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    Tutor MathsGuru: Ask me for your burning Maths questions!

    Scheduled Pinned Locked Moved Primary Schools - Academic Support
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    • R Offline
      rain29
      last edited by

      Hi,


      I need help for the following questions with drawing model.

      1) Tom and Jerry had equal amount of money at first. After Tom spent $8 and Jerry spent $32. Tom had 4 times as much as Jerry. How much did Tom have at first?


      2) John had $130 and Elicia had $88 at first. After they each spent an equal amount of money. John had 4 times as much money as Elicia. How much money did each of them spend?

      Thanks in advance.

      1 Reply Last reply Reply Quote 0
      • lostbunnyL Offline
        lostbunny
        last edited by

        kwcllf:
        Hi,


        Please help with the following question.

        Peter, Mary and Sam have a total of $1,200. If Peter gave them $25 each, Peter and Mary would have a total amount which was $10 less than Sam. Given that Sam originally had 4 times as much money as Mary, how much did Peter have originally?

        Thanks!
        Kwcif,

        My DH insist I post this answer that he worked out.

        P + M -10= S = 1200
        595 = 605 ( this is the only combination where the diff is by 10)

        S=605-25=580s/4=145M
        1200-580S-145M= 475P

        Prove
        475P-50=425P
        145M+25=170M
        575PM
        580S+25=605S

        Maths guru, is this correct?

        1 Reply Last reply Reply Quote 0
        • autolycusA Offline
          autolycus
          last edited by

          kwcllf:
          Hi,


          Please help with the following question.

          Peter, Mary and Sam have a total of $1,200. If Peter gave them $25 each, Peter and Mary would have a total amount which was $10 less than Sam. Given that Sam originally had 4 times as much money as Mary, how much did Peter have originally?

          Thanks!
          Originally:
          Mary has $M
          Sam has 4 x $M
          Peter has $1,200 - 5 x $M

          Then Peter gets generous.

          This becomes:
          Peter has $1200 - 5 x $M - $25 - $25
          Mary has $M + $25
          Sam has 4 x $M + $25

          But to put it another way...

          Sam also has Peter's money + Mary's money + $10
          = $1200 - 5 x $M - $50 + $M + $25 + $10
          = $1200 - $50 + $25 + $10 - 5 x $M + $M
          = $1185 - 4 x $M

          So Sam's money can be expressed in 2 ways but must be the same:

          4 x $M + $25 = $1185 - 4 x $M
          4 x $M + $25 + 4 x $M = $1185
          8 x $M = $1185 - $25 = $1160

          So $M = $1160/8 = $145

          Conclusion:
          Mary started with $M = $145
          Sam started with 4 x $M = 4 x $145 = $580
          Peter had the balance = $1200 - $580 - $145 = $475

          After Peter gave them each $25,
          Mary had $170
          Sam had $605
          Peter had $425

          1 Reply Last reply Reply Quote 0
          • Y Offline
            Yu Xuan
            last edited by

            rain29:
            Hi,


            I need help for the following questions with drawing model.

            1) Tom and Jerry had equal amount of money at first. After Tom spent $8 and Jerry spent $32. Tom had 4 times as much as Jerry. How much did Tom have at first?


            2) John had $130 and Elicia had $88 at first. After they each spent an equal amount of money. John had 4 times as much money as Elicia. How much money did each of them spend?

            Thanks in advance.
            Hi

            Question 1

            Tom --> [ ][ ][ ][ ][$8]
            Jery --> [ ][....$32.....]

            3 units --> $32 - $8 = $24
            1 unit --> $24 / 3 = $8
            4 units --> $8 * 4 = $32

            $32 + $8 = $ 40

            Question 2

            Jo --> [Spent][ ][ ][ ][ ]
            El --> [Spent][ ]

            3 units --> $130 - $88 = $42
            1 unit --> $42 / 3 = $14

            Using Elicia;
            $88 - $14 = $ 74

            1 Reply Last reply Reply Quote 0
            • Y Offline
              Yu Xuan
              last edited by

              kwcllf:
              Hi,


              Please help with the following question.

              Peter, Mary and Sam have a total of $1,200. If Peter gave them $25 each, Peter and Mary would have a total amount which was $10 less than Sam. Given that Sam originally had 4 times as much money as Mary, how much did Peter have originally?

              Thanks!
              Hi

              After transfer;
              Sam --> 4 units + $25
              Mary --> 1 unit + $25

              Since Peter & Mary would have $10 less than Sam, Peter & Mary should have;
              4 units + $25 - $10 = 4 units + $15

              If Mary has 1 unit + $25, then Peter should have;
              4 units + $15 - 1 unit - $25 = 3 units - $10

              To find out what Peter started off with, we need to add back the $50 which he transferred to Sam & Mary;
              3 units - $10 + $50 = 3 units + $40

              Using the $1200 which 3 of them started off with;
              4u + 1u + 3u + $40 --> $1200
              8u --> $1200 - $40 = $1160
              1u --> $1160 / 8 = $145

              Peter at first --> 3u + 40 = [ 3*$145 ] + $40 = $475

              1 Reply Last reply Reply Quote 0
              • R Offline
                rain29
                last edited by

                Hi Yu Xuan,


                Thanks for your help.

                I can get the answer but my daughter dun understand with my explanation. I will explain to her using your method, hope she can understand better.

                1 Reply Last reply Reply Quote 0
                • Y Offline
                  Yu Xuan
                  last edited by

                  rain29:
                  Hi Yu Xuan,


                  Thanks for your help.

                  I can get the answer but my daughter dun understand with my explanation. I will explain to her using your method, hope she can understand better.
                  Hi Rain

                  The pleasure is mine. Nice day.

                  Yu Xuan

                  1 Reply Last reply Reply Quote 0
                  • K Offline
                    kwcllf
                    last edited by

                    Hi All,


                    Thanks for the great help. I managed to do it using the Model method as my P5 kid can understand better.

                    Please see below (Sorry, can’t get it into alignment)

                    M--------[135][10]

                    S--------[135][10][135][10][135][10][135][10][15][10]
                    P+M---- [135][10][135][10][135][10][135][10][15]


                    From the above model (taking into account of S & P+M only):

                    $1200 – (9 x $10) – (2 x$ 15) = $1080
                    $1080 ÷ 8 = $135

                    Therefore originally,
                    Sam = (4 x $135) + (4 x $10) = $580
                    Mary = $135 + $10 = $145
                    Peter = $(1200 – 580 – 145 ) = $475

                    1 Reply Last reply Reply Quote 0
                    • A Offline
                      andante
                      last edited by

                      Pls help for the following question. I have solved it using algebra simultaneous equations but I heard that the pupils cannot use this method to solve during PSLE exam or else marks will be deducted.



                      20% of the number of balls Kyle had is equal to the 35% of the number Pauline had. After Kyle sold another 30 marbles and Pauline bought 20 marbles, 30% of the number of marbles Kyle had is equal to the 50% of the number Pauline had. What is the number of marbles each of them had at first?

                      Thanks in advance

                      1 Reply Last reply Reply Quote 0
                      • M Offline
                        meimeitan
                        last edited by

                        Hi Maths Guru


                        There is a Math question as following:

                        There were 12 more girls than boys in a club. 1/3 of the girls and 1/4 of the boys took part in a competition. Among those who took part in the competition, there were 6 more girls than boys. What fraction of the club members who did not take part in the competition were boys?

                        May I know the meaning of "What fraction of the club members who did not take part in the competition were boys.?" The denominator should be the whole club members or the club members who did not join the competition.

                        Thanks

                        1 Reply Last reply Reply Quote 0

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