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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • T Offline
      tianzhu
      last edited by

      Brenda10:

      Hi Tianzhu
      Thank you for your wonderful picture and explanation. DD said she can understand and also like the presentation. :lol:
      Hi Brenda10

      Good Morning.

      I am happy your dd liked my “masak masak” way of doing maths.

      Best wishes

      1 Reply Last reply Reply Quote 0
      • corneyAmberC Offline
        corneyAmber
        last edited by

        Hifive:
        Hi


        Maths problem - pls help...

        Terry and John went shopping with a total of $198. Terry had $10 more than John. Terry spent 25% as much money as John. After which, he had twice as much money as John.
        a) How much money did Terry bring for shopping?
        b) How much money had Terry left after shopping?

        Kindly help. Thanks in advance!
        Hi, I cannot draw pretty models now as I don't hv the tools with me but hope you can understand my solution.

        T. |u. | 10. |
        J. |u. |
        2u + 10 -> 198
        2u -> 188
        u -> 94
        hence Terry has 94+10 =$104 at first

        T remainder after spending x : u-x+10= 104-x
        J remainder after spending 4x: u-4x = 94- 4x

        T remainder = 2x J remainder
        So 104-x = 2(94-4x)
        7x = 188-104
        7x = 84
        x = 12

        Hence Terry after shopping has 104-12 = $92

        1 Reply Last reply Reply Quote 0
        • H Offline
          Hifive
          last edited by

          Hi ksi


          Thank you for the solution on Terry and John’s question.
          Understood part a.
          As for part b, I don’t quite get it. Is there an alternative method of solution?

          Sorry for taking so much of your time.

          Regards

          1 Reply Last reply Reply Quote 0
          • corneyAmberC Offline
            corneyAmber
            last edited by

            adanial:
            Hello, pls help with the question below....thank you



            Question 2
            Julie had to complete a jigsaw puzzle. On thefirst day, she managed to complete 20% of the puzzle. On the second day she fitted another 60 pc of the puzzle. As a result, the ratio of the number of fitted pieces to the ration of the number of unfitted pieces became 2:5. How many pieces did the jigsaw puzzle consist of ?
            20% -> 1/5 fitted, => 7/35

            After 60 pieces, ratio becomes 2 out of 7 parts fitted => 10/35

            10-7=3
            3 parts-> 60
            1part -> 20
            35 parts -> 700

            Hence puzzle is 700 pieces.

            Here is the diagram version:
            http://i55.tinypic.com/ioferp.jpg\">

            1 Reply Last reply Reply Quote 0
            • corneyAmberC Offline
              corneyAmber
              last edited by

              Hifive:
              Hi ksi


              Thank you for the solution on Terry and John's question.
              Understood part a.
              As for part b, I don't quite get it. Is there an alternative method of solution?

              Sorry for taking so much of your time.

              Regards
              Sorry I am not able to draw the model without my tool so it becomes difficult to visualize, let me try again.

              T. |.........u+10-x....| Where x =what Terry spent
              J. | u-4x |
              Where 4x is what Jerry spent
              ( 25% = 1/4=> if Jerry spent 4 parts, Terry spent 1 part. So if Jerry spent 100, Terry spent $25 then $25 is 1 part, $100 is 4 parts.)

              Based on the model above, Terry has 2 times money left compared to Jerry after both spent so to equal them,

              Terry's remainder = 2 x jerry's remainder

              So 104 - x = 2(94-4x) then you solve x to get terry's final amount.

              Hope this explains better. 🙂

              1 Reply Last reply Reply Quote 0
              • MathIzzzFunM Offline
                MathIzzzFun
                last edited by

                Hifive:
                Hi


                Maths problem - pls help...

                Terry and John went shopping with a total of $198. Terry had $10 more than John. Terry spent 25% as much money as John. After which, he had twice as much money as John.
                a) How much money did Terry bring for shopping?
                b) How much money had Terry left after shopping?

                Kindly help. Thanks in advance!

                Hi

                here's the model approach 😄

                http://www.flickr.com/photos/62167097@N02/5820245316/in/photostream

                cheers.

                1 Reply Last reply Reply Quote 0
                • PiggyLalalaP Offline
                  PiggyLalala
                  last edited by

                  MathIzzzFun:
                  Hifive:

                  Hi


                  Maths problem - pls help...

                  Terry and John went shopping with a total of $198. Terry had $10 more than John. Terry spent 25% as much money as John. After which, he had twice as much money as John.
                  a) How much money did Terry bring for shopping?
                  b) How much money had Terry left after shopping?

                  Kindly help. Thanks in advance!


                  Hi

                  here's the model approach 😄

                  http://www.flickr.com/photos/62167097@N02/5820245316/in/photostream
                  cheers.

                  Thanks for the model approach. I have tried to draw the model but not successful. Though my model is same as yours, I failed to see that 1big block = 3u + 10. 😓

                  1 Reply Last reply Reply Quote 0
                  • T Offline
                    tianzhu
                    last edited by

                    Hi Hifive


                    This question touches on simultaneous concept. There are two unknowns and two equations.

                    Students who are familiar with simultaneous equations may use it solve the problem.

                    Those who are not, don’t worry too much, you can still get around the problem by solving the equations pictorially. Alternatively, you may also solve it by representing the units and parts by letters of the alphabet or simply using units and parts.

                    Hope this helps.

                    Best wishes

                    http://farm4.static.flickr.com/3079/5819760157_cfb63b3d54_z.jpg\">

                    1 Reply Last reply Reply Quote 0
                    • MathIzzzFunM Offline
                      MathIzzzFun
                      last edited by

                      PiggyLalala:
                      MathIzzzFun:

                      [quote=\"Hifive\"]Hi


                      Maths problem - pls help...

                      Terry and John went shopping with a total of $198. Terry had $10 more than John. Terry spent 25% as much money as John. After which, he had twice as much money as John.
                      a) How much money did Terry bring for shopping?
                      b) How much money had Terry left after shopping?

                      Kindly help. Thanks in advance!


                      Hi

                      here's the model approach 😄

                      http://www.flickr.com/photos/62167097@N02/5820245316/in/photostream
                      cheers.

                      Thanks for the model approach. I have tried to draw the model but not successful. Though my model is same as yours, I failed to see that 1big block = 3u + 10. 😓[/quote]hi

                      u r welcome 😄

                      Usually, moving the blocks around will help to \"see\" for example :

                      http://i52.tinypic.com/2sb3ac8.jpg\">

                      cheers.

                      1 Reply Last reply Reply Quote 0
                      • PiggyLalalaP Offline
                        PiggyLalala
                        last edited by

                        tianzhu:
                        Hi Hifive


                        This question touches on simultaneous concept. There are two unknowns and two equations.

                        Students who are familiar with simultaneous equations may use it solve the problem.

                        Those who are not, don’t worry too much, you can still get around the problem by solving the equations pictorially. Alternatively, you may also solve it by representing the units and parts by letters of the alphabet or simply using units and parts.

                        Hope this helps.

                        Best wishes

                        http://farm4.static.flickr.com/3079/5819760157_cfb63b3d54_z.jpg\">
                        :thankyou: for the alternative 'model' approach. Yours is easy to understand because it is just simultaneous questions in pictorial form.
                        😄 But not all word problems can use such pictorial simultaneous equations right? How to know which one can, and which one cant?Sorry.. i ask many questions again. Sorry and thanks for your solution and time.

                        1 Reply Last reply Reply Quote 0

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