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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • T Offline
      tianzhu
      last edited by

      Hifive:


      Hi tianzhu

      Thanks for your help!

      Need to clarify :

      I do not understand why Jack and Sam had a combined speed of 150m/min, I've got it as 130m/min ? Pls advise.
      Hi

      I am sorry, it should be read as Sam and Nasim had a combined speed of 150m/min.

      Best wishes

      1 Reply Last reply Reply Quote 0
      • H Offline
        Hifive
        last edited by

        Hi tianzhu


        Got it. Thank you, thank you!

        1 Reply Last reply Reply Quote 0
        • T Offline
          tianzhu
          last edited by

          Hifive:
          Hi tianzhu


          Got it. Thank you, thank you!
          Hi Hifive

          You're welcome.

          Best wishes

          1 Reply Last reply Reply Quote 0
          • 2 Offline
            2centsworthy
            last edited by

            :thankyou:

            WCW:
            2centsworthy:

            Please help to solve the following:

            Ron had some chocolates and sweets. If Ron sold 18 chocolates and 24 sweets each day, there would still be 25 chocolates left when all the sweets were sold. If Ron sold 13 chocolates and 30 sweets each day, he would still have 139 chocolates left when all the sweets were sold. How many chocolates and sweets did Ron have?

            My method is find the common multiple for 24 and 30. think someone might have an easier and faster way?

            Common muliples of 24 and 30
            120, 240, 360

            C : S
            18 : 24
            18*15 : 24*15
            +25

            C : S
            13 : 30
            13*12 : 30*12
            +139

            C=295
            S=360

            1 Reply Last reply Reply Quote 0
            • D Offline
              Daddy
              last edited by

              Hi,


              I have a question to ask.

              1. grandpa had a farm. He kept 89 goats and chickens. The total number of legs the animals had was 264 legs. How many chickens did grandpa have?

              If use guess and check methode would be very long time to find the anwer. Is there any short way to solve above question?
              Thanks…

              1 Reply Last reply Reply Quote 0
              • MathIzzzFunM Offline
                MathIzzzFun
                last edited by

                Daddy:
                Hi,


                I have a question to ask.

                1. grandpa had a farm. He kept 89 goats and chickens. The total number of legs the animals had was 264 legs. How many chickens did grandpa have?

                If use guess and check methode would be very long time to find the anwer. Is there any short way to solve above question?
                Thanks....
                Hi

                use the assumptive method...

                assume all are goats OR all are chickens first.

                say, all are goats, then total legs = 4 x 89 = 356
                \"extra\" legs = 356 - 264 = 92
                the \"extra\" legs are due to counting chickens as goats.. ie 2 extra legs counted, so number of chickens = 92/2 = 46
                89 - 46 = 43 goats

                so, 46 chickens & 43 goats.

                cheers.

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                • D Offline
                  dnsy
                  last edited by

                  MathIzzzFun - Thanks!

                  1 Reply Last reply Reply Quote 0
                  • ozoraO Offline
                    ozora
                    last edited by

                    need quick help:

                    Some plates and cups were packed into blue and red boxes.There were 12 more blue boxes than red boxes.Each blue box contained 120 plates and each red box contained 150 plates.Given that there were 120 fewer plates than cups in total,how many plates were there?
                    Thanks in advance

                    1 Reply Last reply Reply Quote 0
                    • MathIzzzFunM Offline
                      MathIzzzFun
                      last edited by

                      ozora:
                      need quick help:

                      Some plates and cups were packed into blue and red boxes.There were 12 more blue boxes than red boxes.Each blue box contained 120 plates and each red box contained 150 plates.Given that there were 120 fewer plates than cups in total,how many plates were there?
                      Thanks in advance
                      Hi

                      this is a variation of the typical \"counting coins\" problem sum.

                      There are 120 more cups than plates...& 12 more blue boxes (cups) than red boxes (plates)

                      each blue box has 30 less cups than plates in red box.

                      make the number of boxes the same - either add red boxes, or remove blue boxes. Since we are looking for number of plates (red boxes), we remove blue boxes.

                      remove 12 blue boxes so that there are now equal number of boxes.
                      12 x 120 cups = 1440 cups, there are now 1440 - 120 = 1320 lesser cups than plates in the boxes.

                      each blue box has 30 less cups than plates in red boxes, 1320 / 30 = 44
                      there are 44 red boxes and 44+12 = 56 blue boxes

                      number of plates = 44 x 150 = 6600

                      cheers.

                      1 Reply Last reply Reply Quote 0
                      • ozoraO Offline
                        ozora
                        last edited by

                        MathIzzzFun:
                        ozora:

                        need quick help:

                        Some plates and cups were packed into blue and red boxes.There were 12 more blue boxes than red boxes.Each blue box contained 120 plates and each red box contained 150 plates.Given that there were 120 fewer plates than cups in total,how many plates were there?
                        Thanks in advance

                        Hi

                        this is a variation of the typical \"counting coins\" problem sum.

                        There are 120 more cups than plates...& 12 more blue boxes (cups) than red boxes (plates)

                        each blue box has 30 less cups than plates in red box.

                        make the number of boxes the same - either add red boxes, or remove blue boxes. Since we are looking for number of plates (red boxes), we remove blue boxes.

                        remove 12 blue boxes so that there are now equal number of boxes.
                        12 x 120 cups = 1440 cups, there are now 1440 - 120 = 1320 lesser cups than plates in the boxes.

                        each blue box has 30 less cups than plates in red boxes, 1320 / 30 = 44
                        there are 44 red boxes and 44+12 = 56 blue boxes

                        number of plates = 44 x 150 = 6600

                        cheers.

                        thanks.. may i know how to get\" each blue box has 30 less cups than plates in red box.\"


                        it looked so easy to you but really tough on me and the kids to comprehend.

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