmoney in Box B is $1.80 more than that in Box A. How much money is \tthere in Box A?

3. Joan and Reena shared a sum of money. Joan’s share was $180 less \tthan Reena’s. After Reena had given of her share to Joan, Joan had $20 more than Reena. How much did Joan had at first?


Thanks,
WKong

[Mathmaniac]

wkong:

Hi All,


Need help for the following questions:-

1. A group of pupils helped to carry bundles of newspapers from a lorry to a storeroom. The number of girls was of the number of boys. Each boy \tcarried 260 more bundles of newspapers than the girls in all.
\t(a)\tHow many pupils were there in the group?
\t(b)\tHow many bundles of newspapers were collected?

2. Box A contains only 20-cent coins and Box B contains only 50-cent coins. The number of coins in Box A is twice that in Box B. The amount of \tmoney in Box B is $1.80 more than that in Box A. How much money is \tthere in Box A?

3. Joan and Reena shared a sum of money. Joan’s share was $180 less \tthan Reena’s. After Reena had given of her share to Joan, Joan had $20 more than Reena. How much did Joan had at first?


Thanks,
WKong

1. Insufficient info.

2. Question wrong.

3. Insufficient info.

[wkong]

Mathmaniac:

wkong:

Hi All,


Need help for the following questions:-

1. A group of pupils helped to carry bundles of newspapers from a lorry to a storeroom. The number of girls was of the number of boys. Each boy \tcarried 260 more bundles of newspapers than the girls in all.
\t(a)\tHow many pupils were there in the group?
\t(b)\tHow many bundles of newspapers were collected?

2. Box A contains only 20-cent coins and Box B contains only 50-cent coins. The number of coins in Box A is twice that in Box B. The amount of \tmoney in Box B is $1.80 more than that in Box A. How much money is \tthere in Box A?

3. Joan and Reena shared a sum of money. Joan’s share was $180 less \tthan Reena’s. After Reena had given of her share to Joan, Joan had $20 more than Reena. How much did Joan had at first?


Thanks,
WKong

1. Insufficient info.

2. Question wrong.

3. Insufficient info.

Oh, those were the questions given by my boy's sch teacher which I just copy and paste. That is why he couldnt figure out how to do...

[tianzhu]

wkong:

2. Box A contains only 20-cent coins and Box B contains only 50-cent coins. The number of coins in Box A is twice that in Box B. The amount of money in Box B is $1.80 more than that in Box A. How much money is there in Box A?

Hi

You may use Guess and check or Number*Value method to solve Q2.

You'll get 36 number of 20 cents coin and 18 number of 50 cents coin, making a difference of $1.80(more of 50 cents).

The answer is $7.20.

Best wishes

[Mathmaniac]

tianzhu:

[quote]2. Box A contains only 20-cent coins and Box B contains only 50-cent coins. The number of coins in Box A is twice that in Box B. The amount of money in Box B is $1.80 more than that in Box A. How much money is there in Box A?

Hi

You may use Guess and check or Number*Units to solve Q2.

You'll get 36 number of 20 cents coin and 18 number of 50 cents coin, making a difference of $1.80(more of 50 cents).

The answer is $7.20.

Best wishes[/quote]Sorry, I read the question wrongly. I thought the question said the amount of money in A is more than B, which is impossible.

A faster way of doing:

$0.20x2=$0.40
For 1 50 cent coin in B, you have 2 20 cents coins in A, and a difference of 50-40=10 cents.
So for 1.80 difference, you take 1.80/0.10=18 coins in B
So u have 2x18=36 coins in A.
36x$0.20=$7.20

[Daddy]

Hi mathmaniac,

thanks. but I do not understand. for Q1 4/7 became 16/28???.
and Q2. any model???
Thx

[wkong]

Mathmaniac:

tianzhu:

[quote]2. Box A contains only 20-cent coins and Box B contains only 50-cent coins. The number of coins in Box A is twice that in Box B. The amount of money in Box B is $1.80 more than that in Box A. How much money is there in Box A?

Hi

You may use Guess and check or Number*Units to solve Q2.

You'll get 36 number of 20 cents coin and 18 number of 50 cents coin, making a difference of $1.80(more of 50 cents).

The answer is $7.20.

Best wishes

Sorry, I read the question wrongly. I thought the question said the amount of money in A is more than B, which is impossible.

A faster way of doing:

$0.20x2=$0.40
For 1 50 cent coin in B, you have 2 20 cents coins in A, and a difference of 50-40=10 cents.
So for 1.80 difference, you take 1.80/0.10=18 coins in B
So u have 2x18=36 coins in A.
36x$0.20=$7.20[/quote]Thanks Mathmaniac and tianzhu for solving Qn 2.