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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • T Offline
      tianzhu
      last edited by

      Hi Hifive


      Good Morning.

      Hope this helps.

      Best wishes.

      http://farm6.static.flickr.com/5149/5659052643_4ee8cfe96d_z.jpg\">

      1 Reply Last reply Reply Quote 0
      • H Offline
        Hifive
        last edited by

        Hi tianzhu


        Many thanks for your explanation.

        Regards

        1 Reply Last reply Reply Quote 0
        • T Offline
          tianzhu
          last edited by

          Hifive:
          Hi tianzhu


          Many thanks for your explanation.

          Regards
          Hi

          You're welcome.

          Best wishes.

          1 Reply Last reply Reply Quote 0
          • A Offline
            andante
            last edited by

            I have encountered the following questions about speed :-


            Two people, A and B, were running along a 400-metre oval running track. Thestarted off at the same time, from the same point and ran in the same direction. Person A ran at a speed of 280m/min while person B ran at a speed of 240m/min. How many minutes did Person A take to catch up with Person B?

            I don’t really understand the solution provided.

            It is mentioned that
            For person A to catch up with Person B, he must run one(???) more round than Person B, that is to run an extra 400m. Since Person A covered 280 -240 = 40m more than Person B in each minute, the time he took to catch up with Person B was
            400 / (280 - 240) = 10 min

            Can someone help to explain ?

            Thanks in advance.

            1 Reply Last reply Reply Quote 0
            • S Offline
              small
              last edited by

              andante:
              I have encountered the following questions about speed :-


              Two people, A and B, were running along a 400-metre oval running track. Thestarted off at the same time, from the same point and ran in the same direction. Person A ran at a speed of 280m/min while person B ran at a speed of 240m/min. How many minutes did Person A take to catch up with Person B?

              I don't really understand the solution provided.

              It is mentioned that
              For person A to catch up with Person B, he must run one(???) more round than Person B,, that is to run an extra 400m. Since Person A covered 280 -240 = 40m more than Person B in each minute, the time he took to catch up with Person B was
              400 / (280 - 240) = 10 min

              Can someone help to explain ?

              Thanks in advance.

              Hi,

              HTH..

              After one min run, Person A is 40m ahead of Person B, so the distance between them is 360m.
              After two min run, Person A is 80m ahead of Person B and now the distance between them is 320m.

              For the remaining 320m, Person A will take another 8 min to catch up with Person B.

              320 / 40 = 8

              So in total Person A took 10 min to catch up with Person B.

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              • J Offline
                JadeDry
                last edited by

                Hello:


                I would appreciate some help with this problem:

                Factorize "-ab-9abc" completely.

                I am stuck between two answers:

                ab(-1-9c)

                Or

                -ab(1-9c)

                I would appreciate it if someone could point out the correct one.

                Thanks in advance.

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                • S Offline
                  small
                  last edited by

                  Hi,


                  The answer is -ab(1+9c) OR ab(-1-9c).

                  I personally preferred the first answer.

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                  • C Offline
                    chrisu
                    last edited by

                    After weeks and weeks of waiting, the teacher finally confirmed that $31 is the correct answer and not $14.90. Thanks to all for helping out in this question.

                    tianzhu:
                    chrisu:

                    Will know by today and will revert back here once I get the working from teacher. I'm anxious to know too.

                    Hi

                    First, let’s see the teacher explanation first.

                    We cannot read the intention of the question setter, what we can rely on is our understanding on the concepts of percentages.

                    Tony had 15% more 50c coins than 20c coins. If there were 6 more 50c coins than 20c coins, how much money did Tony have?

                    Based on the question, we are given the understanding that the number of 50 cents coins is 15% more than the number of 20 cents coins.

                    Next compare your question with this common question in P6 percentage.

                    Jian Zhong has $50.Ming Ming has 20% more money than Jian Zhong.How much money does Ming Ming have?

                    How would one interpret the second question?

                    Best wishes

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                    • T Offline
                      teddy7171
                      last edited by

                      tianzhu:
                      teddy7171:

                      Plz help.


                      Mrs Tan bought 4 times as many toy guns as teddy bears. She spent $1750 altogether. A toy gun cost $10 less than a teddy bears. The total cost of Toy guns was $490 more than the total cost of teddy bears.
                      i) how much did Mrs Tan spend on the teddy bears?
                      ii) how much did one teddy bear cost?

                      Thanks.

                      Hi

                      A quick answer.

                      Cost of Teddy bears ------ (1750 - 490) / 2 ------ 630

                      Cost of Toy guns ------ 1120


                      Toy guns ------ 4units

                      Teddy bears ------ 1unit

                      Cost of 1unit of Toy guns ------- 1120 / 4 ------ 280

                      Cost of 1unit of Teddy bears ------- 630

                      630 - 280 ------- 350

                      Difference in cost between 1 TG and 1 TB ------- 10

                      Number of Teddy Bears ------ 350/10 ------- 35

                      Cost per Teddy bear ------- 630 / 35 ------ 18

                      Best wishes

                      Tianzhu,

                      Thank u.

                      1 Reply Last reply Reply Quote 0
                      • J Offline
                        Jcong
                        last edited by

                        The number of the marbles in Box A, Box B and Box C was 195. John added 60 marbles to those in Box A, doubled the number of marbles in Box B and halved the number of marbles in Box C. The ratio of the number of marbles become 4:1:2. What is the total number of marbles in the three boxes now?

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