Q&A - PSLE Math
-
Daddy:
HiHi,
Need help!! Thanks
An empty tank with a capacity of 48.4 litres. Water flows from TapA at 3.2 litres per min and from Tap B at 2.8 litres per min.
Tap A was turned on first. Tap B was turned on 2 min later. The taps were turned off at the same time when the tank was completely filled without overflowing. How much water flowed from Tap B?
Thanks
After Tap A was turned on for 2 min, volume of water in tank = 2 x 3.2L= 6.4L
Remaining volume of tank to be filled = 48.4L - 6.4L = 42L
When both Tap A and Tap B were turned on, the total flow rate = 3.2L/min+2.8L/min = 6L / min
42L / 6L/min = 7 min
So, with both taps running, it would take another 7 min to fill the tank to the brim.
Amount of water from Tap B = 7min x 2.8L/min = 19.6L
cheers. -
Thanks MathIzzzFun & ivanhoo99.
Is 48.4L= 48400cm2 or 48400cm3. Convert litres to cm square or cm cube? which is which? Thanks. -
Daddy:
Thanks MathIzzzFun & ivanhoo99.
Is 48.4L= 48400cm2 or 48400cm3. Convert litres to cm square or cm cube? which is which? Thanks.
litres convert to cubic cm.
1 litre = 1000 cubic cm.
So 48.4 l = 48400 cubic cm or cm3
Reason = litres measure volume and to get volume from cm, it has to be cubic cm or cm3.....that will be easy for the children to remember. cm2 only give areas. -
Daddy:
HiThanks MathIzzzFun & ivanhoo99.
Is 48.4L= 48400cm2 or 48400cm3. Convert litres to cm square or cm cube? which is which? Thanks.
for volume, it is cm3 or cubic cm, 1000 cubic cm (cm3) = 1l = 1000 ml
for area, it is cm2 square cm.
cheers. -
Hi all,
Have a problem here…
A pail contains some pebbles and water. The total volume of the pebbles and water in the pail is 2300 cm3. A cube-shaped tank containing some water has a base area of 361 cm2. The ratio of the volume of water in the tank to the total volume of pebbles and water in the pail is 3:5. What is the water level in the tank? Give your answer in cm, correct to 2 decimal places.
(a) Find the increase in water level of the tank in cm.
(b) A stick is 13cm long. If the stick just touches the water surface in the cube-shaped tank vertically, find the length of the stick that is exposed outside the tank. -
Thanks MathIzzzFun.
Have another math question to ask.
Joey had 5 time as much money as her brother, John. After her father gave her $59 and gave John $49. Joey now had twice as much as John. How much did Joey have at first.
Thank
Daddy -
stary:
Vol of water in tank : vol of pebbles and water = 3 : 5Hi all,
Have a problem here...
A pail contains some pebbles and water. The total volume of the pebbles and water in the pail is 2300 cm3. A cube-shaped tank containing some water has a base area of 361 cm2. The ratio of the volume of water in the tank to the total volume of pebbles and water in the pail is 3:5. What is the water level in the tank? Give your answer in cm, correct to 2 decimal places.
(a) Find the increase in water level of the tank in cm.
(b) A stick is 13cm long. If the stick just touches the water surface in the cube-shaped tank vertically, find the length of the stick that is exposed outside the tank.
3: 5 = V : 2300
V = 3/5 x 2300 = 1380
Base area of tank = 361
Hence water level = 1380/361 = 3.82cm
Is there missing information? Something must happen to cause an increase in the water level to solve (a), eg, the pail's water and pebbles poured into the cube?? -
Daddy:
Hi,Thanks MathIzzzFun.
Have another math question to ask.
Joey had 5 time as much money as her brother, John. After her father gave her $59 and gave John $49. Joey now had twice as much as John. How much did Joey have at first.
Thank
Daddy
Joey : John
5 units : 1 unit
+$59 +$49
2 parts : 1 part
2 units + $98 = 5 units + $59
3 units -> $98-$59 = $39
5 units -> 5/3 x $39 = $65
Cheers! -
ksi:
Hi ksi, i've added the missing info...
Vol of water in tank : vol of pebbles and water = 3 : 5stary:
Hi all,
Have a problem here...
A pail contains some pebbles and water. The total volume of the pebbles and water in the pail is 2300 cm3. A cube-shaped tank containing some water has a base area of 361 cm2. The ratio of the volume of water in the tank to the total volume of pebbles and water in the pail is 3:5. What is the water level in the tank? Give your answer in cm, correct to 2 decimal places.
When all the pebbles are transferred fro the pail to the cube-shaped tank, the total volume of water and pebbles in the tank becomes 2282.5 cm3.
(a) Find the increase in water level of the tank in cm.
(b) A stick is 13cm long. If the stick just touches the water surface in the cube-shaped tank vertically, find the length of the stick that is exposed outside the tank.
3: 5 = V : 2300
V = 3/5 x 2300 = 1380
Base area of tank = 361
Hence water level = 1380/361 = 3.82cm
Is there missing information? Something must happen to cause an increase in the water level to solve (a), eg, the pail's water and pebbles poured into the cube??
-
stary:
Hi ksi, i've added the missing info...
Vol of water in tank : vol of pebbles and water = 3 : 5ksi:
[quote=\"stary\"]Hi all,
Have a problem here...
A pail contains some pebbles and water. The total volume of the pebbles and water in the pail is 2300 cm3. A cube-shaped tank containing some water has a base area of 361 cm2. The ratio of the volume of water in the tank to the total volume of pebbles and water in the pail is 3:5. What is the water level in the tank? Give your answer in cm, correct to 2 decimal places.
When all the pebbles are transferred fro the pail to the cube-shaped tank, the total volume of water and pebbles in the tank becomes 2282.5 cm3.
(a) Find the increase in water level of the tank in cm.
(b) A stick is 13cm long. If the stick just touches the water surface in the cube-shaped tank vertically, find the length of the stick that is exposed outside the tank.
3: 5 = V : 2300
V = 3/5 x 2300 = 1380
Base area of tank = 361
Hence water level = 1380/361 = 3.82cm
Is there missing information? Something must happen to cause an increase in the water level to solve (a), eg, the pail's water and pebbles poured into the cube??
[/quote](a) When pebbles are added in , the volume of the pebbles will be the volume of water raised in the tank.
Volume of pebbles = 2282.5-1380 = 902.5
So level of water increase = 902.5/361 = 2.5cm
(b) Height of the tank = Sq root of 361 = 19 (because it is a cubic tank)
So if water is at 2.5+3.82= 6.32cm
19-6.32 = 12.68cm
So the length of stick exposed outside the tank would be 13-12.68=0.32cm.
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