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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • ozoraO Offline
      ozora
      last edited by

      ADoc:
      LaiHeng:

      Hi

      I managed to solve this question but I wonder is there a another method.
      The question is as follows: There are 80 apples and oranges in a basket. 2/5 of the oranges and 2/3 of the apples are eaten. In the end, they are 36 fruits left. How many oranges were there at first?

      I used SE concepts to solve it : 2/5o+ 2/3a=44----eq1
      3/50+ 1/3a=36-----eq2
      I managed to get 35 oranges.

      Is it possible to use model to get the answer? If so how? Thanks

      Hi! Since model is algebra (including SE) in disguise, so we can still use the so-called model method to help the students visualise this problem instead of calling it SE. So instead of using \"O\" and \"A\", we can always use the pictorial form. Also, I think students are more familiar & comfortable manipulating whole numbers compared to fractions (SE or model).

      Here's a quick diagram so to speak. We can always translate to \"models\" to aid visualisation. not sure if this will be helpful. cheers!

      Original
      oranges [ ] [ ] [ ] [ ] [ ]
      apples { } { } { }

      [ ] [ ] [ ] [ ] [ ] + { } { } { } = 80 fruits
      or 5 [ ] + 3 { } = 80 fruits

      after eating 2/5 oranges & 2/3 apples
      oranges [ ] [ ] [ ]
      apples { }

      [ ] [ ] [ ] + { } \t\t = 36 fruits

      [ ] [ ] [ ] [ ] [ ] [ ] [ ] [ ] [ ] + { } { } { } \t= 36 x 3 = 108 fruits
      |-------------9---------------| |----3-----|
      or 9 [ ] + 3 { } = 108 fruits

      subtracting original of 5 [ ] & 3 { }, we have:
      therefore 4 [ ] = 108 - 80 = 28
      1 [ ] = 7
      therefore 5 [ ] = 5 x 7 = 35 oranges at first

      Adoc thanks for the pictorial explanation. Must really get use of using this approach to teach the children.

      1 Reply Last reply Reply Quote 0
      • T Offline
        tianzhu
        last edited by

        ozora:
        thanks for the clear explanation

        Hi

        You're welcome.

        Best wishes

        1 Reply Last reply Reply Quote 0
        • I Offline
          is_me_lblue
          last edited by

          Hi,


          Question as follow :

          The ratio of the area of A to B is 1:2. If 30% of B overlaps with A, what percentage of the whole figure is not overlapped ?

          Thk u

          Anwer given is 75%.

          1 Reply Last reply Reply Quote 0
          • B Offline
            Belle2011
            last edited by

            is_me_lblue:
            Hi,


            Question as follow :
            The ratio of the area of A to B is 1:2. If 30% of B overlaps with A, what percentage of the whole figure is not overlapped ?
            Thk u
            Anwer given is 75%.
            I try to explain as detailed as possble because I do not know how to insert a diagram which speaks a thousand words.
            B is a bigger circle as compared to A.
            The overlapping area is 30% of B and thus put 3 in that overlapping area and the remaining of B will be 7. Since A:B is 1:2, the total parts for A will be 5 and since the overlapped area is 3, the not overlapped of A is 2.

            Total parts = 7+3+2 = 12.
            Total Not Overlapped parts = 7+2 = 9.

            9/12 = 75%.

            Cheers,
            Belle.

            1 Reply Last reply Reply Quote 0
            • A Offline
              ADoc
              last edited by

              ozora:


              Adoc thanks for the pictorial explanation. Must really get use of using this approach to teach the children.
              cheers! Hope it's useful..

              1 Reply Last reply Reply Quote 0
              • A Offline
                ADoc
                last edited by

                Belle2011:
                is_me_lblue:

                Hi,


                Question as follow :
                The ratio of the area of A to B is 1:2. If 30% of B overlaps with A, what percentage of the whole figure is not overlapped ?
                Thk u
                Anwer given is 75%.

                I try to explain as detailed as possble because I do not know how to insert a diagram which speaks a thousand words.
                B is a bigger circle as compared to A.
                The overlapping area is 30% of B and thus put 3 in that overlapping area and the remaining of B will be 7. Since A:B is 1:2, the total parts for A will be 5 and since the overlapped area is 3, the not overlapped of A is 2.

                Total parts = 7+3+2 = 12.
                Total Not Overlapped parts = 7+2 = 9.

                9/12 = 75%.

                Cheers,
                Belle.

                Hi is_me_Iblue!
                just a \"rough\" diagram. Hope this is useful for your visualisation.

                cheers!
                ADoc
                http://postimage.org/image/312yr9mpw/

                1 Reply Last reply Reply Quote 0
                • E Offline
                  Emelyn
                  last edited by

                  Hi,


                  Brain jammed....cannot solve the problem. Sign of old age too....
                  Asking for help here .......


                  http://postimage.org/image/2kyiwxjj8/

                  In the figure above, which is not drawn to scale, 1/4 of the circle is shaded. The ratio of the area of the square to the area of the rectangle and circle is 5:7. 40% of the square is shaded. 1/3 of the rectangle is shaed. What is the ratio of the area of the circle to the square to the rectangle ?

                  MTIA !!

                  1 Reply Last reply Reply Quote 0
                  • P Offline
                    pixiedust
                    last edited by

                    Appreciate help with the following question.


                    My solution is using listing multiples method.
                    Is there a faster way?
                    Such questions, analysing the gap (like the oranges question) doesn't work?

                    Some NCC cadets are gathered in a hall.
                    If they are grouped into 7 cadets in a team, there will be 4 cadets left out.
                    If they are grouped into 9 cadets in a team, there will be 6 cadets left out.
                    How many cadets are there in the hall if the number of cadets is between 20 and 70 ?

                    1 Reply Last reply Reply Quote 0
                    • T Offline
                      tianzhu
                      last edited by

                      Emelyn:
                      Hi,


                      Brain jammed....cannot solve the problem. Sign of old age too....
                      Asking for help here .......


                      http://postimage.org/image/2kyiwxjj8/

                      In the figure above, which is not drawn to scale, 1/4 of the circle is shaded. The ratio of the area of the square to the area of the rectangle and circle is 5:7. 40% of the square is shaded. 1/3 of the rectangle is shaed. What is the ratio of the area of the circle to the square to the rectangle ?

                      MTIA !!
                      Hi

                      In this question, the units are in pretty nice numbers.

                      You may use Units Method or MD.

                      Circle
                      Shaded ----- 1 unit
                      Unshaded ------ 3 units
                      Total -------4 units

                      Rectangle
                      Shaded ----- 1 unit
                      Unshaded ------ 2 units
                      Total ------- 3 units

                      Square
                      Shaded ----- 2 unit
                      Unshaded ------ 3 units
                      Total --------5 units

                      C:S:R ------4:5:3

                      Now you may wish to try this one.

                      Best wishes

                      http://farm3.static.flickr.com/2407/2673911274_a92537168a_o.jpg\">

                      1 Reply Last reply Reply Quote 0
                      • T Offline
                        tianzhu
                        last edited by

                        pixiedust:
                        Appreciate help with the following question.

                        My solution is using listing multiples method.
                        Is there a faster way?
                        Such questions, analysing the gap (like the oranges question) doesn't work?
                        Hi

                        Systematic listing of multiples is commonly used by primary students to solve this question.

                        Best wishes

                        1 Reply Last reply Reply Quote 0

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