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    Q&A - P5 Math

    Scheduled Pinned Locked Moved Primary 5
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    • corneyAmberC Offline
      corneyAmber
      last edited by

      2DMommy:
      Need help with these two questions :


      1) Mr Tan had 75 more apples than oranges. after he had sold 4/5 of the apples and 3/4 of the oranges, he had 285 fruits left.
      a) how many apples did he sell ?
      B) What fraction of the fruits sold were oranges?

      Thank you .
      1. u = number of oranges
      apples = u+75

      u + (u+75) - 4/5(u+75) - 3/4u ->285
      1/4u + 1/5(u+75) -> 285
      1/4u + 1/5u + 15 -> 285
      9/20u -> 270
      u-> 600

      a)number of apples sold = 4/5(600+75) = 540

      b) oranges sold = 3/4(600) = 450
      Total number of fruits = 600+600+75 = 1275
      Fraction of oranges sold = 450/1275 = 18/51

      1 Reply Last reply Reply Quote 0
      • P Offline
        pixiedust
        last edited by

        Superbugs:
        Superbugs:

        The figure below is not drawn to scale. The figure is made up triangles drawn within a rectangle. BY and CX are straight lines. The area if rectangle ABCD is 480cm2 and the area of triangle BXZ is 56cm2. Find the total area of the shaded parts.


        Sorry that I do not know how to incorporate the diagram herein! Pls help. Tks

        Anyone can help on this?

        Superbugs, very difficult to visualise the diagram like this. If you can't upload a .jpg file - is this a past year top-school paper ? Look for the paper here and provide a link to the paper and the question number, or tell us the school,year,level,question.
        http://www.orlesson.org/orp/

        1 Reply Last reply Reply Quote 0
        • V Offline
          Vanilla Cake
          last edited by

          Superbugs:
          The figure below is not drawn to scale. The figure is made up triangles drawn within a rectangle. BY and CX are straight lines. The area if rectangle ABCD is 480cm2 and the area of triangle BXZ is 56cm2. Find the total area of the shaded parts.

          Sorry that I do not know how to incorporate the diagram herein! Pls help. Tks
          Superbugs:
          Anyone can help on this?
          pixiedust:
          Superbugs, very difficult to visualise the diagram like this. If you can't upload a .jpg file - is this a past year top-school paper ? Look for the paper here and provide a link to the paper and the question number, or tell us the school,year,level,question.
          http://www.orlesson.org/orp/EnglishExam.html
          Hi pixiedust,
          The question posted by \"Superbugs\" was from Rosyth School 2010 P5 SA2 Maths Paper 2 Q6 - 3 marks set on 27 October 2010.

          http://i53.tinypic.com/6nzerk.png\">

          VC's mum

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          • MathIzzzFunM Offline
            MathIzzzFun
            last edited by

            2DMommy:
            Need help with these two questions :


            2) Alice gave $480 to her father and 25% of the remaining Salary to her mother. After giving 43% of her salary to her parents, she saved 15% of her salary.
            a) How much did she spend?
            b) How much did she give to her mother ?

            Thank you .
            Hi

            for q2..

            http://i53.tinypic.com/1jt4bl.jpg\">

            cheers.

            1 Reply Last reply Reply Quote 0
            • P Offline
              pixiedust
              last edited by

              Thanks VC mum.


              Unfortunately, I couldn't crack the problem too.
              Anyone can help Superbug and me ?

              Source : Rosyth School 2010 P5 SA2 Maths Paper 2 Q6
              http://i53.tinypic.com/6nzerk.png\">

              In addition, I am struggling with this too :
              Source : Tao Nan 2010 P5 SA2 Paper 2 Q11
              http://i1197.photobucket.com/albums/aa424/pixie_dust8/m2.jpg\">

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              • K Offline
                ksme
                last edited by

                Pixiedust and Superbug,


                Rosyth School 2010 P5 SA2 Maths Paper 2 Q6

                Area of triangles ABX + BXY+YDC = 1/2 of Area of rectangle ABCD = 240
                Since area of BXZ = 56, the shaded area is 240-56= 184 cm2

                Tao Nan 2010 P5 SA2 Paper 2 Q11

                If perimeter is 56cm, BC = (56-18-18)/2=10cm
                Area of ABX = 1/2 (18*10)= 90 cm2
                Area of BXY = 90-42=48cm2.

                Hope the above helps.

                1 Reply Last reply Reply Quote 0
                • L Offline
                  leelk
                  last edited by

                  Question (1)

                  Hanis had $960 less than Lina. After Hanis gave $2400 to Lina, Lina had 3 times as much as Hanis.
                  a) How much did Lina have in the end?
                  b) How much did Hanis have at first?

                  Question (2)
                  Mr A and Ms B went shopping with a total of $300 and each bought some items. The amount Mr A spent is three times the amount he has left. The amount Ms B spent is twice the amount she has left. Given that the two friends have a total of $90 left, how much did each of them have at first?

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                  • MathIzzzFunM Offline
                    MathIzzzFun
                    last edited by

                    leelk:
                    Question (1)

                    Hanis had $960 less than Lina. After Hanis gave $2400 to Lina, Lina had 3 times as much as Hanis.
                    a) How much did Lina have in the end?
                    b) How much did Hanis have at first?

                    Question (2)
                    Mr A and Ms B went shopping with a total of $300 and each bought some items. The amount Mr A spent is three times the amount he has left. The amount Ms B spent is twice the amount she has left. Given that the two friends have a total of $90 left, how much did each of them have at first?
                    Hi
                    Both questions can be solved using MD too.

                    q1.
                    Initially, Hanis = 1u, Lisa = 1u + 960

                    After Hanis gave $2400 to Lisa,
                    Hanis : Lisa
                    = 1u - $2400 : 1u + $960 + $2400
                    = 1u - $2400 : 1u + $3360
                    = 1 : 3

                    Cross-multiply-

                    3u - $7200 = 1u + $3360
                    2u = $10560
                    1u = $5280

                    In the end, Lisa had 1u + $3360 = $5280 + $3360 = $8640

                    At first, Hanis had 1u = $ 5280

                    q2.

                    Mrs A = * * * *
                    Mrs B = @ @ @ (\"amount spent\" in red)

                    * + @ = $ 90
                    * * * + @ @ = $ 300 - $90 = $210

                    So, * = $ 210 - 2 x $90 = $30
                    @ = $90 - $30 = $60

                    At first,
                    Mrs A had 4 x $30 = $ 120
                    Mrs B had 3 x $ 60 = $ 180

                    cheers.

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                    • T Offline
                      tinasen
                      last edited by

                      Can someone help with a solution (Model methos) to solve this question pls.

                      Weichong and Rama collect stamps. If Rama gives Weichong 15 stamps, he will have the same number of stamps as Weichong. If Weichong gives 15 stamps, he will have 1/2 as many stamps as Rama. How many stamps does each boy have?

                      Answer is be Rama 105 and WeiChong 75
                      Here is what I attempted and came out with wrong answer
                      After R gives 15 to W,
                      Case 1: R -> []15
                      W -> []15

                      After W gives 15 to R,
                      Case 2: R-> [][]
                      W->[]
                      Substituting in case 2, 1U –> 15+15 -> 30
                      W –> 30+15 = 45
                      R –> 60-15 = 45

                      1 Reply Last reply Reply Quote 0
                      • MathIzzzFunM Offline
                        MathIzzzFun
                        last edited by

                        tinasen:
                        Can someone help with a solution (Model methos) to solve this question pls.

                        Weichong and Rama collect stamps. If Rama gives Weichong 15 stamps, he will have the same number of stamps as Weichong. If Weichong gives 15 stamps, he will have 1/2 as many stamps as Rama. How many stamps does each boy have?

                        Answer is be Rama 105 and WeiChong 75
                        Here is what I attempted and came out with wrong answer
                        After R gives 15 to W,
                        Case 1: R -> []15
                        W -> []15

                        After W gives 15 to R,
                        Case 2: R-> [][]
                        W->[]
                        Substituting in case 2, 1U --> 15+15 -> 30
                        W --> 30+15 = 45
                        R --> 60-15 = 45
                        Hi

                        http://i55.tinypic.com/vfeo5.jpg\">

                        cheers

                        1 Reply Last reply Reply Quote 0

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