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    O-Level Additional Math

    Scheduled Pinned Locked Moved Secondary Schools - Academic Support
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    • H Offline
      Herbie
      last edited by

      hi tianzhu, many thanks!


      I hv another qn.

      15 men working 8 hours a day can build a bridge in 30 days.
      How long will 9 men working 8 hours a day take to buiild the same ridge assuming that the rate at which they work remains unchanged? My ans is 50 days.

      B. How many hours a day must 25 men work to build the same bridhe in 16 days!

      Tq

      1 Reply Last reply Reply Quote 0
      • T Offline
        tianzhu
        last edited by

        Herbie:

        15 men working 8 hours a day can build a bridge in 30 days.
        How long will 9 men working 8 hours a day take to buiild the same ridge assuming that the rate at which they work remains unchanged? My ans is 50 days.

        B. How many hours a day must 25 men work to build the same bridhe in 16 days!
        Hi

        Your answer of 50 days for part A is right.

        For part B,
        1 bridge ------ 15*30*8 ------- 3600 man-hours

        Number of men*number of days*number of hours ------- 3600 man-hours

        25*16*h ------- 3600 where h refers to the number of hours the men must work.

        h ------- 9 hours.

        Best wishes

        1 Reply Last reply Reply Quote 0
        • T Offline
          tutor4kids
          last edited by

          Hi, thank you for the solution.

          Could you have me with the following question?

          In the diagram below, ACB is a tangent to the circle at point C. This tangent is parallel to the line FE. Points F, G and H lie on the circle.
          i) Prove that (EC)(CG) = (CF)^2.
          ii) The line FE is extended to meet the circle at H. Prove (FE)(EH) = CF^2 - EC^2.

          http://i52.tinypic.com/33zd7hv.jpg\">

          Thank you.

          1 Reply Last reply Reply Quote 0
          • F Offline
            FrekiWang
            last edited by

            (i) (this is a very standard A Maths Question, Similarity is one of the standard approaches)

            In FEC and GFC,
            AngleEFC=AngleFCA=AngleFGC (hopefully you know why)
            AngleFCE=AngeGCF
            Thus FEC is similar to GFC
            FE/GF=EC/FC=FC/GC
            Cross-multiply 2nd and 3rd, we have EC x GC = FC^2(proven)

            (ii) (usually (ii) is related to (i))
            RHS=CF^2-EC^2
            =EC x GC - EC^2 (from part (i))
            =EC x (GC - EC)
            =EC x GE
            =FE x EH (intersecting chords thereom)
            =LHS (proven)
            Seriously, part(ii) is much easier. In the exam/test, if you cant prove part(i), you can always assume part(i) result and use it to prove part(ii)

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            • T Offline
              tutor4kids
              last edited by

              Hi,


              Thank you very much for the prompt reply! I can understand the solution.
              Thanks once again.

              1 Reply Last reply Reply Quote 0
              • F Offline
                FrekiWang
                last edited by

                tutor4kids:
                Hi,


                Thank you very much for the prompt reply! I can understand the solution.
                Thanks once again.
                Seriously, if you are a home tutor teaching A Maths, I would like to advise that you need more preparation for this topic. A lots of students are having problems in this topic so most likely they are going to ask a lot.

                1 Reply Last reply Reply Quote 0
                • T Offline
                  tutor4kids
                  last edited by

                  Hi, thanks for the advice. I am not a home tutor for A Maths though, just seeking help on behalf of a friend. Anyway, thanks for your help.

                  1 Reply Last reply Reply Quote 0
                  • H Offline
                    Herbie
                    last edited by

                    hi uncle tianzhu. Thanks very much.

                    1 Reply Last reply Reply Quote 0
                    • G Offline
                      g131271
                      last edited by

                      Hi parents,


                      Does anyone of you can help me in this question? A million thanks to those who help to solve.

                      [b]A regular polygon has n sides. The size of each interior angle is 4 times the size of each exterior angle.
                      a. calculate the value of each exterior angle.
                      b. calculate the value of n.
                      c. hence find the sum of interior angles of polygon

                      1 Reply Last reply Reply Quote 0
                      • T Offline
                        tianzhu
                        last edited by

                        Herbie:
                        hi uncle tianzhu. Thanks very much.

                        Hi

                        You're welcome.

                        Best wishes

                        1 Reply Last reply Reply Quote 0

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