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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • J Offline
      jieheng
      last edited by

      Q2)


      At first , J had 10u .

      After J lost 1u (1/10) to K , J had 9u

      Given the ratio of J : K = 3 : 1 .

      Since J had 9u , K should have 3u

      a)

      At first , K had = 3u - 1u = 2u

      At first ,the ratio of the number of cards Jimmy had to the number of cards Kelly had = 10 : 2 = 5 : 1 (Ans)


      old ratio
      J : K Total

      3u 1u 4u

      After J lost more cards to K

      new ratio
      J : K Total

      4u 7u 11u

      Change the ratio of total units to the same number for old ratio and new ratio as the total cards of J and K of old ratio and new ratio should be the same .

      Old ratio * 11 and new ratio * 4 , total ratio would be 44

      old ratio
      J : K Total

      33u 11u 44u

      new ratio
      J : K Total

      16u 28u 44u


      28u - 16u = 72

      12u = 72

      1u = 6

      Total number of cards = 44u = 44 * 6 = 264

      At the end , K had = 28u = 28 * 6 = 168 cards

      At first K had = 2/12 * 264 = 44 cards

      Number of cards that Kelly won from Jimmy altogether
      = 168 - 44
      = 124 cards (Ans)

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      • B Offline
        babyluvv
        last edited by

        Thanks jieheng for helping!! 😉 😄

        1 Reply Last reply Reply Quote 0
        • J Offline
          jieheng
          last edited by

          Hi babyluvv ,


          You are welcome .

          1 Reply Last reply Reply Quote 0
          • ozoraO Offline
            ozora
            last edited by

            I would like to ask any other methods of solving the below questions besides guess and check and algebra.


            I have 20 cars and bikes. The number of car wheels are 38 more wheels than the bike. How many cars and bikes are there respectively?

            1 Reply Last reply Reply Quote 0
            • T Offline
              tianzhu
              last edited by

              ozora:
              I would like to ask any other methods of solving the below questions besides guess and check and algebra.


              I have 20 cars and bikes. The number of car wheels are 38 more wheels than the bike. How many cars and bikes are there respectively?
              Hi

              Good Morning.

              Yes, we can.

              There is always more than one way to arrive at a solution.

              We should strive towards a broad based approach to seeking solutions. We should cast our net wide seeking out those with different perspectives on different questions so as to have a vibrant and robust forum for active learning.This’ll benefit our children in the long run.

              For your question,the numbers are small, so it’s not too tedious to make calculated guesses using GC if you have to.

              A common strategy is to use “Make a Supposition”. A student put up a tabulated list, there are some examples in previous posts.

              Another way of making assumption, this time with a slight tweak, is to use the \"pretend pretend\" way.

              Assume or pretend that every car and bicycle have 2 wheels at first. Kids have fertile imagination, they like to \"pretend, pretend lah\".I miss this innocent part of a kid's life because my boy is no longer that young already.

              Here's the solution.

              20*2 ----- 40
              40 + 38 ------ 78

              2 + 4 ------ 6
              78/6 ------ 13

              13 cars and 7 bicycles

              Best wishes

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              • P Offline
                pixiedust
                last edited by

                Appreciate any help with the following :


                There are 14 pupils in a class.
                If each pupil exchanges one sticker with every other one, how many sticker exchanges are made ?

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                • T Offline
                  tianzhu
                  last edited by

                  pixiedust:
                  Appreciate any help with the following :


                  There are 14 pupils in a class.
                  If each pupil exchanges one sticker with every other one, how many sticker exchanges are made ?
                  Hi

                  Draw a diagram to see a pattern.

                  (13+12+11+10+9+8+7+6+5+4+3+2+1)-------- 91 sticker exchanges

                  Best wishes

                  1 Reply Last reply Reply Quote 0
                  • A Offline
                    avell
                    last edited by

                    Dear all


                    Pls help me for the following questions:-

                    Qn (1)
                    4/5 of John’s money is equal to 3/8 of Sarah’s money. Express Sarah’s money as a ratio of John’s money in it simplest form (draw a model to help you to solve the sum.

                    Qn (2)
                    The ratio of boys and girls on a school bus was 2 : 3. When 16 girls alighted from the bus, the ratio of the remaining boys to girls became 6:5. Find the number of children who remained on the bus.

                    1 Reply Last reply Reply Quote 0
                    • J Offline
                      jieheng
                      last edited by

                      avell:
                      Dear all


                      Pls help me for the following questions:-

                      Qn (1)
                      4/5 of John's money is equal to 3/8 of Sarah's money. Express Sarah's money as a ratio of John's money in it simplest form (draw a model to help you to solve the sum.
                      Hi ,

                      Q1)

                      J [ ][ ][ ][ ][ ] 5 units

                      S [ -][ -][ -][ -][ -][ -][ -][ -] 8 units

                      To solve the question , need to modify the model , so that the units in Red and Blue are equal

                      J * 3 and S * 4

                      J 15 units

                      S 32 units

                      Ratio of Sarah's money to John's money = 32 : 15 (Ans)

                      ****************************************************
                      Faster way to solve this type of question without using the model is to change the numerators of two variables to the same number .

                      John Sarah
                      4/5 3/8

                      Change to

                      John Sarah
                      12/15 12/32

                      Ratio of Sarah's money to John's money = 32 : 15 (Ans)

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                      • J Offline
                        jieheng
                        last edited by

                        avell:
                        Dear all


                        Pls help me for the following questions:-

                        Qn (2)
                        The ratio of boys and girls on a school bus was 2 : 3. When 16 girls alighted from the bus, the ratio of the remaining boys to girls became 6:5. Find the number of children who remained on the bus.
                        Old Ratio
                        B [ ][ ] 2u

                        G [ ][ ][ ] 3u

                        New Ratio
                        B [ ][ ][ ][ ][ ][ ] 6u

                        G [ ][ ][ ][ ][ ] 5u

                        Since the number of the boys remained the same throughout the journey ,
                        modify the old ratio of the boys from 2 units to 6 units

                        Modified old ratio
                        B [ ][ ][ ][ ][ ][ ] 6u

                        G [ ][ ][ ][ ][ ][ ][ ][ ][ ] 9u

                        Compare the units of the girls of modified old ratio and new ratio ,

                        4 units = 16
                        1 unit = 4

                        Number of children remained on the bus = 11 units (6 units of boys and 5 units of girls) = 11 * 4 = 44 (Ans)

                        1 Reply Last reply Reply Quote 0

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