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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • E Offline
      Emelyn
      last edited by

      Hi,


      Brain jammed....cannot solve the problem. Sign of old age too....
      Asking for help here .......


      http://postimage.org/image/2kyiwxjj8/

      In the figure above, which is not drawn to scale, 1/4 of the circle is shaded. The ratio of the area of the square to the area of the rectangle and circle is 5:7. 40% of the square is shaded. 1/3 of the rectangle is shaed. What is the ratio of the area of the circle to the square to the rectangle ?

      MTIA !!

      1 Reply Last reply Reply Quote 0
      • P Offline
        pixiedust
        last edited by

        Appreciate help with the following question.


        My solution is using listing multiples method.
        Is there a faster way?
        Such questions, analysing the gap (like the oranges question) doesn't work?

        Some NCC cadets are gathered in a hall.
        If they are grouped into 7 cadets in a team, there will be 4 cadets left out.
        If they are grouped into 9 cadets in a team, there will be 6 cadets left out.
        How many cadets are there in the hall if the number of cadets is between 20 and 70 ?

        1 Reply Last reply Reply Quote 0
        • T Offline
          tianzhu
          last edited by

          Emelyn:
          Hi,


          Brain jammed....cannot solve the problem. Sign of old age too....
          Asking for help here .......


          http://postimage.org/image/2kyiwxjj8/

          In the figure above, which is not drawn to scale, 1/4 of the circle is shaded. The ratio of the area of the square to the area of the rectangle and circle is 5:7. 40% of the square is shaded. 1/3 of the rectangle is shaed. What is the ratio of the area of the circle to the square to the rectangle ?

          MTIA !!
          Hi

          In this question, the units are in pretty nice numbers.

          You may use Units Method or MD.

          Circle
          Shaded ----- 1 unit
          Unshaded ------ 3 units
          Total -------4 units

          Rectangle
          Shaded ----- 1 unit
          Unshaded ------ 2 units
          Total ------- 3 units

          Square
          Shaded ----- 2 unit
          Unshaded ------ 3 units
          Total --------5 units

          C:S:R ------4:5:3

          Now you may wish to try this one.

          Best wishes

          http://farm3.static.flickr.com/2407/2673911274_a92537168a_o.jpg\">

          1 Reply Last reply Reply Quote 0
          • T Offline
            tianzhu
            last edited by

            pixiedust:
            Appreciate help with the following question.

            My solution is using listing multiples method.
            Is there a faster way?
            Such questions, analysing the gap (like the oranges question) doesn't work?
            Hi

            Systematic listing of multiples is commonly used by primary students to solve this question.

            Best wishes

            1 Reply Last reply Reply Quote 0
            • T Offline
              tianzhu
              last edited by

              pixiedust:

              My solution is using listing multiples method.
              Is there a faster way?
              Such questions, analysing the gap (like the oranges question) doesn't work?
              Hi

              Good Afternoon.

              Is there a faster way? Is there a more efficient method to make life a little easier for our young ones?

              I gave your question some thoughts last night.

              This question is usually solved with “Systematic Listing” .It takes a bit of time but it also ensures that students gain some marks as long as they don’t make careless mistakes.

              I am not too sure whether working it this way is more efficient than SL, do take a look and decide if it works for you.

              First the thought process, we are given a number of cadets between 20 and 70.

              So we have a big group of NCC cadets in a hall.

              For case 1, they are grouped into 7 cadets in a team, this means multiples of 7.As for groups of 9, it also means multiples of 9.

              For comparison, we have some groups of 7 plus 4 in case 1 and some groups of 9 plus 6 in case 2.Remember the total number of cadets in the hall is the same in both cases.

              Hence, it’s likely we would have more groups of 7 than groups of 9.The difference between 6 and 4 is 2.Therefore, we need to find the multiples of 7 which is greater than the multiples of 9 by 2.

              The closest multiples of 7 and 9 to 70 is 63.The difference between them is zero.

              Next move down, (8*7) ------ 56 and (6*9) -------54.This gives a difference of 2.

              The answer is (56+4) ------60 or (54+6) -------60

              For my solution, I’ve drawn more MD than necessary to show the thought process. Once you become more familiar, you may do away with some of them.

              First, find the difference between the remaining cadets after the groupings. Next proceed to find the multiples which give the required difference and you are on the way to the answer.

              Hope you’ll find it useful.

              Best wishes

              http://farm6.static.flickr.com/5171/5511424062_c0bfacc8c2_b.jpg\">

              1 Reply Last reply Reply Quote 0
              • P Offline
                pixiedust
                last edited by

                :goodpost: Thank you VERY much tianzhu !

                It is useful. It is like using listing method + intelligence.

                Much appreciate your time and help.

                1 Reply Last reply Reply Quote 0
                • A Offline
                  atutor2001
                  last edited by

                  pixiedust:
                  Appreciate help with the following question.


                  My solution is using listing multiples method.
                  Is there a faster way?
                  Such questions, analysing the gap (like the oranges question) doesn't work?

                  Some NCC cadets are gathered in a hall.
                  If they are grouped into 7 cadets in a team, there will be 4 cadets left out.
                  If they are grouped into 9 cadets in a team, there will be 6 cadets left out.
                  How many cadets are there in the hall if the number of cadets is between 20 and 70 ?
                  Mathematically, there is no faster way because the number of unknowns (i.e. The total no. of cadets; The no. of groups of 4 in case 1; The no. of groups of 6 in case 2 - 3 unknowns) is more than the number of relationship (equations) given by the question.

                  1 Reply Last reply Reply Quote 0
                  • ozoraO Offline
                    ozora
                    last edited by

                    tianzhu:
                    Emelyn:

                    Hi,


                    Brain jammed....cannot solve the problem. Sign of old age too....
                    Asking for help here .......


                    http://postimage.org/image/2kyiwxjj8/

                    In the figure above, which is not drawn to scale, 1/4 of the circle is shaded. The ratio of the area of the square to the area of the rectangle and circle is 5:7. 40% of the square is shaded. 1/3 of the rectangle is shaed. What is the ratio of the area of the circle to the square to the rectangle ?

                    MTIA !!

                    Hi

                    In this question, the units are in pretty nice numbers.

                    You may use Units Method or MD.

                    Circle
                    Shaded ----- 1 unit
                    Unshaded ------ 3 units
                    Total -------4 units

                    Rectangle
                    Shaded ----- 1 unit
                    Unshaded ------ 2 units
                    Total ------- 3 units

                    Square
                    Shaded ----- 2 unit
                    Unshaded ------ 3 units
                    Total --------5 units

                    C:S:R ------4:5:3

                    Now you may wish to try this one.

                    Best wishes

                    http://farm3.static.flickr.com/2407/2673911274_a92537168a_o.jpg\">

                    hi Tianzhu
                    is the answer: 6:5:3?

                    1 Reply Last reply Reply Quote 0
                    • MathIzzzFunM Offline
                      MathIzzzFun
                      last edited by

                      atutor2001:
                      pixiedust:

                      Appreciate help with the following question.


                      My solution is using listing multiples method.
                      Is there a faster way?
                      Such questions, analysing the gap (like the oranges question) doesn't work?

                      Some NCC cadets are gathered in a hall.
                      If they are grouped into 7 cadets in a team, there will be 4 cadets left out.
                      If they are grouped into 9 cadets in a team, there will be 6 cadets left out.
                      How many cadets are there in the hall if the number of cadets is between 20 and 70 ?

                      Mathematically, there is no faster way because the number of unknowns (i.e. The total no. of cadets; The no. of groups of 4 in case 1; The no. of groups of 6 in case 2 - 3 unknowns) is more than the number of relationship (equations) given by the question.

                      Hi

                      newbie here. Just to share that there is a quick method for this type of problem.

                      Look at the numbers carefully and you will see that by adding 3 to the total will make the total divisible by both 7 and 9. This means that the new total is a multiple of both 7 and 9. So the number is question is 7 x 9 - 3 = 63 - 3 = 60.

                      cheers.

                      1 Reply Last reply Reply Quote 0
                      • T Offline
                        tianzhu
                        last edited by

                        pixiedust:
                        :goodpost: Thank you VERY much tianzhu !

                        It is useful. It is like using listing method + intelligence.

                        Much appreciate your time and help.
                        Hi pixiedust

                        Good Morning.

                        You're welcome.

                        Best wishes

                        1 Reply Last reply Reply Quote 0

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