O-Level Additional Math

[Xiao Hu]

Hi FrekiWang,

Oh mine! You are great!! When I first wrote my question, I was saying I just coundn’t find at least 1 more point or a gradient. But I have to rewrite bec was having trouble to load the image of the question. I left out the word gradient.

THanks so much for your prompt reply and kind help!!

You are good,
Xiao Hu

[FrekiWang]

Xiao Hu:

Hi FrekiWang,

Oh mine! You are great!! When I first wrote my question, I was saying I just coundn't find at least 1 more point or a gradient. But I have to rewrite bec was having trouble to load the image of the question. I left out the word gradient.

THanks so much for your prompt reply and kind help!!

You are good,
Xiao Hu

lol, you are welcome

[Xiao Hu]

Hi FrekiWang,


May I ask more about this question I posted.
What if the sign in the question is changed from + to -?

Quote part of your solution below:
=sqrt[2+sqrt(4cos^2(x/2))]
Note here, 135<x/2<180 (2nd), so cos(x/2) is negative.
=sqrt[2-2cos(x/2)]<--- I suppose your mistake is because you have +2cos(x/2) in this step, I will explain this at the end.

So we would have to change the sign to + when we take out the perfect square cos(x/2) out of the root?

Thanks in advance,
Xiao Hu

[FrekiWang]

Whenever you take out the square of a negative expression out the root, you have to add a negative in front.


eg.

sqrt(9a)=3sqrt(a) (you are taking the square of 3 out. so no need to do anything)

Given a>0
sqrt(2a^2)=asqrt(2) (you are taking the square of a out, and you know a is positive, so no need to do anything)

Given a<0
sqrt(2a^2)=-asqrt(2) (you are taking the square of a out, and you know a is negative, so a negative sign is needed)

[Xiao Hu]

CoffeeCat:

midnightspark:

Hi,


Just asking some sec 2 maths questions, please help


1)
A rectangle of sides x cm and y cm has an area of 72 cm2. Another rectangle of sides (x+1.5) and (y-4)cm has the same area. Find the values of x and y.

2)
When 5 is added to both the numerator and denominator of a fraction, the result becomes 1/2. When 1 is subtracted from both the numerator and the denominator, the fraction becomes 1/5. Find the fraction.

3)
The scale of map X is 1: x and the scale of map Y is 1:y. If the same distance is represented as 5cm on map X and 7.5cm on map Y, calculate the ratio x:y.

Thanks.

For qns 2, use algebra.
let the original fraction be x/y.
(x+5)/(y+5) = 1/2
cross multiplying, 2x + 10 = y+ 5
2x + 5 = y
(x-1)/ (y-1) = 1/5
5x - 5 = y - 1
......

For qns 1
xy = 72
(x+1.5)(y-4) = 72
let y= (72/x) and substitute . You will get a quadratic equation after multiplying the whole equation by x.

For qns 3,
5x = 7.5y
x/y = 7.5/5 = ...

hmmm too busy to give you full solutions. hope this helps.

Hi CoffeeCat,
Can you help double check your answer for question 3?
Since for the same distance, it's represented shorter at 5cm than 7.5cm on X vs Y map. So isn't the ration the other way round 5/7.5=2/3?
Hope you wouldn't mind to help clarify and to point out where my mistake in reasoning is.

Thanks,
Xiao Hu.

[FrekiWang]

Xiao Hu:

CoffeeCat:

[quote=\"midnightspark\"]Hi,


Just asking some sec 2 maths questions, please help


1)
A rectangle of sides x cm and y cm has an area of 72 cm2. Another rectangle of sides (x+1.5) and (y-4)cm has the same area. Find the values of x and y.

2)
When 5 is added to both the numerator and denominator of a fraction, the result becomes 1/2. When 1 is subtracted from both the numerator and the denominator, the fraction becomes 1/5. Find the fraction.

3)
The scale of map X is 1: x and the scale of map Y is 1:y. If the same distance is represented as 5cm on map X and 7.5cm on map Y, calculate the ratio x:y.

Thanks.

For qns 2, use algebra.
let the original fraction be x/y.
(x+5)/(y+5) = 1/2
cross multiplying, 2x + 10 = y+ 5
2x + 5 = y
(x-1)/ (y-1) = 1/5
5x - 5 = y - 1
......

For qns 1
xy = 72
(x+1.5)(y-4) = 72
let y= (72/x) and substitute . You will get a quadratic equation after multiplying the whole equation by x.

For qns 3,
5x = 7.5y
x/y = 7.5/5 = ...

hmmm too busy to give you full solutions. hope this helps.

Hi CoffeeCat,
Can you help double check your answer for question 3?
Since for the same distance, it's represented shorter at 5cm than 7.5cm on X vs Y map. So isn't the ration the other way round 5/7.5=2/3?
Hope you wouldn't mind to help clarify and to point out where my mistake in reasoning is.

Thanks,
Xiao Hu.[/quote]This is the ration:

Map X has a scale of 1:x, this implies 5cm on map X represents an actual distance of 5x cm.
Similarly, 7.5cm on map Y represents an actual distance of 7.5y cm.

Now you are given they represent the same distance, which implies 5x = 7.5y. Do a reverse of cross-mutiplication we have x/y=7.5/5=3/2

Comment on your ration:

For the same actual distance, if you have a map with a very large scale 1:10000000, the distance measured on the map will be very short (i.e. 10km becomes 1mm); Similarly, if you have a map with a very small scale, 1:10, the distance measured on the map will be very long (i.e. 10km becomes 1km). Therefore, for the same actual distance. the longer the distance shown on the map, the smaller the scale of the map is. So x>y since 5cm<7.5cm in this question.

[Xiao Hu]

Hi FrekiWang,

Yes, you are right and the solution was correct. I was not clear about the map scale myself, how the scale was used, that it’s 1 on the map scaled to longer length on actual land.

Thanks for pointing out.
Xiao Hu

[listener]

Hi, i need help in a probability question.


Gabriel takes a bus or a cab to go to school. On a rainy day, the probability that Gabriel takes a bus to school is 1/6 and on a non-rainy day the probability that he takes a cab is 1/12.
Assuming Gabriel’s choice of transport is independent of the weather, find the probability that
a) it will rain when Gabriel goes to school and hence, draw a probability tree for it.
b) Gabriel will take a bus to school on a non-rainy day.

[FrekiWang]

listener:

Hi, i need help in a probability question.


Gabriel takes a bus or a cab to go to school. On a rainy day, the probability that Gabriel takes a bus to school is 1/6 and on a non-rainy day the probability that he takes a cab is 1/12.
Assuming Gabriel's choice of transport is independent of the weather, find the probability that
a) it will rain when Gabriel goes to school and hence, draw a probability tree for it.
b) Gabriel will take a bus to school on a non-rainy day.

Draw a tree and solve it please, I dont want to give any detail as this is somewhat even easier than the textbook example.

[Herbie]

if 600= 22235*5. Find the smallest value of k such tat 600k is a perfect square. Can help to solve it?