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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • M Offline
      mrswongtuition
      last edited by

      Drdj:
      Hi, could you explain this Andrew Er Assessment Book question to me?


      THe question is $1,120 was spent on pots and pans. 1 Pan is $20, 1 Pot is $60. 8 more pans than pots were bought. How many pots and pans were bought?

      Using algebra, and solving 2 simultaneous equtions - 20x + 60 y = 1,120
      and x -y = 8 (where x = no. of pots), I get y = 12, and x = 20 (Which is the book's answer)

      Using this method,
      Difference in cost of pans = $20 x 8 pans = $160
      1 unit = cost of pots
      Hence, 1 unit + $160 = cost of pans
      Hence 1 unit = cost of pots = ($1,120 - $160) / 2 = $480

      No. of pots = $480/$60 = 8, No. of pans = $640/$20=32
      But this is wrong (since difference is 24, not 8). Why?

      Thanks in advance.
      This is how I would teach my students (Sorry if it is confusing as I do not know how to explain by typing):

      Information from question:
      Total cost of Pots & Pans = $1120
      1 Pan = $20
      1 Pot = $60
      There are 8 more pans than pots.

      Therefore, by number of pots and pans:
      Pot !________?_________!
      Pan !________?_________!_____8_____!

      If we take away the cost of 8 pans, we will get the cost of equal number of pots and pans.

      By cost, $20 x 8 = $160, $160 was spent on the 8 more pans bought.
      $1120 - $160 = $960 (amount spent on equal number of pots and pans)

      By grouping of costs,
      1 pot + 1 pan = $20 + $60 = $80

      $960/$80 = 12
      There are 12 sets.

      Therefore,
      Pots = 12
      Pans = 12 + 8 = 20

      To double check that the answer is correct:
      12 x $60 = 720 (Cost of pots)
      20 x $20 = 400 (Cost of pans)
      $720 + $400 = $1120 (Total cost of pots and pans)

      1 Reply Last reply Reply Quote 0
      • S Offline
        suiyuan
        last edited by

        Hi, Mrs Wong


        How would you teach your students to solve the following problems?(if feasible by Model Drawing)

        1) There are 32 rooms for 71 pupils at a student hostel. At the boys’ side, each room is shared by 2 boys. At the girls’ side, each room is shared by 3 girls. If each room is fully occupied by either 2 boys or by 3 girls, find the number of boys and girls respectively.

        2) Alan has 1.5 times as many marbles as Bernard while Carl has 2.5 times as many marbles as Bernard. During a game, both Alan and Carl lost to Bernard and for every 1 marble that Alan lost to Bernard; Carl lost 2 marbles to Bernard. At the end, Alan has 21 marbles left, while Carl has 27 marbles left. How many marbles did Alan lose to Bernard?

        3) When Jenny was 40 years old, her son was twice her daughter’s age. Jenny will be twice her son’s age when her daughter is 28 years old. How old will Jenny be when her daughter is 20 years old?

        Thank you for your help.

        1 Reply Last reply Reply Quote 0
        • M Offline
          mrswongtuition
          last edited by

          Hi Suiyuan,


          For Question 1, I would use Guess & Check:
          Information from question:
          32 rooms (all full)
          71 pupils total
          Each room either 2 boys or 3 girls

          Rooms for Girls/\tNo. of Girls/\tRoom for Boys/\tNo. of Boys/\tTotal Rooms/\tTotal Pupils/\tCheck
          16\t48\t16\t32\t32\t80\tNO
          10\t30\t22\t44\t32\t74\tNO

          Based on the above,
          For every decrease in 6 rooms for girls, there is a decrease in 6 pupils, therefore, for every decrease in 1 room for girls, there is a decrease in 1 pupil in total.

          We need 71 pupils in total, therefore total pupils need to decrease by 3 pupils, which means that we need to decrease the number of rooms for girls by 3 rooms.

          Then you will get:
          Rooms for Girls/\tNo. of Girls/\tRoom for Boys/\tNo. of Boys/\tTotal Rooms/\tTotal Pupils/\tCheck
          7\t21\t25\t50\t32\t72\tYES

          The answer is:
          21 girls
          50 boys

          *This is how I would teach Guess & Check method so that students do not waste time trying all the possibilities but just try 2 and zoom in directly on the answer.

          (Sorry I do not know how to post table here)

          1 Reply Last reply Reply Quote 0
          • S Offline
            suiyuan
            last edited by

            Hi, Mrs Wong.


            Thank you for your quick response.

            For Q1,besides G and C, is there any alternative way?

            You may post images by following the steps in these links.
            http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=2699&start=15
            http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=3767&start=30

            1 Reply Last reply Reply Quote 0
            • S Offline
              suiyuan
              last edited by

              [quote][IMG]http://i697.photobucket.com/albums/vv338/mrsw[/quote]
              Hi Mrs Wong

              You may wish to repost the image again.The link doesn't seem to work.
              Alternatively, you may click on URL.

              1 Reply Last reply Reply Quote 0
              • T Offline
                Tang
                last edited by

                suiyuan:
                Hi, Mrs Wong


                How would you teach your students to solve the following problems?(if feasible by Model Drawing)

                1) There are 32 rooms for 71 pupils at a student hostel. At the boys’ side, each room is shared by 2 boys. At the girls’ side, each room is shared by 3 girls. If each room is fully occupied by either 2 boys or by 3 girls, find the number of boys and girls respectively.

                2) Alan has 1.5 times as many marbles as Bernard while Carl has 2.5 times as many marbles as Bernard. During a game, both Alan and Carl lost to Bernard and for every 1 marble that Alan lost to Bernard; Carl lost 2 marbles to Bernard. At the end, Alan has 21 marbles left, while Carl has 27 marbles left. How many marbles did Alan lose to Bernard?

                3) When Jenny was 40 years old, her son was twice her daughter’s age. Jenny will be twice her son’s age when her daughter is 28 years old. How old will Jenny be when her daughter is 20 years old?

                Thank you for your help.
                1.
                G + B = 71 [x 2]
                2G + 2 B = 2 x 71 = 142

                G/3 + B/2 = 32 [x 6]
                2 G + 3 B = 6 x 32 = 192

                B = 192 - 142 = 50 boys

                G = 71 - 50 = 21 girls

                Or
                Suppose all boys, 32 x 2 = 64
                71 - 64 = 7 [short fall]
                3 - 2 = 1 [Difference in number]
                7 / 1 = 7 Rooms for girls

                32 - 7 = 25 Rooms for boys

                7 x 3 = 21 girls
                25 x 2 = 50 boys


                2.

                A : B : C = 3 : 2 : 5
                Change ratio -1 : +3 : -2
                AN = 21 and CN = 27

                3 Units - Part = 21 [x 2]
                6 Units - 2 Parts = 2 x 21 = 42

                5 Units - 2 Parts = 27

                Unit = 42 - 27 = 15

                Part = 3 x 15 - 21 = 24 marbles.


                3. Refer to Uncle Observer's Blog - Maths-Whole Number for Model Drawing and answer.

                1 Reply Last reply Reply Quote 0
                • S Offline
                  suiyuan
                  last edited by

                  suiyuan:
                  [quote][IMG]http://i697.photobucket.com/albums/vv338/mrsw

                  Hi Mrs Wong

                  You may wish to repost the image again.The link doesn't seem to work.
                  Alternatively, you may click on URL.[/quote]Hi Mrs Wong

                  I am sorry to inconvenience you again.Could you help to repost the image as that particular link doesn't seem to work.

                  1 Reply Last reply Reply Quote 0
                  • D Offline
                    Drdj
                    last edited by

                    Dear all,


                    Please help me to solve this sum - from CHIJ Prelim 2008
                    Thanks in advance 🙂

                    http://www.postimage.org/

                    1 Reply Last reply Reply Quote 0
                    • A Offline
                      AnnT2009
                      last edited by

                      Please help,


                      Q1 Mary and Jason each have some money. If Mary spent$80 per day and Jason spent $40 per day. Mary will have $500 left when Jason has spent all his money. If Mary spent $40 per day and Jason spent $80 per day. Mary will have $1100 left when Jason spent all his money. What is the amount of money Jason has?
                      Ans:$400

                      Q2 Mr Tan bought three times as many badges as toy cars and spent $144 in total. He spent $84 more on toy cars than on badges. Given that a toy car cost $10.40 more than a badge. What is the cost of a badge?
                      Ans:$1

                      TIA.

                      1 Reply Last reply Reply Quote 0
                      • T Offline
                        tianzhu
                        last edited by

                        Hi drdj


                        When you post questions, you don't have to click on quote everytime unless you are referring to it.Otherwise it becomes kind of confusing.

                        Just click on post reply will do.

                        1 Reply Last reply Reply Quote 0

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