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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • T Offline
      tianzhu
      last edited by

      LaiHeng:
      2. A bag contains 200 blue balls and 450 yellow balls. A tin contains 850 blue and 340 yellow balls. After some blue and yellow balls are moved from the tin to the bag, the percentage of the blue balls in the bag becomes 50% and the blue balls in the tin becomes 70%.

      a)How many blue balls are moved from the tin to the bag?
      b)How many yellow balls are moved from the tin to the bag?
      Hi

      In answering this question, a student should note that the total number of blue and yellow balls remains the same in the before and after scenarios.

      Before
      Bag
      Blue ----- 200
      Yellow ----- 450

      Tin
      Blue ----- 850
      Yellow ----- 340

      Total number of blue balls ------ 200+850 ------1050
      Total number of yellow balls ------ 450+340 ------790

      After
      Bag
      Blue ----- 1 unit
      Yellow ----- 1 unit

      Tin
      Blue ----- 7 parts
      Yellow ----- 3 parts

      Here, we’ve two equations with two variables, and we cannot run away from simultaneous equations.

      Some students may find it difficult to grasp SE concepts; the challenge is to help the less mathematically inclined students deal with such handicaps.

      Needless to say, students who have learned SE from external courses or their parents would go ahead with SE.

      Students who are able to grasp SE concepts may use letters of the alphabets to solve the equations or work using units and parts to represent the quantities of the blue and yellow balls as shown above.

      Let’s begin.

      1 unit + 7 parts ------1050
      1 unit + 3 parts ------ 790
      4 parts ------ 260

      Tin
      Yellow ------ 3 part ----- 3*65 ------ 195
      Blue ------ 7 parts ---- 7*65 ----- 455

      a)How many blue balls are moved from the tin to the bag?
      850 – 455 ------ 395


      b)How many yellow balls are moved from the tin to the bag?
      340 – 195 ------- 145

      For those students who have difficulties understanding SE, you may solve it by visualising such equations in pictorial form.

      Please help to check the calculations as they had been done in a rush.

      Best wishes

      1 Reply Last reply Reply Quote 0
      • ozoraO Offline
        ozora
        last edited by

        tianzhu:
        Hi LaiHeng


        Good Morning.

        Here's the solution to Q1.

        Hope this helps.

        Best wishes

        http://farm6.static.flickr.com/5095/5490097769_cb20f73bac_b.jpg\">
        thanks
        the explanation for both questions are clear. I really got a lot to learn from you.

        1 Reply Last reply Reply Quote 0
        • ozoraO Offline
          ozora
          last edited by

          tianzhu:
          LaiHeng:

          2. A bag contains 200 blue balls and 450 yellow balls. A tin contains 850 blue and 340 yellow balls. After some blue and yellow balls are moved from the tin to the bag, the percentage of the blue balls in the bag becomes 50% and the blue balls in the tin becomes 70%.

          a)How many blue balls are moved from the tin to the bag?
          b)How many yellow balls are moved from the tin to the bag?

          Hi

          In answering this question, a student should note that the total number of blue and yellow balls remains the same in the before and after scenarios.

          Before
          Bag
          Blue ----- 200
          Yellow ----- 450

          Tin
          Blue ----- 850
          Yellow ----- 340

          Total number of blue balls ------ 200+850 ------1050
          Total number of yellow balls ------ 450+340 ------790

          After
          Bag
          Blue ----- 1 unit
          Yellow ----- 1 unit

          Tin
          Blue ----- 7 parts
          Yellow ----- 3 parts

          Here, we’ve two equations with two variables, and we cannot run away from simultaneous equations.

          Some students may find it difficult to grasp SE concepts; the challenge is to help the less mathematically inclined students deal with such handicaps.

          Needless to say, students who have learned SE from external courses or their parents would go ahead with SE.

          Students who are able to grasp SE concepts may use letters of the alphabets to solve the equations or work using units and parts to represent the quantities of the blue and yellow balls as shown above.

          Let’s begin.

          1 unit + 7 parts ------1050
          1 unit + 3 parts ------ 790
          4 parts ------ 260

          Tin
          Yellow ------ 3 part ----- 3*65 ------ 195
          Blue ------ 7 parts ---- 7*65 ----- 455

          a)How many blue balls are moved from the tin to the bag?
          850 – 455 ------ 395


          b)How many yellow balls are moved from the tin to the bag?
          340 – 195 ------- 145

          For those students who have difficulties understanding SE, you may solve it by visualising such equations in pictorial form.

          Please help to check the calculations as they had been done in a rush.

          Best wishes

          thanks for the prompt help.

          1 Reply Last reply Reply Quote 0
          • T Offline
            tianzhu
            last edited by

            LaiHeng:
            thanks

            the explanation for both questions are clear. I really got a lot to learn from you.
            Hi

            You're welcome.

            Best wishes

            1 Reply Last reply Reply Quote 0
            • ozoraO Offline
              ozora
              last edited by

              Hi

              I managed to solve this question but I wonder is there a another method.
              The question is as follows: There are 80 apples and oranges in a basket. 2/5 of the oranges and 2/3 of the apples are eaten. In the end, they are 36 fruits left. How many oranges were there at first?

              I used SE concepts to solve it : 2/5o+ 2/3a=44----eq1
              3/50+ 1/3a=36-----eq2
              I managed to get 35 oranges.

              Is it possible to use model to get the answer? If so how? Thanks

              1 Reply Last reply Reply Quote 0
              • A Offline
                ADoc
                last edited by

                LaiHeng:
                Hi

                I managed to solve this question but I wonder is there a another method.
                The question is as follows: There are 80 apples and oranges in a basket. 2/5 of the oranges and 2/3 of the apples are eaten. In the end, they are 36 fruits left. How many oranges were there at first?

                I used SE concepts to solve it : 2/5o+ 2/3a=44----eq1
                3/50+ 1/3a=36-----eq2
                I managed to get 35 oranges.

                Is it possible to use model to get the answer? If so how? Thanks
                Hi! Since model is algebra (including SE) in disguise, so we can still use the so-called model method to help the students visualise this problem instead of calling it SE. So instead of using \"O\" and \"A\", we can always use the pictorial form. Also, I think students are more familiar & comfortable manipulating whole numbers compared to fractions (SE or model).

                Here's a quick diagram so to speak. We can always translate to \"models\" to aid visualisation. not sure if this will be helpful. cheers!

                Original
                oranges [ ] [ ] [ ] [ ] [ ]
                apples { } { } { }

                [ ] [ ] [ ] [ ] [ ] + { } { } { } = 80 fruits
                or 5 [ ] + 3 { } = 80 fruits

                after eating 2/5 oranges & 2/3 apples
                oranges [ ] [ ] [ ]
                apples { }

                [ ] [ ] [ ] + { } \t\t = 36 fruits

                [ ] [ ] [ ] [ ] [ ] [ ] [ ] [ ] [ ] + { } { } { } \t= 36 x 3 = 108 fruits
                |-------------9---------------| |----3-----|
                or 9 [ ] + 3 { } = 108 fruits

                subtracting original of 5 [ ] & 3 { }, we have:
                therefore 4 [ ] = 108 - 80 = 28
                1 [ ] = 7
                therefore 5 [ ] = 5 x 7 = 35 oranges at first

                1 Reply Last reply Reply Quote 0
                • T Offline
                  tianzhu
                  last edited by

                  LaiHeng:
                  Hi

                  I managed to solve this question but I wonder is there a another method.

                  The question is as follows: There are 80 apples and oranges in a basket. 2/5 of the oranges and 2/3 of the apples are eaten. In the end, they are 36 fruits left. How many oranges were there at first?

                  I used SE concepts to solve it : 2/5o+ 2/3a=44----eq1
                  3/50+ 1/3a=36-----eq2
                  I managed to get 35 oranges.

                  Is it possible to use model to get the answer? If so how? Thanks
                  Hi

                  Besides solving SE in algebraic manipulation, alphabet method or in pictorial form, you may also solve this question with Systematic Listing.

                  SL is less efficient but may offer a lifeline for less mathematically inclined students. It may take a bit more time but it’ll give one precious few marks as long as a student is able to have the patience to list down the equivalent fractions in a systematic manner.

                  But, use it as a last resort, .... imagine a striker or midfielder taking long shots at goals in the dying minutes of the game hoping for that elusive winning goal or equaliser.

                  Best wishes

                  1 Reply Last reply Reply Quote 0
                  • ozoraO Offline
                    ozora
                    last edited by

                    tianzhu:
                    LaiHeng:

                    Hi

                    I managed to solve this question but I wonder is there a another method.

                    The question is as follows: There are 80 apples and oranges in a basket. 2/5 of the oranges and 2/3 of the apples are eaten. In the end, they are 36 fruits left. How many oranges were there at first?

                    I used SE concepts to solve it : 2/5o+ 2/3a=44----eq1
                    3/5o+ 1/3a=36-----eq2
                    I managed to get 35 oranges.

                    Is it possible to use model to get the answer? If so how? Thanks

                    Hi

                    Besides solving SE in algebraic manipulation, alphabet method or in pictorial form, you may also solve this question with Systematic Listing.

                    SL is less efficient but may offer a lifeline for less mathematically inclined students. It may take a bit more time but it’ll give one precious few marks as long as a student is able to have the patience to list down the equivalent fractions in a systematic manner.

                    But, use it as a last resort, .... imagine a striker or midfielder taking long shots at goals in the dying minutes of the game hoping for that elusive winning goal or equaliser.

                    Best wishes

                    is alphabet method the same as my stated method?
                    thanks for answering Tianzhu.

                    1 Reply Last reply Reply Quote 0
                    • T Offline
                      tianzhu
                      last edited by

                      LaiHeng:
                      is alphabet method the same as my stated method?
                      Hi LaiHeng

                      Good Morning.

                      No, I think your method is geared more towards manipulation of algebraic fractions.

                      Aiyo, memory jammed early in the morning, I cannot recall where this term ”alphabet method” surface from. Jialat, really a sign of old age.

                      Anyway , we are using the letters of the alphabet to represent units and parts because the fractions for apples and oranges are of different measures.

                      There are 80 apples and oranges in a basket. 2/5 of the oranges and 2/3 of the apples are eaten. In the end, they are 36 fruits left. How many oranges were there at first?

                      1O represents 1 unit of oranges and 1A represent 1 part of apples.

                      2O+2A ------ 44
                      3O+1A ------ 36

                      Representing the equations in this form avoids working with fractions in the calculations.

                      We have
                      1O+1A ------22
                      2O ------36-22-----14
                      1O ------7
                      5O ------ 35.

                      A student may translate these equations into pictorial method if he prefers.

                      Do not be too particular about the names of the terms, different books may call the same term different names. What’s more important is that a child is able to apply the concepts to solve questions.

                      Let the child take the method he/she is most comfortable with to the exam hall.

                      Best wishes

                      1 Reply Last reply Reply Quote 0
                      • ozoraO Offline
                        ozora
                        last edited by

                        tianzhu:
                        LaiHeng:

                        is alphabet method the same as my stated method?

                        Hi LaiHeng

                        Good Morning.

                        No, I think your method is geared more towards manipulation of algebraic fractions.

                        Aiyo, memory jammed early in the morning, I cannot recall where this term ”alphabet method” surface from. Jialat, really a sign of old age.

                        Anyway , we are using the letters of the alphabet to represent units and parts because the fractions for apples and oranges are of different measures.

                        There are 80 apples and oranges in a basket. 2/5 of the oranges and 2/3 of the apples are eaten. In the end, they are 36 fruits left. How many oranges were there at first?

                        1O represents 1 unit of oranges and 1A represent 1 part of apples.

                        2O+2A ------ 44
                        3O+1A ------ 36

                        Representing the equations in this form avoids working with fractions in the calculations.

                        We have
                        1O+1A ------22
                        2O ------36-22-----14
                        1O ------7
                        5O ------ 35.

                        A student may translate these equations into pictorial method if he prefers.

                        Do not be too particular about the names of the terms, different books may call the same term different names. What’s more important is that a child is able to apply the concepts to solve questions.

                        Let the child take the method he/she is most comfortable with to the exam hall.

                        Best wishes

                        thanks for the clear explanation

                        1 Reply Last reply Reply Quote 0

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