Q&A - PSLE Math

[bobsg01]

Wow, it's easier to explain to my son now with this model diagram.


Thank you MathIzzzFun. :salute:

[Dharma]

bobsg01:

Need some engligtenment on this answer.


In Total number of parts the figure has is 2 + 9 = 11 units

Why does it used 9 instead of 8 with minus 1 for Z? Confusing because they used 2 for X (which is minus 1 instead of 3). :?

Thanks for your kind assistant.

http://i53.tinypic.com/cltf5.jpg\">

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Ratio of X : Y : Z = 3 : 4 : 9
Ratio of Y (Shaded) : Y(Unshaded) = 1 : 3
Ratio of X (Shaded) : X (Unshaded) = 1 : 2
Total area of figure = 2u +1u + 3u + (9u – 4u) = 11u
Total area of shaded portion = 1u
Fraction of unshaded portion = (11u -1u)/11u = 10/11

[bobsg01]

Thanks Dharma for alternative solution. :hi5:

[bobsg01]

Math problem.


Appreciate any kind help.

Thanks. :faint:

http://i55.tinypic.com/2cnfihj.jpg\">

[MathIzzzFun]

bobsg01:

Wow, it's easier to explain to my son now with this model diagram.


Thank you MathIzzzFun. :salute:

Hi bobsg01,

u r welcome, bon weekend !

cheers.

[MathIzzzFun]

bobsg01:

Math problem.


Appreciate any kind help.

Thanks. :faint:

http://i55.tinypic.com/2cnfihj.jpg\">

Hi bobsg01,

hope this helps

http://i52.tinypic.com/346rgnp.jpg\">

bon weekend !

cheers.

[bobsg01]

Fantastic solution and it's super clear. Thank you and happy weekend MathIzzzFun. :goodpost:

[bobsg01]

PSLE past examination question. Stuck.......


Appreciate for the kind help.

http://i56.tinypic.com/2e4dgud.jpg\">

[MathIzzzFun]

bobsg01:

PSLE past examination question. Stuck.......


Appreciate for the kind help.

http://i56.tinypic.com/2e4dgud.jpg\">

Hi bobsg01,

this is similar to a question that was discussed before - http://www.flickr.com/photos/62167097@N02/5661546018/in/photostream

When 8 sweets given to each girl, left over 25 sweets.
When 11 sweets are given to each girl, last girl had only 6 - ie short of 5.

25 + 5 = 30
11-8 = 3
30 / 3 = 10, so there were 10 girls.
Number of sweets = 8 x 10 + 25 = 105.

cheers.

[bobsg01]

Thank you MathIzzzFun for the solution.


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