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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • T Offline
      tianzhu
      last edited by

      fxchow:

      1) Mrs Gopal and Mrs Ari went to the supermarket.
      Both women decided to spend all their money on either apples or pears and they would not buy the same fruit.
      If Mrs Gopal bought only pears, she would have 9 more fruit than Mrs Ari.
      If she bought only apples, she would have 41 more fruit than Mrs Ari.
      How much more money has Mrs Gopal than Mrs Ari?
      Ans: $12
      Hi

      This question has been discussed in one of the earlier posts.

      Please refer to the solution from kancheongmum.

      After reading Tianzhu post, lead me to solve this question using this method which is not new. The question of Tom spend $40 per day and Mary spend $80 per day and Mary would have $500 left when Tom has spent all his money .......

      Apples : Pears ---- 40:60 ---- 2:3

      1st case Ari spent 2/3 of Gopal 2nd case Ari spent 3/2 of Gopal
      equal fraction 2/3 = 6/9 and 3/2 = 6/4

      Gopal ()()()()()()()()() $5.40
      Ari ()()()()()()

      Gopal ()()()() $16.40
      Ari ()()()()()()


      9u + $5.40 = 4u + $16.40
      5u ---- $11
      1u ---- $2.20
      Gopal money more than Ari by ---- 3u + $5.40 = (3 x $2.20) + $5.40
      = $12

      Best wishes

      1 Reply Last reply Reply Quote 0
      • S Offline
        SaPan
        last edited by

        MathIzzzFun:
        ...

        Q1...
        http://i55.tinypic.com/m9n69u.jpg\">

        Q2.. http://www.flickr.com/photos/62167097@N02/5897096477/in/photostream

        cheers.
        thank you so much, MathIzzzFun!

        pls allow me another question, :-
        is it possible to solve such questions using units and parts?

        1 Reply Last reply Reply Quote 0
        • Z Offline
          zsqchx
          last edited by

          Please help to solve the following question. Thanks.


          Sam went shopping at a department store. He spent 1/5 of his money on a soft set and $800 on a washing machine. Later, he spent 1/8 of his remaining amount on dining table. If the amount of money left was $100 more than half of the amount he had at first, how much money did Sam have at first?

          1 Reply Last reply Reply Quote 0
          • D Offline
            Dharma
            last edited by

            zsqchx:
            Please help to solve the following question. Thanks.


            Sam went shopping at a department store. He spent 1/5 of his money on a soft set and $800 on a washing machine. Later, he spent 1/8 of his remaining amount on dining table. If the amount of money left was $100 more than half of the amount he had at first, how much money did Sam have at first?
            If Sam had 100u at first
            Spent 1/5 of sofa => 20u
            Spent on washing machine => $800
            Remainder => 100u – (20u +$800) = 80u - $800
            Spent 1/8 of remainder on dining table; so he’ll be left with 7/8 of remainder i.e. (70u - $700)
            (70u - $700) – (100u/2) = $100
            20u - $700 = $100
            20u = $800
            1u = $40
            Amt San had at first = 100u = $4000

            1 Reply Last reply Reply Quote 0
            • MathIzzzFunM Offline
              MathIzzzFun
              last edited by

              zsqchx:
              Please help to solve the following question. Thanks.


              Sam went shopping at a department store. He spent 1/5 of his money on a soft set and $800 on a washing machine. Later, he spent 1/8 of his remaining amount on dining table. If the amount of money left was $100 more than half of the amount he had at first, how much money did Sam have at first?
              Hi

              a model approach πŸ˜„

              http://www.flickr.com/photos/62167097@N02/5899971661/in/photostream

              cheers.

              1 Reply Last reply Reply Quote 0
              • MathIzzzFunM Offline
                MathIzzzFun
                last edited by

                SaPan:
                MathIzzzFun:

                ...

                Q1...
                http://i55.tinypic.com/m9n69u.jpg\">

                Q2.. http://www.flickr.com/photos/62167097@N02/5897096477/in/photostream

                cheers.

                thank you so much, MathIzzzFun!

                pls allow me another question, :-
                is it possible to solve such questions using units and parts?

                Hi SaPan,

                yes, you can also solve such questions using the units and parts approach ie algebra... by the way, model approach is algebra in visual form.

                cheers.

                1 Reply Last reply Reply Quote 0
                • F Offline
                  fxchow
                  last edited by

                  MathIzzzFun:
                  fxchow:

                  Hi,


                  Can someone help to solve these two questions. TIA πŸ˜„

                  1) Mrs Gopal and Mrs Ari went to the supermarket.
                  Both women decided to spend all their money on either apples or pears and they would not buy the same fruit.
                  If Mrs Gopal bought only pears, she would have 9 more fruit than Mrs Ari.
                  If she bought only apples, she would have 41 more fruit than Mrs Ari.
                  How much more money has Mrs Gopal than Mrs Ari?
                  Ans: $12

                  2) Talik was given some pocket money for recess. He realised that if he had spent $0.80 on each meal, he would have 8 meals fewer than if he had spent $0.60 per meal.
                  Talik spent $0.60 on 8 meals and spent $0.80 on the remaining meals. How many meals did the money last him?
                  Ans: $26

                  Hi fxchow,

                  Q1 is missing some information - costs of fruits for eg.

                  For Q2,

                  If Talik spent $0.60 per meal, he would have 8 more meals ---> 8 x 0.60 = $4.80. This amount was accumulated from spending $0.20 less per meal. So, number of $0.80 meals = $4.80 / 0.20 = 24

                  Amount of money he had = 24 x $0.80 = $19.20

                  After spending 8 x $0.60 meals, number of $0.80 meals he could have
                  = ($19.20 - $4.80) / $0.80
                  = 144 / 8
                  = 18

                  Total number of meals ($0.60 meals + $0.80 meals) = 8 x+ 18 = 26

                  cheers.

                  Hi MathIzzzFun,

                  Sorry, for question 1, each apple costs $0.40 while each pear costs $0.60.

                  Thanks!

                  1 Reply Last reply Reply Quote 0
                  • S Offline
                    SaPan
                    last edited by

                    MathIzzzFun:
                    ...

                    Hi SaPan,

                    yes, you can also solve such questions using the units and parts approach ie algebra... by the way, model approach is algebra in visual form.

                    cheers.
                    thanks again MathIzzzFun, I'll try and solve it using the unit and parts ways. πŸ™‚

                    1 Reply Last reply Reply Quote 0
                    • A Offline
                      Angel25
                      last edited by

                      A rectangular tank, 1m long, 80cm wide and 40cm high was filled with some water. 8 metal cubes of equal volume were placed in the water and 1200cm3 of water overflowed from the tank. Jacob then took 3 metal cubes from the water carefully and the height of the water in the tank was 37cm, (taking 1litre=1000cm3)

                      a) what was the volume of each metal cube?
                      b) what was the length of each metal cube?
                      c) how many litres of water were in the tank before 8 metal cubes were put in?

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                      • A Offline
                        Angel25
                        last edited by

                        This is a P6 Question:-


                        Two tins of different sizes weigh individually. The bigger tin measuring 1m by 50cm by 40cm has a mass of 24kg when it is filled with 100 metal bars, each weighing 200g.
                        Find the mass of the smaller rectangular empty tin which is made of the same material and is 80cm by 30cm by 20cm.
                        (heuristics skills - Before - After concept)

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