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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • corneyAmberC Offline
      corneyAmber
      last edited by

      raghupavithra:
      Mr sim earns $2500 every month.After giving 3/5 of his salary to his wife and 1/2 of the remainder to his son, he saves the rest. How much money can Mr sim save in 3 years?

      Amount left after giving wife per month
      = 2/5 * 2500
      = 1000

      After giving 1/2 of remainder to son, amt he saves per month = 1000-500 = 500

      Hence savings in 3 years = 36*500 = $18,000

      1 Reply Last reply Reply Quote 0
      • corneyAmberC Offline
        corneyAmber
        last edited by

        bobsg01:
        Primary 6 Problem.


        Thanks for your kind help.

        http://i53.tinypic.com/2vceyvk.jpg\">

        1 litre = 1000 cubic cm
        5.95 litres = 1000 x 5.95 = 5950 cubic cm

        (a) Water level = 5950/700 = 8.5cm

        (b) Remaining level to full = 10-8.5 =1.5cm

        hence amount of water to fill tank = 700 x 1.5 = 1050 cubic cm or 1.05 litres

        1 Reply Last reply Reply Quote 0
        • S Offline
          stary
          last edited by

          Can somebody help me???... 😢

          1 Reply Last reply Reply Quote 0
          • S Offline
            stary
            last edited by

            Wow... Since 18 May 2008, we've reached the 346th page!!!

            Keep it up team! :rahrah: :rahrah: :rahrah:

            1 Reply Last reply Reply Quote 0
            • corneyAmberC Offline
              corneyAmber
              last edited by

              stary:
              Hi all,


              Have 2 questions that I need help with...

              1.
              A and B start cycling at the same time from the same place.
              If they cycle in the opposite direction, they will be 37 2/5 km apart after 55 min.
              If they cycle in the same direction, A will be 2 1/5 km ahead of B after 55 min.
              (a) Find the diff. in their average speed.
              (b) Find the average speed of the slower cyclist.(Express in decimals)

              Your help is GREATLY appreciated by me.

              Best regards,
              Stary
              A <--------------------|------------> B

              A |-------------------->
              B |------------->

              So whether they go the same or opposite direction,
              difference in distance = 2 1/5km
              time taken = 55/60 h
              (a) difference in average speed
              = dist/time
              = 11/5 x 60/55
              = 2.4 km/h

              (b) distance covered by slower cyclist
              = (37 2/5 - 2 1/5) / 2
              = 176/10 km
              Hence average speed of slower cyclist
              = 176/10 x 60/55
              = 19.2 km/h

              1 Reply Last reply Reply Quote 0
              • corneyAmberC Offline
                corneyAmber
                last edited by

                stary:
                Hi all,


                Have 2 questions that I need help with...

                2.
                At 2pm, Melvin started from Vivo City and travelled towards Sun City at an average speed of 78km/h. At 3:12pm, he went past Andrew who was travelling from Sun City to Vivo City. At 3:42pm, the distance between Melvin and Andrew was 75 km.
                (a) What was Andrew's speed?
                (b) At what time did Andrew reach Vivi City?


                Your help is GREATLY appreciated by me.

                Best regards,
                Stary
                3:12pm-3:42pm = 30 mins = 1/2 hr
                Distance travelled by Melvin from 3:12 to 3:42 = 78 x 1/2 h = 39km

                Distance travelled by Andrew from 3:12-3:42 = 75- 39 = 36km
                (a) Hence Andrew's speed = 36/ (1/2) = 72km/h

                (b) Distance travelled by Melvin up to 3:12 = 78 x 6/5 h = 93.6km

                Time taken by Andrew to travel from the time he met Melvin at 3:12 to Vivo
                = distance/speed
                =93.6 / 72
                = 1.3 h = 1 hr 18 mins

                Hence Andrew arrive at vivo city at (3:12pm + 1h 18 min) = 4:30pm

                1 Reply Last reply Reply Quote 0
                • S Offline
                  stary
                  last edited by

                  ksi:
                  stary:

                  Hi all,


                  Have 2 questions that I need help with...

                  1.
                  A and B start cycling at the same time from the same place.
                  If they cycle in the opposite direction, they will be 37 2/5 km apart after 55 min.
                  If they cycle in the same direction, A will be 2 1/5 km ahead of B after 55 min.
                  (a) Find the diff. in their average speed.
                  (b) Find the average speed of the slower cyclist.(Express in decimals)

                  Your help is GREATLY appreciated by me.

                  Best regards,
                  Stary

                  A <--------------------|------------> B

                  A |-------------------->
                  B |------------->

                  So whether they go the same or opposite direction,
                  difference in distance = 2 1/5km
                  time taken = 55/60 h
                  (a) difference in average speed
                  = dist/time
                  = 11/5 x 60/55
                  = 2.4 km/h

                  (b) distance covered by slower cyclist
                  = (37 2/5 - 2 1/5) / 2
                  = 176/10 km
                  Hence average speed of slower cyclist
                  = 176/10 x 60/55
                  = 19.2 km/h

                  Thank you very much ksi!!!

                  1 Reply Last reply Reply Quote 0
                  • S Offline
                    stary
                    last edited by

                    ksi:
                    stary:

                    Hi all,


                    Have 2 questions that I need help with...

                    2.
                    At 2pm, Melvin started from Vivo City and travelled towards Sun City at an average speed of 78km/h. At 3:12pm, he went past Andrew who was travelling from Sun City to Vivo City. At 3:42pm, the distance between Melvin and Andrew was 75 km.
                    (a) What was Andrew's speed?
                    (b) At what time did Andrew reach Vivi City?


                    Your help is GREATLY appreciated by me.

                    Best regards,
                    Stary

                    3:12pm-3:42pm = 30 mins = 1/2 hr
                    Distance travelled by Melvin from 3:12 to 3:42 = 78 x 1/2 h = 39km

                    Distance travelled by Andrew from 3:12-3:42 = 75- 39 = 36km
                    (a) Hence Andrew's speed = 36/ (1/2) = 72km/h

                    (b) Distance travelled by Melvin up to 3:12 = 78 x 6/5 h = 93.6km

                    Time taken by Andrew to travel from the time he met Melvin at 3:12 to Vivo
                    = distance/speed
                    =93.6 / 72
                    = 1.3 h = 1 hr 18 mins

                    Hence Andrew arrive at vivo city at (3:12pm + 1h 18 min) = 4:30pm

                    Thank you very much ksi!!!(Once again) :dancing:

                    1 Reply Last reply Reply Quote 0
                    • B Offline
                      bobsg01
                      last edited by

                      Thank you ksi. :rahrah:

                      1 Reply Last reply Reply Quote 0
                      • B Offline
                        bobsg01
                        last edited by

                        P6 Volume question.


                        Thanks for any help provided.

                        http://i53.tinypic.com/25k1zpf.jpg\">

                        1 Reply Last reply Reply Quote 0

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