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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • MathIzzzFunM Offline
      MathIzzzFun
      last edited by

      bobsg01:
      Thanks MathIzzzFun.


      :goodpost:
      Hi bobsg01,

      you are welcome :lol:

      cheers.

      1 Reply Last reply Reply Quote 0
      • N Offline
        Neat
        last edited by

        tianzhu:
        Neat:


        What made you decide to multiply by 4 to get the equivalent ratio?

        Hi

        We are given that the total number of ducks and cows is between 20 and 40.

        We are also given the ratio of the total number of ducks' legs to the total number of cows' legs is 5:9.

        Given this ratio, a student is expected to find out the number of animals.

        A cow has 4 legs and a duck has 2 legs.

        Hence, the number showing the number of cow’s legs has to be a multiple of 4.Likewise the number showing the number of duck’s legs has to be a multiple of 2.

        That’s why we multiply the given ratios 5:9 by 4 to get 20:36.

        This gives us 10:9 as the ratio for the number of ducks to the number of cows. This is not within the range of 20 and 40.

        Multiply by 2 to get an equivalent ratio of 20:18 which is 38 and within the range.

        Best wishes

        [quote]Thanks tianzhu for your detailed and clear explanation.

        Thanks again.
        :salute: [/quote]

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        • T Offline
          tianzhu
          last edited by

          Neat:

          Thanks tianzhu for your detailed and clear explanation.
          Hi

          You're welcome.

          Best wishes

          1 Reply Last reply Reply Quote 0
          • B Offline
            bobsg01
            last edited by

            Thanks in advance for your answer: :? :?


            http://i56.tinypic.com/yktg0.jpg\">

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            • starlight1968sgS Offline
              starlight1968sg
              last edited by

              bobsg01:
              Thanks in advance for your answer: :? :?


              http://i56.tinypic.com/yktg0.jpg\">
              Find area or perimeter ???

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              • B Offline
                bobsg01
                last edited by

                Sorry for the confusion.


                This is the question on top:

                http://i55.tinypic.com/2a7h2dy.jpg\">

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                • ChiefKiasuC Offline
                  ChiefKiasu
                  last edited by

                  bobsg01:
                  Thanks in advance for your answer: :? :?


                  http://i56.tinypic.com/yktg0.jpg\">
                  Diameter of external circle = 14 + 14 = 28cm
                  Area of external circle = 14^2 * PI = 616cm^2
                  Diameter of external circle = 28 * PI = 88cm
                  Area of shaded area
                  = Area of external circle - Area of square - Area of 2 small circles
                  = 616 - 14*14 - 2 (7^2 * PI)
                  = 616 - 196 - 308
                  = 112cm^2

                  1 Reply Last reply Reply Quote 0
                  • ChiefKiasuC Offline
                    ChiefKiasu
                    last edited by

                    bobsg01:
                    Sorry for the confusion.


                    This is the question on top:

                    http://i55.tinypic.com/2a7h2dy.jpg\">
                    Area of external square = 18*18 = 324cm^2
                    Area of circle = 9^2 * PI = 254.57cm^2
                    Area of shaded area = Area of external square - Area of circle
                    = 324 - 254.57
                    = 69.43cm^2

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                    • B Offline
                      bobsg01
                      last edited by

                      Thank you ChiefKiasu.

                      1 Reply Last reply Reply Quote 0
                      • B Offline
                        bobsg01
                        last edited by

                        Area of circle = 9^2 * PI = 254.57cm^2


                        Sorry, what the meaning of PI ?

                        1 Reply Last reply Reply Quote 0

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