Tutor MathsGuru: Ask me for your burning Maths questions!

[wahwah]

Hi MathIzzzFun,

Thanks for the solution!

[ozora]

Need help. Unable to comprehend " with the same amount of money?" Does it mean $90?

How to solve?
Jane bought some pens at $90. If she was given a discount of 20% on her purchase, she would be able to buy 6 more pens wuth the same amount of money. Find the usual price of 1 pen.

[andante]

Hi,

pls help to solve the following question WITHOUT using simultaneous equation.

There was a total of 2400 red, blue and green marbles in Box A and Box B at first. The number of marbles in Box A was twice the number of marbles in Box B. In Box A, The number of red marbles is 25% of the total number of blue and green marbles. The number of blue and green marbles in Box B is 60% of the total number of marbles in Box B. After transferring some marbles between each other, 25% of the marbles in Box A and 75% of marbles in Box B were red. How many marbles were there in Box A after the change?

[MathIzzzFun]

ozora:

Need help. Unable to comprehend \" with the same amount of money?\" Does it mean $90?

How to solve?
Jane bought some pens at $90. If she was given a discount of 20% on her purchase, she would be able to buy 6 more pens with the same amount of money. Find the usual price of 1 pen.

Hi

Discount of 20% = $90 x 0.2 = $ 18
1 pen = $ 18/6 = $3 = 80% of original price

So original price = 10/8 x $3 = $ 3.75 / pen

cheers.

[MathIzzzFun]

wahwah:

Hi MathIzzzFun,

Thanks for the solution!

u r welcome

cheers.

[MathIzzzFun]

andante:

Hi,

pls help to solve the following question WITHOUT using simultaneous equation.

There was a total of 2400 red, blue and green marbles in Box A and Box B at first. The number of marbles in Box A was twice the number of marbles in Box B. In Box A, The number of red marbles is 25% of the total number of blue and green marbles. The number of blue and green marbles in Box B is 60% of the total number of marbles in Box B. After transferring some marbles between each other, 25% of the marbles in Box A and 75% of marbles in Box B were red. How many marbles were there in Box A after the change?

Hi

hope this helps

http://www.flickr.com/photos/62167097@N02/5997248173/in/photostream

cheers.

[ozora]

MathIzzzFun:

ozora:

Need help. Unable to comprehend \" with the same amount of money?\" Does it mean $90?

How to solve?
Jane bought some pens at $90. If she was given a discount of 20% on her purchase, she would be able to buy 6 more pens with the same amount of money. Find the usual price of 1 pen.

Hi

Discount of 20% = $90 x 0.2 = $ 18
1 pen = $ 18/6 = $3 = 80% of original price

So original price = 10/8 x $3 = $ 3.75 / pen

cheers.

oic
thanks

[andante]

MathIzzzFun:

andante:

Hi,

pls help to solve the following question WITHOUT using simultaneous equation.

There was a total of 2400 red, blue and green marbles in Box A and Box B at first. The number of marbles in Box A was twice the number of marbles in Box B. In Box A, The number of red marbles is 25% of the total number of blue and green marbles. The number of blue and green marbles in Box B is 60% of the total number of marbles in Box B. After transferring some marbles between each other, 25% of the marbles in Box A and 75% of marbles in Box B were red. How many marbles were there in Box A after the change?

Hi

hope this helps

http://www.flickr.com/photos/62167097@N02/5997248173/in/photostream

cheers.

Hi,
Thanks for the solution but I dont really understand why 2400/ 4 ?
why 4 ? how to group as 4 ? and 640-600/2 why 2 ?

[MathIzzzFun]

andante:

MathIzzzFun:

[quote=\"andante\"]Hi,

pls help to solve the following question WITHOUT using simultaneous equation.

There was a total of 2400 red, blue and green marbles in Box A and Box B at first. The number of marbles in Box A was twice the number of marbles in Box B. In Box A, The number of red marbles is 25% of the total number of blue and green marbles. The number of blue and green marbles in Box B is 60% of the total number of marbles in Box B. After transferring some marbles between each other, 25% of the marbles in Box A and 75% of marbles in Box B were red. How many marbles were there in Box A after the change?

Hi

hope this helps

http://www.flickr.com/photos/62167097@N02/5997248173/in/photostream

cheers.

Hi,
Thanks for the solution but I dont really understand why 2400/ 4 ?
why 4 ? how to group as 4 ? and 640-600/2 why 2 ?[/quote]Hi

After transfer,

Box A = @ @ @ @
Box B = * * * *
Total in Box A + Box B = 2400,
so @ + * = 2400 / 4 = 600 (there are 4 groups of \"@ + *\" in Box A & Box B)

25% of Box A and 75% of Box B are red,
so @ + * * * = 640,

since @ + * = 600, * * = 640-600, * = (640-600)/2 = 20

cheers.

[andante]

MathIzzzFun:

andante:

[quote=\"MathIzzzFun\"]Hi,

pls help to solve the following question WITHOUT using simultaneous equation.

There was a total of 2400 red, blue and green marbles in Box A and Box B at first. The number of marbles in Box A was twice the number of marbles in Box B. In Box A, The number of red marbles is 25% of the total number of blue and green marbles. The number of blue and green marbles in Box B is 60% of the total number of marbles in Box B. After transferring some marbles between each other, 25% of the marbles in Box A and 75% of marbles in Box B were red. How many marbles were there in Box A after the change?

Hi

hope this helps

http://www.flickr.com/photos/62167097@N02/5997248173/in/photostream

cheers.

Hi

After transfer,

Box A = @ @ @ @
Box B = * * * *
Total in Box A + Box B = 2400,
so @ + * = 2400 / 4 = 600 (there are 4 groups of \"@ + *\" in Box A & Box B)

25% of Box A and 75% of Box are red,
so @ + * * * = 640,

since @ + * = 600, * * = 640-600, * = (640-600)/2 = 20

cheers.[/quote]Thank you very much