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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • MathIzzzFunM Offline
      MathIzzzFun
      last edited by

      Jazpy:
      Qn: At first, Kumar had only $5-notes and Devi had only $2-notes. The number of notes Kumar had is 2/3 of Devi's notes. When Devi gave Kumar $80, he changed all the $80 to $5 notes. Then the number of notes Devi has now is 10% more than Kumar. How many notes does Devi have at the end????



      Please help
      Hi

      At first,
      Number of $5 notes : Number of $2 notes = 2 : 3
      Value of $5 notes : Value of $2 notes = 2 x 5 : 3 x 2 = 10 : 6 = 5 : 3

      In the end,
      number of $5 notes : number of $2 notes = 10 : 11
      Value of $5 notes : Value of $2 notes = 10 x 5 : 11 x 2 = 50 : 22

      Total value remained the same,
      At first, Value of $5 notes : Value of $2 notes = 5 : 3 = 45u : 27u (total 72u)
      In the end, Value of $5 notes : Value of $2 notes = 50u : 22u (total 72u)

      So, 50u – 45u = 5u = $80, 1u = $16

      Number of $2 notes in the end = 22u /($2) = 22 x 16 / 2 = 176

      alternative approach using MD - http://www.flickr.com/photos/62167097@N02/6010152839/in/photostream/

      cheers.

      1 Reply Last reply Reply Quote 0
      • M Offline
        matrix0405
        last edited by

        Math models: Using Before & After approach + Percentage.


        http://www.youtube.com/watch?v=_f2enjbMrLA

        1 Reply Last reply Reply Quote 0
        • S Offline
          stary
          last edited by

          atutor2001:
          stary:

          Hi all,


          Can someone explain/show me the workings of this question?

          http://www.flickr.com/photos/64113082@N03/6007585363/in/photostream
          Ans: 5
          (SCGS Prelim 2010 P6 Question 3)

          Thanks!

          Add the numbers at the 4 corners and divide by 4. (the middle number is the average)

          Thanks a lot!

          1 Reply Last reply Reply Quote 0
          • S Offline
            stary
            last edited by

            matrix0405:
            Math models: Using Before & After approach + Percentage.


            http://www.youtube.com/watch?v=_f2enjbMrLA
            :goodpost: :goodpost:

            1 Reply Last reply Reply Quote 0
            • S Offline
              stary
              last edited by

              Hi all,


              Have a question to ask u all...

              There were some fruits in a warehouse. 3/7 of them were apples and the rest were oranges. After throwing away 27 apples and 1/4 of the oranges that were rotten, there were 3/5 of the fruits left.
              (a) How many fruits were thrown away?
              (b) How many apples were there at first?

              :?

              1 Reply Last reply Reply Quote 0
              • A Offline
                atutor2001
                last edited by

                stary:
                Hi all,


                Have a question to ask u all...

                There were some fruits in a warehouse. 3/7 of them were apples and the rest were oranges. After throwing away 27 apples and 1/4 of the oranges that were rotten, there were 3/5 of the fruits left.
                (a) How many fruits were thrown away?
                (b) How many apples were there at first?

                :?
                Using ratio to solve :

                Apple : Orange : Total = 3 : 4 : 7 (Before)
                Because the fruits left is given as 3/5 of \"Before\", the total of \"before\" must be divisible by 5. So x 5 to the ratio

                Apple : Orange : Total = 15U : 20U : 35U (Before)
                Apple : Orange : Total = -27 : -5U : (??) (Fruits thrown away)
                Apple : Orange : Total = (15U-27) : 15U : 21U (After)

                The decrease in the total is 35U - 21U = 14U
                The fruits thrown away is 27+5U

                Therefore, 14U = 27 + 5U
                9U = 27
                U = 3

                Total fruits thrown away is 14U = 42
                Total apples (at first) is 15U = 45

                1 Reply Last reply Reply Quote 0
                • S Offline
                  stary
                  last edited by

                  atutor2001:
                  stary:

                  Hi all,


                  Have a question to ask u all...

                  There were some fruits in a warehouse. 3/7 of them were apples and the rest were oranges. After throwing away 27 apples and 1/4 of the oranges that were rotten, there were 3/5 of the fruits left.
                  (a) How many fruits were thrown away?
                  (b) How many apples were there at first?

                  :?

                  Using ratio to solve :

                  Apple : Orange : Total = 3 : 4 : 7 (Before)
                  Because the fruits left is given as 3/5 of \"Before\", the total of \"before\" must be divisible by 5. So x 5 to the ratio

                  Apple : Orange : Total = 15U : 20U : 35U (Before)
                  Apple : Orange : Total = -27 : -5U : (??) (Fruits thrown away)
                  Apple : Orange : Total = (15U-27) : 15U : 21U (After)

                  The decrease in the total is 35U - 21U = 14U
                  The fruits thrown away is 27+5U

                  Therefore, 14U = 27 + 5U
                  9U = 27
                  U = 3

                  Total fruits thrown away is 14U = 42
                  Total apples (at first) is 15U = 45

                  Thanks! :thankyou:

                  1 Reply Last reply Reply Quote 0
                  • S Offline
                    Saralala
                    last edited by

                    tianzhu:
                    1) There were some marbles at a shop. The ratio of the number of red marbles to the number of blue marbles was 2:3. When 50 more red marbles and 30 more blue marbles were added, the ratio of the number of red marbles to the number of blue marbles became 5:6. How many marbles were there at first?

                    Let me try to solve the first question:

                    Method 1:

                    If you use algebra, it will be rather fast (trained my son to do so as PSLE still allows):

                    2x + 50 = (5/6) (3x +30)
                    x = 50

                    5 units at the start so 50 x 5 = 250 marbles at first.

                    -----------------------------------------------------------------
                    Method 2 (Diagrams):

                    Draw 2 units for red and 3 units for blue.

                    For red, draw dotted unit for 50 extra red and a 1 unit size to fill up 5:6 to become 6:6.

                    For blue, just add 30 extra blue as dotted unit.

                    Thus, 30 + 1 big unit = 50 + 1 small unit

                    We can say 1 big unit - 1 small unit = 20.

                    --- Look at red units now. There are 2 big units and 1 50 dotted unit. So 2 small units + 20 + 20 +50 = 5 small units.

                    3 small units = 90
                    1 small unit = 30

                    2 big unit = 30 x 5 - 50
                    = 100

                    5 big units = 100/ 2 * 5
                    = 250.

                    Alright, sorry if it sounds very difficult, but I don't think it is if I can draw. Haha. Too lazy to draw. :x

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                    • H Offline
                      Hifive
                      last edited by

                      Hi all,


                      Need help with this question:

                      During a basketball match, the teacher promised the team of 8 pupils an equal playing time during the 40 minutes match. Given that only 5 players can play at any one time, what is the average playing time for each pupil?

                      Thanks in advance.

                      1 Reply Last reply Reply Quote 0
                      • MathIzzzFunM Offline
                        MathIzzzFun
                        last edited by

                        Hifive:
                        Hi all,


                        Need help with this question:

                        During a basketball match, the teacher promised the team of 8 pupils an equal playing time during the 40 minutes match. Given that only 5 players can play at any one time, what is the average playing time for each pupil?

                        Thanks in advance.
                        Hi

                        Divide 40 minutes into 8 x 5 minutes time slots, and for each 5 min slot, there will be 5 playing slots, total 5 x 8 playing slots. So, each will get 5 playing slots ie 5 x 5 = 25 min.

                        http://i55.tinypic.com/24cd3r4.jpg\">

                        cheers.

                        1 Reply Last reply Reply Quote 0

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